Code Functionality Analysis Quiz

Study Notes

Code Functionality Analysis

The code iterates through a string txt1, comparing each character (x) with all other characters (y).
If a matching character is found at a different index (i != j), the character at index j is deleted from txt1.
The code uses nested while loops (a and b).
Deleting elements in a loop, in this case modifies the string, leading to index mismatches (i).
Counter measures are added to handle the problem of removing elements from a string while iterating over it.
The i and j counters are updated or adjusted when characters are deleted.

Crucial Actions Inside Inner Loop

The if (i != j && y == x) condition is crucial. It ensures that a character is compared only with different characters within the string itself.
The txt1.deleteCharAt(j) operation removes the matching character at index j.

Potential Insert Statements at Line 1 (and their impact)

continue b;: This statement will skip to the next iteration of the inner loop (b) without removing or moving the current character. This is a valid option since the code adjusts the iterators afterward. A character that's matched is not deleted and the loop continues.
j--; i--; break a;: This combination adjusts the inner and outer loop iterators. This statement, though, works by effectively backing up to the previous index.

Summary

The code effectively removes all instances of a character in the input string if they appear more than once.
continue b; is better, because it avoids removing chars that haven't been compared.
j--; i--; break a; works, but isn't as efficient.

Description

Test your understanding of the code functionality that iterates through a string and removes duplicate characters. This quiz highlights the importance of managing index mismatches when modifying a string during iteration. Dive into the crucial operations and conditions that help maintain accurate character comparisons.