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Questions and Answers
Consider the following balanced chemical reaction: $2 ClO (g) \rightleftharpoons Cl (g) + ClO_2 (g))$. The equilibrium constant, K, for this reaction at 385 K is $4.26 \times 10^{-4}$. If 1.240 atm of $ClO (g)$ and 0.330 atm of $Cl (g)$ are sealed in a container at 385 K, and no $ClO_2 (g)$ is present initially, what is the partial pressure of $ClO (g)$ (in atm) after equilibrium is established?
Consider the following balanced chemical reaction: $2 ClO (g) \rightleftharpoons Cl (g) + ClO_2 (g))$. The equilibrium constant, K, for this reaction at 385 K is $4.26 \times 10^{-4}$. If 1.240 atm of $ClO (g)$ and 0.330 atm of $Cl (g)$ are sealed in a container at 385 K, and no $ClO_2 (g)$ is present initially, what is the partial pressure of $ClO (g)$ (in atm) after equilibrium is established?
- 1.240 atm
- 0.332 atm
- 1.236 atm (correct)
- 0.00196 atm
Consider the following balanced chemical reaction: $BrO (g) + ClO (g) \rightleftharpoons ClO_2 (g) + Br (g))$. The equilibrium constant, K, for this reaction at 385 K is 0.040 and the reaction is endothermic, as written. Which of the following statements is TRUE regarding Plot A?
Consider the following balanced chemical reaction: $BrO (g) + ClO (g) \rightleftharpoons ClO_2 (g) + Br (g))$. The equilibrium constant, K, for this reaction at 385 K is 0.040 and the reaction is endothermic, as written. Which of the following statements is TRUE regarding Plot A?
- Plot A depicts the reaction spontaneously proceeding in the forward direction to reach equilibrium at a temperature less than 385 K.
- Plot A depicts the reaction spontaneously proceeding in the reverse direction to reach equilibrium at a temperature greater than 385 K.
- Plot A depicts the reaction spontaneously proceeding in the forward direction to reach equilibrium at a temperature greater than 385 K. (correct)
- Plot A depicts the reaction spontaneously proceeding in the forward direction to reach equilibrium at a temperature equal to 385 K.
Consider the generic, balanced chemical reaction: $A(g) + 2 B(g) \rightleftharpoons 2 C(g)$ which is endothermic. If the reaction is allowed to reach equilibrium and is then heated from the original temperature, $T_1$, to a new, higher temperature, $T_2$, in which direction does the reaction spontaneously shift to re-establish equilibrium?
Consider the generic, balanced chemical reaction: $A(g) + 2 B(g) \rightleftharpoons 2 C(g)$ which is endothermic. If the reaction is allowed to reach equilibrium and is then heated from the original temperature, $T_1$, to a new, higher temperature, $T_2$, in which direction does the reaction spontaneously shift to re-establish equilibrium?
- Reverse
- Forward (correct)
- Ambiguous
Consider the generic, balanced chemical reaction: $A(g) + 2 B(g) \rightleftharpoons C(g) + D(g)$ which is exothermic. If the reaction is allowed to reach equilibrium and is then heated from the original temperature, $T_1$, to a new, higher temperature, $T_2$, in which direction does the reaction spontaneously shift to re-establish equilibrium?
Consider the generic, balanced chemical reaction: $A(g) + 2 B(g) \rightleftharpoons C(g) + D(g)$ which is exothermic. If the reaction is allowed to reach equilibrium and is then heated from the original temperature, $T_1$, to a new, higher temperature, $T_2$, in which direction does the reaction spontaneously shift to re-establish equilibrium?
Consider the generic, balanced chemical reaction: $A(g) + B(g) \rightleftharpoons C(s) + 2 D(g)$ which is endothermic (Note that product C is a pure solid.). If the reaction is allowed to reach equilibrium and is then heated from the original temperature, $T_1$, to a new, higher temperature, $T_2$, in which direction does the reaction spontaneously shift to re-establish equilibrium?
Consider the generic, balanced chemical reaction: $A(g) + B(g) \rightleftharpoons C(s) + 2 D(g)$ which is endothermic (Note that product C is a pure solid.). If the reaction is allowed to reach equilibrium and is then heated from the original temperature, $T_1$, to a new, higher temperature, $T_2$, in which direction does the reaction spontaneously shift to re-establish equilibrium?
Consider the balanced gas phase reaction shown below: $4 NO (g) + 6 H_2O (g) \rightleftharpoons 4 NH_3 (g) + 5 O_2 (g)$. K = $8.32 \times 10^{-19}$ at temperature T. If 1.25 atm of $NH_3(g)$ and 1.25 atm of $O_2(g)$ are placed in a sealed container at temperature T, and no NO (g) or $H_2O (g)$ are initially present, what is the partial pressure of $NH_3 (g)$ (in atm) after equilibrium has been established?
Consider the balanced gas phase reaction shown below: $4 NO (g) + 6 H_2O (g) \rightleftharpoons 4 NH_3 (g) + 5 O_2 (g)$. K = $8.32 \times 10^{-19}$ at temperature T. If 1.25 atm of $NH_3(g)$ and 1.25 atm of $O_2(g)$ are placed in a sealed container at temperature T, and no NO (g) or $H_2O (g)$ are initially present, what is the partial pressure of $NH_3 (g)$ (in atm) after equilibrium has been established?
At high temperatures, the solid compound $(NH_4)_2CO_3$ decomposes according to the following balanced chemical reaction: $(NH_4)_2CO_3 (s) \rightleftharpoons 2 NH_3 (g) + CO_2 (g) + H_2O (g)$. When excess $(NH_4)_2CO_3 (s)$ is sealed in an evacuated container at 750 K, the total pressure is 3.52 atm after equilibrium is established. What is the equilibrium constant, K, for this reaction at 750 K?
At high temperatures, the solid compound $(NH_4)_2CO_3$ decomposes according to the following balanced chemical reaction: $(NH_4)_2CO_3 (s) \rightleftharpoons 2 NH_3 (g) + CO_2 (g) + H_2O (g)$. When excess $(NH_4)_2CO_3 (s)$ is sealed in an evacuated container at 750 K, the total pressure is 3.52 atm after equilibrium is established. What is the equilibrium constant, K, for this reaction at 750 K?
At high temperatures, the solid compound $(NH_4)_2CO_3$ decomposes according to the following balanced chemical reaction: $(NH_4)_2CO_3 (s) \rightleftharpoons 2 NH_3 (g) + CO_2 (g) + H_2O (g)$. If the equilibrium constant K at 775 K is equal to 5.47. Explain why when 1.40 atm of each gas are initially sealed in a container at 775 K, no solid is observed to form. Explain your reasoning in 1-2 sentences
At high temperatures, the solid compound $(NH_4)_2CO_3$ decomposes according to the following balanced chemical reaction: $(NH_4)_2CO_3 (s) \rightleftharpoons 2 NH_3 (g) + CO_2 (g) + H_2O (g)$. If the equilibrium constant K at 775 K is equal to 5.47. Explain why when 1.40 atm of each gas are initially sealed in a container at 775 K, no solid is observed to form. Explain your reasoning in 1-2 sentences
At high temperatures, the solid compound $(NH_4)_2CO_3$ decomposes according to the following balanced chemical reaction: $(NH_4)_2CO_3 (s) \rightleftharpoons 2 NH_3 (g) + CO_2 (g) + H_2O (g)$. If the equilibrium constant K at 775 K is equal to 5.47. Determine the minimum amount of $NH_3 (g)$ that should be added to the container described in part (b, i) above in order for solid to form at 775 K. Report your answer in terms of the minimum amount of pressure (in atm) that should be added to the 1.40 atm of $NH_3 (g) already present.
At high temperatures, the solid compound $(NH_4)_2CO_3$ decomposes according to the following balanced chemical reaction: $(NH_4)_2CO_3 (s) \rightleftharpoons 2 NH_3 (g) + CO_2 (g) + H_2O (g)$. If the equilibrium constant K at 775 K is equal to 5.47. Determine the minimum amount of $NH_3 (g)$ that should be added to the container described in part (b, i) above in order for solid to form at 775 K. Report your answer in terms of the minimum amount of pressure (in atm) that should be added to the 1.40 atm of $NH_3 (g) already present.
A 0.40 M aqueous solution of HF is prepared at 25°C. Given: $K_a (HF, 25°C) = 6.6 \times 10^{-4}$. What is the percent dissociation of HF after equilibrium is established?
A 0.40 M aqueous solution of HF is prepared at 25°C. Given: $K_a (HF, 25°C) = 6.6 \times 10^{-4}$. What is the percent dissociation of HF after equilibrium is established?
Using your work from part (a), determine the number of moles of $HClO_4$ that should be added to 600.0 mL of pure water at 25°C so that this solution would have the same final pH as the 0.40 M aqueous solution of HF described above.
Using your work from part (a), determine the number of moles of $HClO_4$ that should be added to 600.0 mL of pure water at 25°C so that this solution would have the same final pH as the 0.40 M aqueous solution of HF described above.
Comparing a 600.0 mL sample of the 0.40 M aqueous solution of HF and the 600.0 mL sample of the $HClO_4$ solution, is this statement TRUE or FALSE: After equilibrium is established for each solution, the $[H_3O^+]$ is the same for both solutions.
Comparing a 600.0 mL sample of the 0.40 M aqueous solution of HF and the 600.0 mL sample of the $HClO_4$ solution, is this statement TRUE or FALSE: After equilibrium is established for each solution, the $[H_3O^+]$ is the same for both solutions.
Comparing a 600.0 mL sample of the 0.40 M aqueous solution of HF and the 600.0 mL sample of the $HClO_4$ solution, is this statement TRUE or FALSE: The same number of moles of $OH^−$ would be required to completely neutralize each solution.
Comparing a 600.0 mL sample of the 0.40 M aqueous solution of HF and the 600.0 mL sample of the $HClO_4$ solution, is this statement TRUE or FALSE: The same number of moles of $OH^−$ would be required to completely neutralize each solution.
Comparing a 600.0 mL sample of the 0.40 M aqueous solution of HF and the 600.0 mL sample of the $HClO_4$ solution, is this statement TRUE or FALSE: Both solutions would have a pH of 7.00 after completely neutralizing the acids with OH.
Comparing a 600.0 mL sample of the 0.40 M aqueous solution of HF and the 600.0 mL sample of the $HClO_4$ solution, is this statement TRUE or FALSE: Both solutions would have a pH of 7.00 after completely neutralizing the acids with OH.
At 25°C, $K_a$ for the weak acid, hypochlorous acid, HClO, is $3.0 \times 10^{-8}$ ($pK_a$=7.53). You may assume a temperature of 25°C throughout this problem. Determine the mass (in g) of solid potassium hypochlorite, $K^+ClO^−$, that must be added to a 500 mL aqueous solution of 0.10 M HClO to prepare a buffer solution with pH = 8.00.
At 25°C, $K_a$ for the weak acid, hypochlorous acid, HClO, is $3.0 \times 10^{-8}$ ($pK_a$=7.53). You may assume a temperature of 25°C throughout this problem. Determine the mass (in g) of solid potassium hypochlorite, $K^+ClO^−$, that must be added to a 500 mL aqueous solution of 0.10 M HClO to prepare a buffer solution with pH = 8.00.
Write the balanced chemical equation that represents the governing equilibrium in this buffer: $K^+ClO^−$ + HClO
Write the balanced chemical equation that represents the governing equilibrium in this buffer: $K^+ClO^−$ + HClO
50 mL of a 0.20 M aqueous HCl solution is then added to the buffer described in part (a). Determine the pH of the buffer after this addition of HCl.
50 mL of a 0.20 M aqueous HCl solution is then added to the buffer described in part (a). Determine the pH of the buffer after this addition of HCl.
Using your work from part (c), calculate the number of moles of KClO that must be added to the buffer solution in part (c) to bring it back to the original pH of 8.00.
Using your work from part (c), calculate the number of moles of KClO that must be added to the buffer solution in part (c) to bring it back to the original pH of 8.00.
Volume of 0.50 M NaOH Added (mL). Determine the number of moles of HA in the original 200.0 mL solution (i.e., before any NaOH solution was added).
Volume of 0.50 M NaOH Added (mL). Determine the number of moles of HA in the original 200.0 mL solution (i.e., before any NaOH solution was added).
Calculate the $K_b$ for the conjugate weak base of the weak acid HA.
Calculate the $K_b$ for the conjugate weak base of the weak acid HA.
Which of the following is the monoprotic weak acid, HA, in the titration curve shown above?
Which of the following is the monoprotic weak acid, HA, in the titration curve shown above?
When 500.0 mL of a 0.50 M aqueous solution of $MgCl_2$ is added to 250.0 mL of a 0.50 M aqueous solution of NaF at 25° C, a precipitate of the sparingly-soluble salt, $MgF_2$, is formed. What is the mass of $MgF_2 (in grams) that precipitates immediately upon mixing the two solutions, assuming complete reaction?
When 500.0 mL of a 0.50 M aqueous solution of $MgCl_2$ is added to 250.0 mL of a 0.50 M aqueous solution of NaF at 25° C, a precipitate of the sparingly-soluble salt, $MgF_2$, is formed. What is the mass of $MgF_2 (in grams) that precipitates immediately upon mixing the two solutions, assuming complete reaction?
In order to establish equilibrium, a small amount of the $MgF_2$ precipitate determined in part (a) re-dissolves back into solution. What is the mass of $MgF_2 (in grams) that re-dissolves?
In order to establish equilibrium, a small amount of the $MgF_2$ precipitate determined in part (a) re-dissolves back into solution. What is the mass of $MgF_2 (in grams) that re-dissolves?
Flashcards
Equilibrium Constant (K)
Equilibrium Constant (K)
A measure of the relative amounts of reactants and products at equilibrium.
Dynamic Equilibrium
Dynamic Equilibrium
Species participating in a chemical reaction are in dynamic equilibrium when the rate of forward and reverse reactions are equal.
Partial Pressure
Partial Pressure
The pressure exerted by a single gas in a mixture of gases.
Method of Successive Approximations (MOSA)
Method of Successive Approximations (MOSA)
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Assumption in Equilibrium Calc
Assumption in Equilibrium Calc
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Reversible Reaction
Reversible Reaction
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Equilibrium State
Equilibrium State
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Initial Pressure
Initial Pressure
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Change in Pressure
Change in Pressure
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Equilibrium Pressures
Equilibrium Pressures
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Simplifying the Quadratic
Simplifying the Quadratic
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K Expression Setup
K Expression Setup
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Solving for 'x'
Solving for 'x'
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Verify the approximation
Verify the approximation
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Equilibrium Pressures Calculation
Equilibrium Pressures Calculation
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Reaction Quotient (Q)
Reaction Quotient (Q)
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Temp and Equilibrium
Temp and Equilibrium
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Inert gas and equilibrium
Inert gas and equilibrium
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Catalyst and Equilibrium
Catalyst and Equilibrium
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Le Chatelier's Principle
Le Chatelier's Principle
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Pressure and equilibrium
Pressure and equilibrium
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Reactants and equilibrium
Reactants and equilibrium
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Products and equilibrium
Products and equilibrium
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Chemical Kinetics
Chemical Kinetics
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Reaction Rate
Reaction Rate
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Catalyst
Catalyst
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Homogeneous Catalyst
Homogeneous Catalyst
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Heterogeneous Catalyst
Heterogeneous Catalyst
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Activation Energy (Ea)
Activation Energy (Ea)
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Reaction Intermediate
Reaction Intermediate
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Study Notes
- This is Chemistry 112A First Exam Key created by Professor Bleeke
- The exam consists of questions covering representative topics
- The exam duration is 1.5 hours
- The exam contains 8 questions on 10 numbered pages, including the scratch page.
- The exam must be turned in its entirety, including the scratch page
- Total points are 100
Exam Point Breakdown
- Question 1 is worth 12 points
- Question 2 is worth 8 points
- Question 3 is worth 12 points
- Question 4 is worth 14 points
- Question 5 is worth 13 points
- Question 6 is worth 13 points
- Question 7 is worth 14 points
- Question 8 is worth 14 points
Question 1a
- Consider the balanced chemical reaction: 2 ClO (g) = Cl (g) + ClO2 (g)
- The equilibrium constant, K, for this reaction at 385 K is 4.26 × 10−4
- 1.240 atm of ClO (g) and 0.330 atm of Cl (g) are sealed in a container at 385 K, with no ClO2 (g) initially present
- After equilibrium, partial pressures are: Pclo= 1.236 atm, Pc1= 0.332 atm, Pc102= 0.00196 atm
Question 1b
- Consider the balanced chemical reaction: BrO (g) + ClO (g) = ClO2 (g) + Br (g)
- The equilibrium constant, K, for this reaction at 385 K is 0.040 and the reaction is endothermic
- Plot A depicts the reaction spontaneously proceeding in the forward direction to reach equilibrium at a temperature less than 385 K
- Plot B depicts the reaction spontaneously proceeding in the forward direction to reach equilibrium at a temperature greater than 385 K
- Plot C depicts the reaction spontaneously proceeding in the reverse direction to reach equilibrium at a temperature equal to 385 K
Question 2
- Reactions are either endothermic or exothermic in the forward direction
- Each reaction reaches equilibrium and is then heated from T1 to a higher temperature, T2
- The reaction shifts spontaneously to re-establish equilibrium
- A) For A(g) + 2 B(g) = 2 C(g) which is endothermic, the reaction shifts forward
- B) For A(g) + B(g) = 2 C(g) which is exothermic, the reaction shifts reverse
- C) For A(g) + 2 B(g) = C(g) + D(g) which is exothermic, direction is ambiguous
- D) For A(g) + B(g) = C(s) +2 D(g) which is endothermic, the reaction shifts forward
Question 3
- A balanced gas phase reaction: 4 NO (g) + 6 H2O (g) = 4 NH3 (g) + 5 O2 (g)
- K = 8.32 × 10-19 at temperature T
- _1.25 atm of NH3(g) and 1.25 atm of O2(g) are placed in a sealed container at temperature T
- No NO (g) or H2O (g) are initially present
- After equilibrium partial pressures are: PNH3= 0.251 atm, Po₂= 0.00119 atm
Question 4a
- Solid compound (NH4)2CO3 decomposes at high temperatures
- (NH4)2CO3 (s) = 2 NH3 (g) + CO2 (g) + H2O (g)
- Excess (NH4)2CO3 (s) is sealed in an evacuated container at 750 K
- Total pressure is 3.52 atm after equilibrium is established
- Equilibrium constant K = 2.40
Question 4b
- Same chemical reaction at T = 775 K
- Equilibrium constant K at 775 K is equal to 5.47
Question 4bi
- When 1.40 atm of each gas are initially sealed in a container at 775 K, no solid is observed to form
- When 1.40 atm of each gas are sealed in a container at 775 K, Q (3.84) is less than K (5.47)
- The reaction is spontaneous in the forward direction and no solid forms
Question 4bii
- To determine the minimum amount of NH3 (g) that should be added to the container described in part (b, i) above in order for solid to form at 775 K
- A minimum of 0.27 atm of NH3(g) must be added
- When Q = K, the reaction is at equilibrium and solid would form
Question 5a
- A 0.40 M aqueous solution of HF is prepared at 25°C
- Ka (HF, 25°C) = 6.6 × 10-4 and pKa (HF, 25°C) = 3.18
- % dissociation = 3.98%
Question 5b
- Using work from part (a), determine the number of moles of HClO4 that should be added to 600.0 mL of pure water at 25°C so that this solution would have the same final pH as the 0.40 M aqueous solution of HF described above
-
- 00955 moles
Question 5c
- Comparing a 600.0 mL sample of the 0.40 M aqueous solution of HF described in part (a) and the 600.0 mL sample of the HClO4 solution described in part (b) to determine if the statements below are TRUE or FALSE
- After equilibrium is established for each solution, the [H3O⁺] is the same for both solutions (TRUE)
- The same number of moles of OH¯ would be required to completely neutralize each solution (FALSE)
- Both solutions would have a pH of 7.00 after completely neutralizing the acids with OH (FALSE)
Question 6a
- At 25°C, Ka for hypochlorous acid (HClO) is 3.0 ×_10-8 (pKa=7.53)
- KClO is completely soluble in water and MW (KClO) = 90.55 g/mol
- 13.4 grams of solid potassium hypochlorite, K+ClO¯, that must be added to a 500 mL aqueous solution of 0.10 M HClO to prepare a buffer solution with pH = 8.00
Question 6b
- The balanced chemical equation that represents the governing equilibrium in this buffer is ClO (aq) + H2O (l) = HClO (aq) + OH¯ (aq)
Question 6c
- 50 mL of a 0.20 M aqueous HCl solution is then added to the buffer described in part (a) to determine the pH of the buffer after this addition
- pH = 7.89
Question 6d
- Determine the number of moles of KClO that must be added to the buffer solution in part (c) to bring it back to the original pH of 8.00
- nclo- = 0.0391 mol
Question 7a
- A 200.0 mL aqueous solution at 25°C contains a weak, monoprotic acid, HA
- This solution is titrated with a 0.50 M aqueous solution of NaOH at 25°C
- Based on the graph, moles NaOH added = moles of HA
- Moles NaOH (0. 50 M)(0.152 L) = 0.076 moles HA
Question 7b
- Calculate the K♭ for the conjugate weak base of the weak acid HA
-
- 076 moles of HA is converted to A- after adding of 152 mL NaOH
- Kb = 5.32 × 10-10
Question 7c
- The monoprotic weak acid, HA, in the titration curve is identified as HN3
- Ka = 1.9 × 10-5
Question 8a
- When 500.0 mL of a 0.50 M aqueous solution of MgCl2 is added to 250.0 mL of a 0.50 M aqueous solution of NaF at 25°
- A precipitate of the sparingly-soluble salt, MgF2, is formed
- MgCl2 and NaF are completely soluble in water to produce Mg2+, Cl-, Na+, and F¯ ions
- Ksp for MgF2 = 6.6 × 10-9 at 25°C and MW (MgF2) = 62.30 g/mol
- _You may ignore any reaction between F¯ and H2O
-
- 89 grams of MgF2 are precipitates
Question 8b
- In order to establish equilibrium, a small amount of the MgF2 precipitate determined in part (a) re-dissolves back into solution
-
- 79 × 10-3 grams MgF2 that re-dissolves
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Description
Chemistry 112A First Exam Key by Professor Bleeke. The exam covers representative topics. It consists of 8 questions on 10 numbered pages, including the scratch page, and must be turned in its entirety.