Cuprous Iodide Test

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to Lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

What type of chemical are iodides?

Active reducing agents

What is the chemical formula for cuprous iodide?

Cu₂I₂

What is the chemical formula for the iodide that is oxidized into free iodine?

I₂

What is the color of the precipitate formed in the cuprous iodide test?

<p>White</p> Signup and view all the answers

What is the color of the free iodine?

<p>Brown</p> Signup and view all the answers

Flashcards

Oxidation

A chemical reaction where a substance loses electrons, becoming more positive.

Reduction

A chemical reaction where a substance gains electrons, becoming more negative.

Iodides as Reducing Agents

Iodides are chemicals that have the ability to donate electrons, making them capable of reducing other substances.

Redox Reaction

A reaction where a substance reacts with another substance and loses electrons, while the other gains electrons.

Signup and view all the flashcards

Oxidizing Agent

A substance that causes another substance to lose electrons, becoming oxidized.

Signup and view all the flashcards

Reducing Agent

A substance that causes another substance to gain electrons, becoming reduced.

Signup and view all the flashcards

Precipitate

A solid material that forms from a solution during a chemical reaction.

Signup and view all the flashcards

Cuprous Iodide (Cu₂I₂)

The white precipitate formed when iodides react with copper sulfate.

Signup and view all the flashcards

Brown solution

The brown color observed in the solution during the cuprous iodide test, caused by the formation of iodine.

Signup and view all the flashcards

Cuprous Iodide Test

The chemical reaction where iodides react with copper sulfate to form cuprous iodide and iodine.

Signup and view all the flashcards

Study Notes

Cuprous Iodide Test

  • Iodides are reducing agents that react with CuSO₄
  • This reaction forms a white precipitate of cuprous iodide (Cu₂I₂).
  • The iodide is oxidized to free iodine (I₂).
  • The white precipitate appears as a brown solution due to the formed iodine.
  • The overall reaction is: 2CuSO₄ + 4NaI → Cu₂I₂ + I₂ + 2Na₂SO₄
  • The white precipitate is Cu₂I₂ .
  • The brown color is from the iodine (I₂).

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

More Like This

اختبار اليوديد النحاسي
10 questions

اختبار اليوديد النحاسي

EnticingAntigorite1106 avatar
EnticingAntigorite1106
Use Quizgecko on...
Browser
Open
Browser
Browser