Class 9 Maths Quiz

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Questions and Answers

What is the equation of the circle with center at $(-2, 3)$ and radius $5$?

  • $(x + 2)^2 + (y - 3)^2 = 5$
  • $(x - 2)^2 + (y + 3)^2 = 5$
  • $(x - 2)^2 + (y + 3)^2 = 25$ (correct)
  • $(x + 2)^2 + (y - 3)^2 = 25$

In the equation $3x - 4y = 12$, what is the slope of the line?

  • $-\frac{3}{4}$
  • $\frac{3}{4}$ (correct)
  • $\frac{4}{3}$
  • $-\frac{4}{3}$

What are the solutions to the equation $2x^2 - 5x + 2 = 0$?

  • $x = \frac{1}{2}, \frac{2}{5}$
  • $x = \frac{1}{2}, 2$ (correct)
  • $x = -\frac{1}{2}, -2$
  • $x = 1, 2$

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Study Notes

Circle Equation

  • The equation of a circle with center (a, b) and radius r is (x - a)^2 + (y - b)^2 = r^2
  • The equation of the circle with center at (-2, 3) and radius 5 is (x + 2)^2 + (y - 3)^2 = 5^2
  • The equation of the circle with center at (-2, 3) and radius 5 is (x + 2)^2 + (y - 3)^2 = 25

Slope of a Line

  • The equation 3x - 4y = 12 is a linear equation in standard form
  • The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept
  • To find the slope of the line, rewrite the equation in slope-intercept form: 4y = 3x - 12
  • Divide both sides by 4: y = (3/4)x - 3
  • The slope of the line is 3/4

Quadratic Equations

  • The equation 2x^2 - 5x + 2 = 0 is a quadratic equation in standard form
  • The quadratic formula is x = (-b ± √(b^2 - 4ac)) / 2a, where a, b, and c are the coefficients of the equation
  • In the equation 2x^2 - 5x + 2 = 0, a = 2, b = -5, and c = 2
  • Apply the quadratic formula: x = (5 ± √((-5)^2 - 4(2)(2))) / 2(2)
  • Simplify the expression: x = (5 ± √(25 - 16)) / 4
  • Simplify the expression: x = (5 ± √9) / 4
  • Simplify the expression: x = (5 ± 3) / 4
  • The solutions to the equation are x = (5 + 3) / 4 = 2 and x = (5 - 3) / 4 = 1/2

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