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Coulomb's Law and Electric Field Quiz

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Questions and Answers

According to Coulomb's Law, what is the formula for the force between two charges Q1 and Q2?

$F = \frac{Q1 \cdot Q2}{4\pi\epsilon_0 R_{12}^2}$ (correct)
$F = \frac{Q1 + Q2}{R_{12}}$
$F = \frac{Q1 \cdot Q2}{R_{12}}$
$F = \frac{Q1 + Q2}{4\pi\epsilon_0 R_{12}^2}$

What does the vector a12 represent in Coulomb's Law?

The magnitude of the force between Q1 and Q2
The position vector of Q2 relative to Q1
The displacement vector of Q2 relative to Q1
The unit vector in the direction of the line segment from Q1 to Q2 (correct)

In the given example, what is the value of R12?

$R12 = 1\hat{a}_x + 2\hat{a}_y + 3\hat{a}_z$
$R12 = 1\hat{a}_x - 2\hat{a}_y + 2\hat{a}_z$
$R12 = 2\hat{a}_x - 2\hat{a}_y + 2\hat{a}_z$
$R12 = 2\hat{a}_x + 0\hat{a}_y + 5\hat{a}_z$ (correct)

What is the formula for the electric field intensity at a point due to a charge Q?

<p>$E = \frac{Q}{4\pi\epsilon_0 R^2}$ (A)</p> Signup and view all the answers

What is the relationship between the force exerted on Q2 by Q1 and the force exerted on Q1 by Q2?

<p>The forces have the same magnitude but opposite directions (A)</p> Signup and view all the answers

Flashcards

Coulomb's Law formula

The formula for the force between two charges Q1 and Q2 is F = (Q1 * Q2) / (4πε₀R₁₂²).

Unit vector a12

The vector a12 represents the direction from charge Q1 to Q2.

Value of R12

R12 is given as R12 = 2aₓ + 0aᵧ + 5a𝓏.

Electric field intensity formula

The electric field intensity E at a point due to a charge Q is E = Q / (4πε₀R²).

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Forces on charges Q1 and Q2

The forces on Q2 by Q1 and on Q1 by Q2 have the same magnitude but opposite directions.