24 Questions
What is the equation obtained by applying KVL for loop ABEFA?
-5I1 - 20 - 10(I1 - I2) + 40 = 0
What is the equation obtained by multiplying equation (1) by 2 and equation (2) by 3?
-30I1 + 20I2 = -40, 30I1 - 36I2 = -30
What is the value of I2 in amperes?
I2 = 4.375 Amp
What is the SI unit of electric work?
Joule
What is the method used to analyze the given circuit?
Mesh Analysis
What is the rate at which electrical energy is transferred by an electric circuit?
Power
What is the use of Cramer's Rule in circuit analysis?
To solve a system of linear equations
What is the SI unit of power?
Watt
What is the purpose of applying KVL for loop BCDEB?
To write another equation to solve for the currents
What is the formula to calculate the resistance of a coil?
R = ρl / A
What is the formula to calculate the current in a circuit?
I = V / R
What is the formula to calculate the power absorbed by a coil?
P = V × I
What is the total length of the coil?
160000 cm
What is the resistance of the coil?
40 Ω
What is the value of I1 when using Cramer's Rule?
4.25 Amp
What is the value of total current through the 10 ohm resistor?
-0.125 Amp
What is the value of VB in the given circuit?
-1.25V
What is the value of ∆ in Cramer's Rule?
80
What is the value of I2 when using Cramer's Rule?
4.375 Amp
What is the application of Node Analysis in this circuit?
To find the voltage at a node
What is the value of I when using Mesh Analysis?
-0.125 Amp
What is the value of ∆1 in Cramer's Rule?
340
What is the application of Cramer's Rule in this circuit?
To solve systems of linear equations
What is the value of I1 + I2?
8.625 Amp
Study Notes
KVL and Circuit Analysis
- Applying Kirchhoff's Voltage Law (KVL) to loop ABEFA yields an equation describing voltage drops around the loop.
- Simplify the equation: -15I1 + 10I2 = -20
- Apply KVL to loop BCDEB: -2I2 + 10 - 10(I2 - I1) = 0
- Simplify the equation: 10I1 - 12I2 = -10
- Solve for I2 by multiplying equation (1) by 2 and equation (2) by 3, and then adding them: I2 = 4.375 Amp
- Solve for I1 by substituting I2 in equation (1): I1 = 4.25 Amp
Electric Work and Power
- Electric work: the work done per unit of charge
- SI unit of electric work: Joule
- Electric power: the rate at which electrical energy is transferred
- SI unit of electric power: Watt (one Joule per second)
Coil Resistance and Power
- Calculate the total length of the coil: ltotal = 160000 cm = 1600 m
- Calculate the resistance of the coil: R = 40 Ω
- Calculate the current: I = 2.75 Amp
- Calculate the power absorbed by the coil: P = 302.5 Watt
Equivalent Resistance in Parallel Connection
- Derive an expression for equivalent resistance: R_equivalent = (R1*R2)/(R1+R2)
- Calculate the total current through the 10 ohm resistor: I = I1 - I2 = -0.125 Amp
Node Analysis
- Apply KVL at node B: I1 + I2 + I3 = 0
- Solve for VB: VB = -1.25 V
- Calculate the total current through the 10 ohm resistor: I = VB/10 = -0.125 Amp
Solve the circuit analysis problem involving currents and resistors.
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