Chemistry Quiz on Orbital Interactions and Reactions
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Questions and Answers

Why is NaClO4 a stronger oxidizing agent than NaClO3?

  • It is a gas at room temperature.
  • It has a lower oxidation number of Cl.
  • Cl in NaClO4 has an oxidation number of +7. (correct)
  • NaClO4 contains more oxygen atoms.

An ideal gas can undergo a phase transition.

False (B)

What role does fluorine play in making fluorosulfuric acid (FSO3H) stronger than sulfuric acid?

Fluorine is more electronegative than oxygen, pulling electrons away from the O-H bond and increasing the partial positive charge on hydrogen.

The mutation of glutamic acid to valine in hemoglobin reduces its water solubility due to valine's ___________ side chain.

<p>non-polar</p> Signup and view all the answers

Match the following compounds with their properties:

<p>NaClO4 = Stronger oxidizing agent NaClO3 = Weaker oxidizing agent Fluorosulfuric acid = Stronger acid than sulfuric acid Sickle cell hemoglobin = Proteins stick together due to hydrophobic interactions</p> Signup and view all the answers

What is the yield of lead (II) iodide, PbI2, produced in the reaction?

<p>23.1 g (D)</p> Signup and view all the answers

The concentration of lead (II) ions, Pb2+, in solution at the end of the reaction is greater than 0 M.

<p>False (B)</p> Signup and view all the answers

What is the bond order of the BF molecule according to molecular orbital theory?

<p>3</p> Signup and view all the answers

The concentration of potassium ions, K+, in the solution is _____ M.

<p>0.14</p> Signup and view all the answers

Match the following ions with their concentrations in the resulting solution:

<p>Pb2+ = 0 M K+ = 0.14 M H+ = 0 M</p> Signup and view all the answers

In the reaction between lead (II) nitrate and potassium iodide, which species is the limiting reagent?

<p>KI (A)</p> Signup and view all the answers

The best Lewis structure for BF satisfies all octet rules for both atoms.

<p>True (A)</p> Signup and view all the answers

What indicates a discrepancy between MO theory and experimental results in the bond order of BF?

<p>The bond order of 1.5 suggests not all electrons are involved in bonding as MO theory predicts a bond order of 3.</p> Signup and view all the answers

What role does BeH2 play when reacting with hydrochloric acid in the aqueous phase?

<p>Lewis base (C)</p> Signup and view all the answers

KrH4 is expected to function as an acid due to the electron density concentrated on Kr.

<p>False (B)</p> Signup and view all the answers

Explain why Li3PO4 is highly insoluble despite being a Group 1 metal compound.

<p>The lattice energy of Li3PO4 is too high to permit dissolution in water.</p> Signup and view all the answers

Group 1 metal oxides react with water to produce __________.

<p>hydroxide</p> Signup and view all the answers

Match the following properties or behaviors with the appropriate compound:

<p>BeH2 = Lewis base Li3PO4 = Insoluble in water Group 1 metal oxides = Create a basic solution KrH4 = Electron donor</p> Signup and view all the answers

Which molecular orbital corresponds to the HOMO in KrH4?

<p>σ3* (B)</p> Signup and view all the answers

HOMO in molecular orbital theory represents the highest occupied bonding orbital.

<p>False (B)</p> Signup and view all the answers

What happens to the electron density in KrH4 during a reaction?

<p>Electron density builds up on H, making it an electron donor.</p> Signup and view all the answers

Flashcards

Limiting Reagent in Reaction 2

The reactant that gets completely consumed in a chemical reaction, determining the maximum amount of product that can be formed.

Calculating Moles of KI

Used to determine the amount (in moles) of Potassium Iodide (KI) present, needed for stoichiometric calculations within a reaction.

Calculating Moles of Lead(II) Nitrate

Method to determine the quantity of Pb(NO3)2 moles. Crucial for determining the limiting reactant.

Determining Limiting Reagent

Process to identify which reactant is fully consumed in a chemical reaction first.

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Calculating Product Yield

Method used to calculate product (PbI2) amount formed during reaction, using limiting reagent.

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Concentration of Ions in Solution (After Reaction)

Quantifying concentration of the different ions present in a solution after a chemical reaction.

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MO Diagram (Molecular Orbital Diagram)

Graphical representation of molecular orbitals, depicting electron distribution and energies within molecules.

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Bond Order (MO Theory)

Measure of bond strength in a molecule derived through molecular orbital analysis, equal to half the difference between the bonding and antibonding electrons.

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NaClO4 vs NaClO3 Oxidation Strength

NaClO4 is a stronger oxidizing agent than NaClO3 because the higher oxidation number (+7 vs +5) of chlorine in NaClO4 makes it more strongly attracted to electrons, making it more willing to accept them.

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Ideal Gas Law Limitations at Low Pressure

At low temperatures (e.g., 300 K) and low pressures (below 200 atm), the ideal gas law overestimates the volume of gases. This is because intermolecular forces (IMFs) are significant, compressing the gas more than the ideal gas law predicts.

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Phase Transitions and Ideal Gases

Ideal gases cannot undergo phase transitions (like condensation) because their particles have no attractive forces between them. Attractive forces are necessary to form liquids or solids.

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FSO3H vs H2SO4 Acidity

Fluorosulfuric acid (FSO3H) is a stronger acid than sulfuric acid (H2SO4) because fluorine (F) is more electronegative than oxygen (O). This stronger pull on electrons from the H in the O—H bond leads to a greater partial positive charge on the hydrogen, making it easier to release.

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Sickle Cell Anemia Mutation Effect

Substituting glutamic acid with valine in hemoglobin leads to protein sticking due to the change in polarity and water solubility. Glutamic acid is polar and water-soluble, whereas valine is non-polar and hydrophobic (water-repelling). This change reduces hemoglobin's water solubility and increases attraction between the proteins.

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HOMO

Highest Occupied Molecular Orbital. It's the orbital containing the highest energy electron in a molecule's ground state.

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LUMO

Lowest Unoccupied Molecular Orbital. It's the orbital with the lowest energy that is empty in a molecule's ground state.

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BeH2 as a Lewis Base

BeH2 acts as a Lewis base because its HOMO, heavily concentrated on the hydrogen atoms, donates electrons to form new bonds with an electrophile.

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Orbital Interaction in BeH2 + HCl

The HOMO of BeH2, containing the electron density on the hydrogen atoms, overlaps with the LUMO of HCl (the sigma* antibonding orbital of H-Cl), forming a new bond.

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KrH4 HOMO and LUMO

KrH4's HOMO is the σ3* antibonding orbital, while its LUMO is the σ4* antibonding orbital, indicating its ability to donate electrons.

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KrH4 as a Base

KrH4 acts as a base due to its electron-rich HOMO located on the hydrogen atoms, making it a likely electron donor.

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Li3PO4 Insoluble in Water

Despite other Group 1 metal phosphates generally being soluble, Li3PO4 is insoluble due to its exceptionally high lattice energy, which opposes the forces of solvation.

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Group 1 Metal Oxides Form Basic Solutions

Group 1 metal oxides react with water to form hydroxides, releasing hydroxide ions (OH-) into the solution, increasing its pH and making it basic.

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Study Notes

Orbital Interactions

  • Orbital interactions can be categorized as σ-bonding, σ-antibonding, π-bonding, π-antibonding, or non-bonding.

Aqueous Permanganate and Oxalate Reaction

  • Aqueous permanganate ([MnO₄⁻]) reacts with aqueous oxalate ([C₂O₄]²⁻) under acidic conditions to produce gaseous carbon dioxide (CO₂) and aqueous manganese (II) ion (Mn²⁺).
  • The balanced chemical equation is: 16H⁺(aq) + 2MnO₄⁻(aq) + 5[C₂O₄]²⁻(aq) → 10CO₂(g) + 2Mn²⁺(aq) + 8H₂O(l).

Concentration of Ions

  • Solutions with higher concentrations of ions have greater numbers of ions in solution.
  • For example, 1.50 M Al(NO₃)₃ has the greatest concentration of ions (6.00M) compared to the other solutions.

Crystal Field Theory

  • Decreasing the oxidation state of a metal center does not lead to a greater crystal field splitting. This is because it leads to a decrease in metal-ligand bonding strength.
  • Decreasing the electronegativity of a ligand's binding atom decreases a ligand's ability to donate electron density to the metal center, thus leading to a decrease in crystal field splitting.
  • An increase in crystal field splitting makes the probability that a metal center will reside in a low spin electron configuration greater.
  • The d₂² and dₓ²-y² orbitals participate in bonding, while the remaining d-orbitals are non-bonding in an octahedral arrangement.

Coordination Complexes

  • Complex 1 is most likely to reside in a low-spin configuration.
  • Complex 3 will have the greatest crystal field splitting.
  • Complex 2 is most likely to absorb the lowest energy visible light. (E.g., red).
  • A complex that absorbs 600 nm light appears blue.

Gas Containers

  • Assuming ideal behavior, Container A (He) has the greatest pressure of gas.
  • Assuming ideal behavior, Container C (NH₃) has the greatest density of gas.
  • Assuming real behavior, Container C (NH₃) has the lowest pressure of gas.
  • Assuming real behavior, all containers have the same greatest volume of available space.

Chemical Reactions

  • Various chemical reactions and their classifications (precipitation, acid/base, redox) are described.

Boiling Point

  • From a given set of structures, the compound with the highest boiling point should be selected.

Oxidation Numbers

  • Oxidation numbers are assigned to the central atoms of given molecules.

Surface Tension, Viscosity etc analysis

  • 1,4-dioxane is more miscible with hexane.
  • 1,4-dioxane has lower surface tension and viscosity compared to glycerol.
  • 1,4-dioxane has less adhesion to glass compared to glycerol.

Xenon Isotopes

  • Molar mass of isotope 129 = 128.9 g/mol
  • Molar mass of isotope 131 = 131.0 g/mol

Empirical Formula

  • The empirical formula for a given compound can be determined via combustion analysis data and titration data.

Molecular Formula

  • The molecular formula for a given compound is determined from the empirical formula and molar mass. A sample calculation is included

Lead (II) Oxide Reactions

  • A set of molecular and ionic equations show the reaction of lead(II) oxide with nitric acid and potassium iodide. Product names are identified.
  • The limiting reagent and amount of product are determined for the reactions.
  • Concentrations of lead(II), potassium, and hydronium ions are calculated at the end of the reaction.

Molecular Orbitals

  • Molecular orbital diagrams are drawn for BF and KrH4.
  • The bond order is determined for these species
  • The consistency of MO diagrams with known properties (bond order, charge distribution) are discussed.

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Practice Exam 3 Key PDF

Description

Test your knowledge on key concepts in chemistry, including orbital interactions like σ and π bonding, aqueous reactions involving permanganate and oxalate, and the effects of ion concentration. Dive into crystal field theory to see how metal oxidation states affect bonding strength. Ideal for chemistry students exploring complex bonding theories.

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