De Broglie Wavelength Quiz

De Broglie Wavelength

• The de Broglie wavelength describes the wave-like nature of particles, specifically their momentum.
• The de Broglie wavelength is inversely proportional to the momentum of the particle.
• Doubling the kinetic energy of an electron would decrease its de Broglie wavelength by a factor of the square root of 2.
• The de Broglie wavelength of an electron is significantly greater than the de Broglie wavelength of a proton with the same kinetic energy. This is because the electron has a much smaller mass than the proton.
• The de Broglie wavelength of an electron with a kinetic energy of 120 eV can be calculated using the following formula:

λ = h / p = h / √(2mK)

Where: - λ is the de Broglie wavelength - h is Planck's constant (6.63 x 10^-34 Js) - m is the mass of the electron (9.11 x 10^-31 kg) - K is the kinetic energy of the electron (120 eV converted to joules).

This quiz covers the de Broglie wavelength of an electron with a given kinetic energy, its relationship with kinetic energy, and a comparison between the de Broglie wavelength of an electron and a proton. Test your understanding of this fundamental concept in quantum mechanics.