Chemistry Chapter 8: Polarity of Compounds
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Questions and Answers

Which compound is nonpolar?

  • CH3CHO
  • cis-dichloroethylene
  • CH2=CHCl
  • 1,2 dichloroethane (correct)

What characteristic makes cis-dichloroethylene polar?

  • A straight-chain structure
  • The presence of a single chlorine atom
  • The presence of asymmetric carbon atoms
  • The arrangement of chlorine atoms creating a net dipole moment (correct)

Which of the following compounds has no isomer?

  • ClCH2CH2Cl (correct)
  • CH3CHO
  • CH2=CHCl
  • CH3CH2CH2Cl

What type of bond is present in cis-dichloroethylene?

<p>Double bonds between carbon atoms (C)</p> Signup and view all the answers

Which compound contains both a chlorine atom and a carbon-carbon double bond?

<p>cis-dichloroethylene (D)</p> Signup and view all the answers

Study Notes

Polarity of Compounds

  • 1,2-dichloroethane ($C_2H_4Cl_2$) is a nonpolar molecule due to its symmetrical tetrahedral geometry.
  • The dipole moments of the two C-Cl bonds in 1,2-dichloroethane cancel each other out, resulting in overall nonpolarity.
  • In contrast, cis-dichloroethylene ($C_2H_2Cl_2$) has a polar character because it features a double bond (C=C) and a bent shape.
  • The cis configuration leads to an uneven distribution of charge, resulting in a net dipole moment.

Isomers of Compounds

  • $CH_3CH_2CH_2Cl$: This compound has isomers, including primary and secondary alkyl chlorides.
  • $CH_3CHO$: This compound (acetaldehyde) has structural isomers, specifically cyclic and branched variants.
  • $CH_2=CHCl$: This compound (vinyl chloride) has geometric isomers due to the presence of the double bond.
  • $ClCH_2CH_2Cl$: This compound (1,2-dichloroethane) has no isomers, as the two chlorine atoms are bound to the same carbon chain without alternative structural arrangements.

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Description

This quiz explores the molecular polarity of 1,2 dichloroethane and cis-dichloroethylene. It focuses on the structural and bonding differences that lead to nonpolar and polar characteristics. Test your understanding of molecular shapes and dipole moments in these compounds.

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