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Questions and Answers
What is the equation obtained by applying KVL for loop ABEFA?
What is the equation obtained by multiplying equation (1) by 2 and equation (2) by 3?
What is the value of I2 in amperes?
What is the SI unit of electric work?
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What is the method used to analyze the given circuit?
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What is the rate at which electrical energy is transferred by an electric circuit?
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What is the use of Cramer's Rule in circuit analysis?
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What is the SI unit of power?
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What is the purpose of applying KVL for loop BCDEB?
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What is the formula to calculate the resistance of a coil?
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What is the formula to calculate the current in a circuit?
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What is the formula to calculate the power absorbed by a coil?
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What is the total length of the coil?
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What is the resistance of the coil?
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What is the value of I1 when using Cramer's Rule?
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What is the value of total current through the 10 ohm resistor?
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What is the value of VB in the given circuit?
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What is the value of ∆ in Cramer's Rule?
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What is the value of I2 when using Cramer's Rule?
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What is the application of Node Analysis in this circuit?
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What is the value of I when using Mesh Analysis?
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What is the value of ∆1 in Cramer's Rule?
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What is the application of Cramer's Rule in this circuit?
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What is the value of I1 + I2?
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Study Notes
KVL and Circuit Analysis
- Applying Kirchhoff's Voltage Law (KVL) to loop ABEFA yields an equation describing voltage drops around the loop.
- Simplify the equation: -15I1 + 10I2 = -20
- Apply KVL to loop BCDEB: -2I2 + 10 - 10(I2 - I1) = 0
- Simplify the equation: 10I1 - 12I2 = -10
- Solve for I2 by multiplying equation (1) by 2 and equation (2) by 3, and then adding them: I2 = 4.375 Amp
- Solve for I1 by substituting I2 in equation (1): I1 = 4.25 Amp
Electric Work and Power
- Electric work: the work done per unit of charge
- SI unit of electric work: Joule
- Electric power: the rate at which electrical energy is transferred
- SI unit of electric power: Watt (one Joule per second)
Coil Resistance and Power
- Calculate the total length of the coil: ltotal = 160000 cm = 1600 m
- Calculate the resistance of the coil: R = 40 Ω
- Calculate the current: I = 2.75 Amp
- Calculate the power absorbed by the coil: P = 302.5 Watt
Equivalent Resistance in Parallel Connection
- Derive an expression for equivalent resistance: R_equivalent = (R1*R2)/(R1+R2)
- Calculate the total current through the 10 ohm resistor: I = I1 - I2 = -0.125 Amp
Node Analysis
- Apply KVL at node B: I1 + I2 + I3 = 0
- Solve for VB: VB = -1.25 V
- Calculate the total current through the 10 ohm resistor: I = VB/10 = -0.125 Amp
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Description
Solve the circuit analysis problem involving currents and resistors.