Discrete Mathematics: Ordered and Unordered Partitions

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to Lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

What is a k-selection?

A choice of k elements taken from a set of n elements such that the order does not matter and repetitions are allowed.

What is the formula to calculate the number of k-selections from a set of n elements?

C(k+n−1, k)

What is the number of ways 30 batteries can be distributed among 10 different types?

211915132

How many ways can 30 batteries be distributed if at least 4 are of type A76?

<p>70607460</p> Signup and view all the answers

What is an unordered partition?

<p>A collection of disjoint nonempty subsets whose union forms the original set.</p> Signup and view all the answers

How many ways can 9 toys be divided among 4 children given specific toy allocations?

<p>2520</p> Signup and view all the answers

What is the method for determining the number of unordered partitions?

<p>Count the ordered partitions and divide by the appropriate factor to eliminate order.</p> Signup and view all the answers

How many distinct permutations can be formed from the letters of the word 'BENZENE'?

<p>420</p> Signup and view all the answers

How many different signals can be formed using 4 identical red flags and 2 identical blue flags?

<p>15</p> Signup and view all the answers

What is the number of permutations of the letters in 'ELEVEN'?

<p>120</p> Signup and view all the answers

How many permutations can be formed from the letters of 'BASEBALL'?

<p>5040</p> Signup and view all the answers

Flashcards are hidden until you start studying

Study Notes

K-Selections

  • A k-selection of a set of n elements is a choice of k elements taken from a set of n elements such that the order of elements does not matter and elements can be repeated.
  • k-selections are also called k-combinations with repetition allowed or multisets of size k.
  • The number of k-selections that can be selected from a set of n elements is C(k+n-1, k) or C(k+n−1, k).

Exercises on K-Selections

  • In a camera shop, there are 10 different types of batteries. The number of ways to distribute a total inventory of 30 batteries among the 10 different types is C(30+10-1, 30) = C(39, 30) = 211915132.
  • If one of the types of batteries is A76, the number of ways to distribute a total inventory of 30 batteries among the 10 different types, such that the inventory must include at least four A76 batteries, is C(26+10-1, 26) = C(35, 26) = 70607460.

Ordered and Unordered Partitions

  • An unordered partition of a finite set S is a collection [A1, A2, …, Ak] of disjoint (nonempty) subsets of S (called cells) whose union is S.
  • The partition is ordered if the order of the cells in the list counts.
  • Example: Let S = {1, 2, 3, …, 7}. The collections P1 = [{1,2}, {3,4,5}, {6,7}] and P2 = [{6,7}, {3,4,5}, {1,2}] determine the same partition of S but are distinct ordered partitions.

Theorem on Ordered Partitions

  • Let S contain n elements and let n1, n2, …, nk be positive integers with n1+n2+…+nk = n. Then there exist n! / (n1!n2!n3!…nk!) different ordered partitions of S of the form [A1, A2, …, Ak], where A1 contains n1 elements, A2 contains n2 elements, …, Ak contains nk elements.

Exercises on Ordered Partitions

  • The number of ways to divide 12 students into 3 groups with 4 students in each group so that one group studies English, one History, and one Mathematics is 12! / (4!4!4!) = 34650.
  • The number of ways to divide 12 students into 3 groups with 4 students in each group so that all the groups study Mathematics is 12! / (4!4!4!) / 3! = 1730.

Generalized Permutation or Permutations with Repetitions

  • The number of permutations of n elements of which n1 are alike, n2 are alike, …, nk are alike is n! / (n1!n2!…nk!).
  • This number is often called a multinomial coefficient, and is denoted by the symbol (n; n1, n2, …, nk).

Exercises on Generalized Permutations

  • The number of distinct permutations that can be formed using the letters of the word “BENZENE” is 7! / (3!2!) = 420.
  • The number of different signals that can be formed from four identical red flags and two identical blue flags is 6! / (4!2!) = 15.

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

Related Documents

More Like This

Use Quizgecko on...
Browser
Browser