Podcast
Questions and Answers
What is the equation of the circle with center at $(-2, 3)$ and radius $5$?
What is the equation of the circle with center at $(-2, 3)$ and radius $5$?
In the equation $3x - 4y = 12$, what is the slope of the line?
In the equation $3x - 4y = 12$, what is the slope of the line?
What are the solutions to the equation $2x^2 - 5x + 2 = 0$?
What are the solutions to the equation $2x^2 - 5x + 2 = 0$?
Study Notes
Circle Equation
- The equation of a circle with center (a, b) and radius r is (x - a)^2 + (y - b)^2 = r^2
- The equation of the circle with center at (-2, 3) and radius 5 is (x + 2)^2 + (y - 3)^2 = 5^2
- The equation of the circle with center at (-2, 3) and radius 5 is (x + 2)^2 + (y - 3)^2 = 25
Slope of a Line
- The equation 3x - 4y = 12 is a linear equation in standard form
- The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept
- To find the slope of the line, rewrite the equation in slope-intercept form: 4y = 3x - 12
- Divide both sides by 4: y = (3/4)x - 3
- The slope of the line is 3/4
Quadratic Equations
- The equation 2x^2 - 5x + 2 = 0 is a quadratic equation in standard form
- The quadratic formula is x = (-b ± √(b^2 - 4ac)) / 2a, where a, b, and c are the coefficients of the equation
- In the equation 2x^2 - 5x + 2 = 0, a = 2, b = -5, and c = 2
- Apply the quadratic formula: x = (5 ± √((-5)^2 - 4(2)(2))) / 2(2)
- Simplify the expression: x = (5 ± √(25 - 16)) / 4
- Simplify the expression: x = (5 ± √9) / 4
- Simplify the expression: x = (5 ± 3) / 4
- The solutions to the equation are x = (5 + 3) / 4 = 2 and x = (5 - 3) / 4 = 1/2
Studying That Suits You
Use AI to generate personalized quizzes and flashcards to suit your learning preferences.
Description
Test your understanding of Class 9 NCERT Maths topics including circles, linear equations in two variables, and coordinate geometry with this question paper. Evaluate your knowledge and practice for exams with a variety of problems covering these key concepts.