Daniel Carrión: Solving Quadratic Equations of Second Degree

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Questions and Answers

¿Cuáles son los coeficientes de la ecuación cuadrática 3x² - 2x = 4?

True (A)

¿La fórmula para resolver ecuaciones cuadráticas de la forma x² + bx + c = 0 es x = -b/2 ± √(b²-4ac)/2a?

True (A)

¿La ecuación x² + 2x + 8 = 0 se resuelve utilizando la fórmula cuadrática?

True (A)

¿El valor de x1 al resolver la ecuación x² + 2x + 8 = 0 es 4?

<p>True (A)</p> Signup and view all the answers

¿La fórmula cuadrática proporciona solo una solución para una ecuación de segundo grado?

<p>False (B)</p> Signup and view all the answers

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Study Notes

  • Daniel Carrión: speaking about solving quadratic equations of second degree
  • Quadratic equation: form where x appears at least once squared, e.g. x² + 12x + 8 = 0
  • Terms:
    • Coefficient of the quadratic term (x²): a
    • Coefficient of the linear term (x): b
    • Constant term (without x): c
  • Examples:
    • 3x² - 2x = 4: a = 3, b = -2, c = 4
    • 6x² + 3x - 5 = 0: a = 6, b = 3, c = -5
    • x² + 5x + 8 = 0: a = 1, b = 5, c = 8
  • Formula to solve quadratic equations of the form x² + bx + c = 0
    • x = -b/2 ± √(b²-4ac)/2a
  • Solving a quadratic equation involves finding the value of x
  • In the provided example, x² + 2x + 8 = 0 is to be solved.
  • Determining values of a, b, and c: a = 1, b = 2, c = -8
  • Applying the quadratic formula: x = -2 ± √(2²-4(1)(-8)/2(1))
  • Solving for x1: x = -2 + √(16+32) = 4
  • Solving for x2: x = -2 - √(16+32) = -10
  • The quadratic formula provides two solutions, one for the positive sign and the other for the negative sign.
  • In the given example, x = 4 and x = -10 are the solutions.

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