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Questions and Answers
In a scenario where two heterozygous individuals (Aa) are crossed, what proportion of the offspring would be expected to display the recessive phenotype, assuming simple Mendelian inheritance?
In a scenario where two heterozygous individuals (Aa) are crossed, what proportion of the offspring would be expected to display the recessive phenotype, assuming simple Mendelian inheritance?
- 75%
- 25% (correct)
- 50%
- 100%
A plant species has three alleles for flower color: $R$ (red), $r$ (white), and $r'$ (pink). $R$ is dominant to both $r$ and $r'$, while $r$ and $r'$ exhibit codominance. What would be the phenotype of a plant with the genotype $rr'$?
A plant species has three alleles for flower color: $R$ (red), $r$ (white), and $r'$ (pink). $R$ is dominant to both $r$ and $r'$, while $r$ and $r'$ exhibit codominance. What would be the phenotype of a plant with the genotype $rr'$?
- Red
- White-pink striped (correct)
- White
- Pink
A test cross is performed on a pea plant that exhibits a dominant trait, but its genotype is unknown. The test cross involves crossing this plant with a plant that is homozygous recessive for the same trait. If all offspring from the test cross exhibit the dominant trait, what can be inferred about the genotype of the original plant?
A test cross is performed on a pea plant that exhibits a dominant trait, but its genotype is unknown. The test cross involves crossing this plant with a plant that is homozygous recessive for the same trait. If all offspring from the test cross exhibit the dominant trait, what can be inferred about the genotype of the original plant?
- The original plant is homozygous dominant (correct)
- The original plant is heterozygous
- The original plant could be either homozygous dominant or heterozygous
- The original plant's genotype cannot be determined from this information
Flashcards
Genotype
Genotype
The genetic makeup of an organism.
Phenotype
Phenotype
The physical expression of a trait.
Homozygous
Homozygous
Having two identical alleles for a particular gene.
Study Notes
Introduction to Electric Charges and Fields
- Explores electric force as a non-contact force similar to gravitational force.
- Focuses on electric charge and its related phenomena.
Electric Charge
What is Electric Charge?
- Electric charge is acquired when two different materials are rubbed together, causing attraction.
- It is a property of matter causing force exertion in an electromagnetic field.
- There are two types of charges: positive and negative with like charges repelling and unlike charges attracting.
- The SI unit for electric charge is the coulomb (C).
- Electric charge is quantized, existing in discrete packets that are integer multiples of the elementary charge (e).
- e = $1.602192 \times 10^{-19} C$
- An electron has a charge of -e, while a proton has a charge of +e.
- Charge is conserved; the total charge within an isolated system remains constant.
Conductors and Insulators
- Materials are classified by their ability to conduct electricity.
- Conductors allow electric charge to move freely (e.g., metals, human body).
- Insulators restrict the movement of electric charge (e.g., glass, plastic, wood).
Charging by Induction
- Induction is charging an object without direct contact.
- A charged object is brought near a neutral object, causing charge redistribution.
- Grounding the neutral object allows charge flow between the object and the ground.
- Removing the ground and then the charged object leaves the neutral object charged.
Basic Properties of Electric Charge
Additivity of Charges
- The total charge of a system is the algebraic sum of individual charges.
- If charges are $q_1, q_2, q_3,..., q_n$, the total charge Q is: $Q = q_1 + q_2 + q_3 +... + q_n$.
Charge is Conserved
- The total charge in an isolated system remains constant.
- Charge is neither created nor destroyed, only transferred.
Quantization of Charge
- Electric charge is an integral multiple of the elementary charge e.
- $q = ne$, where n is an integer (0, ±1, ±2, ±3,...).
Coulomb's Law
Coulomb's Law
- The force between two point charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
- $F = k \frac{|q_1 q_2|}{r^2}$
- Where:
- F is the electrostatic force
- $q_1$ and $q_2$ are the magnitudes of the charges
- r is the distance between the charges
- k is Coulomb's constant
- $k = \frac{1}{4 \pi \epsilon_0} = 8.9875 \times 10^9 Nm^2C^{-2} \approx 9 \times 10^9 Nm^2C^{-2}$
- $\epsilon_0$ is the permittivity of free space, equalling $8.854 \times 10^{-12} C^2N^{-1}m^{-2}$.
Vector Form of Coulomb's Law
- The force on charge $q_1$ due to $q_2$ is: $\overrightarrow{F}{12} = k \frac{q_1 q_2}{r^2{12}} \hat{r}_{12}$.
- $\overrightarrow{F}_{12}$ is the force on $q_1$ due to $q_2$.
- $\hat{r}_{12}$ is the unit vector from $q_2$ to $q_1$.
- $r_{12}$ is the distance between $q_1$ and $q_2$.
Forces between Multiple Charges
- The total force on a charge due to multiple charges is the vector sum of individual forces. $\overrightarrow{F}1 = \overrightarrow{F}{12} + \overrightarrow{F}{13} +... + \overrightarrow{F}{1n}$
Electric Field
Electric Field
- An electric field is a region around a charged object where force is exerted on other charges.
- Defined as $\overrightarrow{E} = \frac{\overrightarrow{F}}{q}$, where $\overrightarrow{F}$ is the force on a small positive test charge $q$.
- The SI unit of electric field is N/C or V/m.
Electric Field due to a Point Charge
- Given by $\overrightarrow{E} = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r^2} \hat{r}$, where $\hat{r}$ is the unit vector from the charge to the point of calculation.
Electric Field due to a System of Charges
- The electric field is the vector sum of fields from individual charges.
- $\overrightarrow{E} = \overrightarrow{E}_1 + \overrightarrow{E}_2 +... + \overrightarrow{E}_n$
Electric Field Lines
Electric Field Lines
- Imaginary lines representing the direction and strength of an electric field.
Properties of Electric Field Lines
- Start from positive charges and end at negative charges.
- The number of lines is proportional to the charge magnitude.
- Tangent to a line indicates the electric field direction.
- Field lines never intersect and the density shows field strength.
Electric Flux
Area Vector
- The area vector $\overrightarrow{\Delta S}$ has a magnitude equal to the area and a direction normal to the surface.
Electric Flux
- Measures the number of electric field lines through a surface with $\Delta \phi = \overrightarrow{E} \cdot \overrightarrow{\Delta S} = E \Delta S \cos \theta$.
- $\Delta \phi$ is the electric flux through the surface $\Delta S$.
- $\overrightarrow{E}$ is the electric field.
- $\overrightarrow{\Delta S}$ is the area vector.
- $\theta$ is the angle between $\overrightarrow{E}$ and $\overrightarrow{\Delta S}$.
- For a closed surface, the total electric flux is: $\phi = \oint \overrightarrow{E} \cdot d\overrightarrow{S}$.
Electric Dipole
Electric Dipole
- Pair of equal but opposite charges separated by a small distance $2a$.
- The center of the dipole is the midpoint of the line joining the charges.
Dipole Moment
- $\overrightarrow{p}$ equals $q(2a)$, directed from the negative to positive charge. The SI unit is Coulomb-meter (Cm).
Electric Field of a Dipole
- At a point on the axial line: $E = \frac{1}{4 \pi \epsilon_0} \frac{2pr}{(r^2 - a^2)^2}$. If $r >> a$, then $E \approx \frac{1}{4 \pi \epsilon_0} \frac{2p}{r^3}$.
- At a point on the equatorial line: $E = \frac{1}{4 \pi \epsilon_0} \frac{p}{(r^2 + a^2)^{3/2}}$. If $r >> a$, then $E \approx \frac{1}{4 \pi \epsilon_0} \frac{p}{r^3}$.
Dipole in a Uniform External Field
- Experiences a torque: $\overrightarrow{\tau} = \overrightarrow{p} \times \overrightarrow{E}$ or $\tau = p E \sin \theta$, with $\theta$ as the angle between $\overrightarrow{p}$ and $\overrightarrow{E}$.
- Potential energy $U = - \overrightarrow{p} \cdot \overrightarrow{E}$ or $U = -pE \cos \theta$.
Continuous Charge Distribution
Continuous Charge Distribution
- Distribution of electric charge continuously over a region.
Types of Charge Distribution
- Linear charge density ($\lambda$): Charge per unit length, $\lambda = \frac{dQ}{dl}$.
- Surface charge density ($\sigma$): Charge per unit area, $\sigma = \frac{dQ}{dS}$.
- Volume charge density ($\rho$): Charge per unit volume, $\rho = \frac{dQ}{dV}$.
Electric Field due to a Continuous Charge Distribution
- Given by $\overrightarrow{E} = \frac{1}{4 \pi \epsilon_0} \int \frac{dQ}{r^2} \hat{r}$, where $dQ$ is the charge element and $r$ is the distance to the point of calculation.
Gauss's Law
Gauss's Law
- The total electric flux through a closed surface equals the enclosed charge divided by $\epsilon_0$: $\phi = \oint \overrightarrow{E} \cdot d\overrightarrow{S} = \frac{Q_{encl}}{\epsilon_0}$.
- $\phi$ signifies the electric flux through a surface.
- $\overrightarrow{E}$ stands for the electric field.
- $d\overrightarrow{S}$ is the area vector.
- $Q_{encl}$ is the total enclosed charge.
- $\epsilon_0$ is the permittivity of free space.
Applications of Gauss's Law
- Electric field due to an infinitely long straight wire: $E = \frac{\lambda}{2 \pi \epsilon_0 r}$.
- Electric field due to a uniformly charged infinite plane sheet: $E = \frac{\sigma}{2 \epsilon_0}$.
- Electric field due to a uniformly charged thin spherical shell:
- For $r < R$: $E = 0$.
- For $r \geq R$: $E = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r^2}$.
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