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Questions and Answers
A researcher wants to determine if the distribution of M&M colors in a bag matches the distribution claimed by the manufacturer. Which statistical test is most appropriate?
A researcher wants to determine if the distribution of M&M colors in a bag matches the distribution claimed by the manufacturer. Which statistical test is most appropriate?
- Paired samples t-test
- Chi-Square goodness-of-fit test (correct)
- Chi-Square test of independence
- Independent samples t-test
In a Chi-Square goodness-of-fit test, what does the null hypothesis typically state?
In a Chi-Square goodness-of-fit test, what does the null hypothesis typically state?
- There is a significant association between the observed and expected frequencies.
- The observed frequencies are significantly different from each other.
- The observed frequencies do not follow the specified distribution.
- The observed frequencies follow the specified distribution. (correct)
A company claims its product line consists of 40% Type X, 40% Type Y, and 20% Type Z. To test this claim with sample data, what is the first step?
A company claims its product line consists of 40% Type X, 40% Type Y, and 20% Type Z. To test this claim with sample data, what is the first step?
- Collect sample data on the number of products of each type. (correct)
- Determine the critical value for the test at a chosen alpha level.
- Compare the claimed proportions to a standard normal distribution.
- Calculate the Chi-Square test statistic directly.
Which condition must be met to ensure the valid use of the Chi-Square goodness-of-fit test?
Which condition must be met to ensure the valid use of the Chi-Square goodness-of-fit test?
Why are expected frequencies used in the Chi-Square test?
Why are expected frequencies used in the Chi-Square test?
What does a very large Chi-Square test statistic suggest?
What does a very large Chi-Square test statistic suggest?
How is the degrees of freedom (df) calculated for a goodness-of-fit test with five categories?
How is the degrees of freedom (df) calculated for a goodness-of-fit test with five categories?
What does a small p-value (e.g., p < 0.05) indicate in a goodness-of-fit test?
What does a small p-value (e.g., p < 0.05) indicate in a goodness-of-fit test?
Why can the Chi-Square statistic never be negative?
Why can the Chi-Square statistic never be negative?
When calculating expected frequencies, why is it important to use proportions rather than percentages?
When calculating expected frequencies, why is it important to use proportions rather than percentages?
What is the potential impact of a very large sample size on a Chi-Square test?
What is the potential impact of a very large sample size on a Chi-Square test?
In a Chi-Square test, a p-value of 0.90 is obtained. What is the correct interpretation?
In a Chi-Square test, a p-value of 0.90 is obtained. What is the correct interpretation?
Why is the Chi-Square test considered a non-parametric test?
Why is the Chi-Square test considered a non-parametric test?
In which scenario would a goodness-of-fit test be LEAST appropriate?
In which scenario would a goodness-of-fit test be LEAST appropriate?
What should you do if some expected frequencies are below 5 in a Chi-Square test?
What should you do if some expected frequencies are below 5 in a Chi-Square test?
What is the primary purpose of the Chi-Square test of independence?
What is the primary purpose of the Chi-Square test of independence?
In a Chi-Square test of independence, what does the null hypothesis state?
In a Chi-Square test of independence, what does the null hypothesis state?
In a Chi-Square test of independence with a contingency table of size 3x4, how are the expected frequencies calculated?
In a Chi-Square test of independence with a contingency table of size 3x4, how are the expected frequencies calculated?
What assumptions must be met for a Chi-Square test of independence to be valid?
What assumptions must be met for a Chi-Square test of independence to be valid?
Which real-world example best illustrates the use of a Chi-Square test of independence?
Which real-world example best illustrates the use of a Chi-Square test of independence?
Flashcards
Chi-Square Goodness-of-Fit Test
Chi-Square Goodness-of-Fit Test
Tests if observed frequency distribution of a single categorical variable differs significantly from an expected distribution.
Null Hypothesis (Chi-Square)
Null Hypothesis (Chi-Square)
The observed frequencies follow the specified distribution.
Alternative Hypothesis (Chi-Square)
Alternative Hypothesis (Chi-Square)
The observed frequencies do not follow the specified distribution.
Conditions for Chi-Square Test
Conditions for Chi-Square Test
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Expected Frequencies Use
Expected Frequencies Use
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Large Chi-Square Statistic Implies
Large Chi-Square Statistic Implies
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Degrees of Freedom (Goodness-of-Fit)
Degrees of Freedom (Goodness-of-Fit)
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Small P-Value Implies
Small P-Value Implies
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Can the Chi-Square Statistic be Negative?
Can the Chi-Square Statistic be Negative?
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Proportions (Not Percentages) Use
Proportions (Not Percentages) Use
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Impact of Large Sample Size
Impact of Large Sample Size
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High P-Value Implies
High P-Value Implies
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Chi-Square Test Non-Parametric
Chi-Square Test Non-Parametric
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Chi-Square Test of Independence Purpose
Chi-Square Test of Independence Purpose
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Null Hypothesis (Independence)
Null Hypothesis (Independence)
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Expected Independence Frequencies
Expected Independence Frequencies
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Chi-Square Independence Example
Chi-Square Independence Example
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Significant Chi-Square Test of Independence Implies
Significant Chi-Square Test of Independence Implies
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Non-Significant Chi-Square Test of Independence Implies
Non-Significant Chi-Square Test of Independence Implies
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Main Difference: Goodness-of-Fit vs. Independence
Main Difference: Goodness-of-Fit vs. Independence
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Study Notes
- The Chi-Square goodness-of-fit test assesses if the observed frequency distribution for a single categorical variable significantly differs from an expected distribution.
- Null hypothesis (H₀) in a Chi-Square goodness-of-fit test states that the observed frequencies follow the specified distribution.
- Alternative hypothesis (H₁) indicates that the observed frequencies do not follow the specified distribution.
Testing a Claim with Sample Data
- Collect sample data on the number of products of each type.
- Calculate the expected frequencies using the proportions claimed.
- Compute the test statistic using the Chi-Square formula.
- Compare the test statistic to the critical value or use the p-value to assess significance.
Conditions for Chi-Square Goodness-of-Fit
- Data must be frequencies (counts).
- Categories must be mutually exclusive.
- The expected frequency in each category should be at least 5.
Expected Frequencies in Chi-Square Test
- Expected frequencies represent what one would expect if the null hypothesis is true.
- They help assess if the observed data significantly deviates from this expectation.
Chi-Square Test Statistic Interpretation
- A large Chi-Square statistic suggests a significant difference between observed and expected frequencies, indicating evidence against the null hypothesis.
Degrees of Freedom
- Degrees of freedom (df) for a goodness-of-fit test = (number of categories) - 1
P-Value Indication
- A small p-value (e.g., p < 0.05) suggests strong evidence against the null hypothesis.
- A small p-value indicates the observed distribution that does not match the expected distribution.
Chi-Square Statistic
- No, it cannot be negative.
- It is always non-negative due to squaring the differences between observed and expected frequencies.
Proportions and Expected Frequencies
- Proportions allow calculating expected frequencies in terms of counts, which are needed for the Chi-Square formula.
Sample Size Impact
- With a large sample size, even minor differences between observed and expected frequencies can become statistically significant.
- Large sample sizes can lead to rejection of the null hypothesis even if the practical difference is minor.
P-Value of 0.87
- A p-value of 0.87 is very high.
- A p-value of 0.87 suggests no evidence to reject the null hypothesis.
- A p-value of 0.87 indicates the observed distribution likely matches the expected distribution.
Nature of Chi-Square Test
- Considered non-parametric because it does not require assumptions about the population distribution.
- Based on categorical data.
Real-Life Applications
- Determining if a die is fair.
- Assessing customer preferences across product categories.
- Analyzing election vote proportions.
Addressing Low Frequencies
- Combine categories if appropriate, or use an exact test or simulation-based alternative.
Chi-Square Test of Independence
- Determines if there is a significant association between two categorical variables.
Hypotheses
- H₀: The two variables are independent.
- H₁: The two variables are not independent (they are associated).
Calculating Expected Frequencies
- (row total * column total) / grand total.
Assumptions
- Observations are independent.
- Categories are mutually exclusive.
- Expected cell counts are at least 5 in most cells.
Real-World Examples
- Testing if smoking status relates to gender.
- Assessing if educational level associates with employment status.
Degrees of Freedom
- df = (number of rows - 1) * (number of columns - 1)
Significant Test of Independence
- Implies a statistically significant association between the two variables.
- Two variables imply they are not independent.
Non-Significant Test of Independence
- Indicates there is no evidence of association between the variables.
- Two variables imply they are likely independent.
Data Type Usage
- Chi-Square test of independence is not used for continuous data.
- Requires categorical data.
- Continuous data must be categorized before applying the test.
Causation
- Does not determine causation.
- Only detects association, not causality.
Data Table
- A contingency table (cross-tabulation) of observed frequencies is used for Chi-Square test of independence.
Observed vs. Expected Frequencies
- If all observed frequencies are close to expected frequencies, it suggests the two variables are likely independent.
- A result of observed frequencies close to expected frequencies could result in failure to reject the null hypothesis.
Distribution
- The sampling distribution of the test statistic under H₀ approximates the Chi-Square distribution.
- The Chi-Square distribution is used to evaluate the test statistic.
Result of x² = 0
- Observed frequencies equal expected frequencies exactly.
- Concludes perfect independence between variables.
Limitations
- Requires large sample sizes.
- Does not measure strength or direction of association.
- Can be misleading with small expected frequencies.
Test Purpose Difference
- Goodness-of-Fit tests whether the distribution of a single categorical variable matches a specific expected distribution.
- Test of Independence tests whether there is an association between two categorical variables.
Hypotheses Difference
- Goodness-of-Fit: H₀ states the observed distribution fits the expected distribution, while H₁ states it does not.
- Test of Independence: H₀ states the two variables are independent, while H₁ states they are associated (dependent).
Frequency Calculation Difference
- Goodness-of-Fit: Expected frequencies are calculated from a known or hypothesized distribution.
- Test of Independence: Expected frequencies are calculated from the product of row and column totals divided by the grand total
Degrees of Freedom Difference
- Goodness-of-Fit: df = (number of categories – 1)
- Test of Independence: df = (number of rows – 1) × (number of columns – 1)
Data Type Difference
- Goodness-of-Fit: One categorical variable with multiple levels.
- Test of Independence: Two categorical variables cross-tabulated into a contingency table.
Situational Appropriate Examples
- Goodness-of-Fit: Testing whether a die is fair (each number 1–6 has equal probability).
- Test of Independence: Testing whether gender is associated with voting preference.
Distribution Table Usage
- Both tests use the Chi-Square distribution table to find critical values.
- The specific value depends on the degrees of freedom, which are calculated differently for each test.
Test Choice for Blood Types
- The Goodness-of-Fit test should be used to assess whether the distribution of blood types in a city matches national proportions.
- Test choice because you are comparing observed frequencies in a single categorical variable (blood type) to known national proportions.
Test Choice for Survey Data
- The Chi-Square Test of Independence should be used to analyze survey data about people's favorite fruit and their region.
- Test choice because you are examining the relationship between two categorical variables.
Conclusion with P-value > 0.05
- In both cases, a p-value greater than 0.05 means we fail to reject the null hypothesis.
- For Goodness-of-Fit: The observed distribution matches the expected.
- For Test of Independence: There is no evidence of association between the variables.
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