Cuprous Iodide Test
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Questions and Answers

What type of chemical are iodides?

Active reducing agents

What is the chemical formula for cuprous iodide?

Cu₂I₂

What is the chemical formula for the iodide that is oxidized into free iodine?

I₂

What is the color of the precipitate formed in the cuprous iodide test?

<p>White</p> Signup and view all the answers

What is the color of the free iodine?

<p>Brown</p> Signup and view all the answers

Study Notes

Cuprous Iodide Test

  • Iodides are reducing agents that react with CuSO₄
  • This reaction forms a white precipitate of cuprous iodide (Cu₂I₂).
  • The iodide is oxidized to free iodine (I₂).
  • The white precipitate appears as a brown solution due to the formed iodine.
  • The overall reaction is: 2CuSO₄ + 4NaI → Cu₂I₂ + I₂ + 2Na₂SO₄
  • The white precipitate is Cu₂I₂ .
  • The brown color is from the iodine (I₂).

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Description

Explore the chemistry behind the Cuprous Iodide Test, where iodides act as reducing agents and react with CuSO₄. This quiz delves into the formation of the white precipitate of cuprous iodide and the oxidation process that leads to free iodine. Test your understanding of the chemical reactions involved!

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