Chemical Equilibrium Concepts
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Questions and Answers

In the ICE table method for solving equilibrium problems, which step involves using the balanced chemical equation to express the equilibrium constant $K$?

  • Step 4: Solve for x.
  • Step 3: Write the expression for K. (correct)
  • Step 5: Calculate equilibrium concentrations.
  • Step 2: Define changes in concentration (E).

According to Le Châtelier's Principle, how will a system at equilibrium respond to the removal of a product?

  • There will be no change as the system is already at equilibrium.
  • The reaction will shift to the right, favoring product formation. (correct)
  • The reaction will shift to the left, favoring reactant formation.
  • The reaction will proceed at a slower rate without changing concentrations.

For the reversible reaction $N_2(g) + 3H_2(g) ightleftharpoons 2NH_3(g)$, how does decreasing the volume of the container affect the equilibrium?

  • The rate of both forward and reverse reactions decreases equally.
  • There is no change in the equilibrium position because the total number of moles remains constant.
  • The equilibrium shifts to the right, favoring the production of $NH_3$. (correct)
  • The equilibrium shifts to the left, favoring the production of $N_2$ and $H_2$.

For an exothermic reaction at equilibrium, what is the effect of increasing the temperature?

<p>The equilibrium shifts to the left, favoring reactant formation. (C)</p> Signup and view all the answers

Why does adding a catalyst to a reaction at equilibrium not change the equilibrium position?

<p>A catalyst speeds up both the forward and reverse reactions equally, leading to no net change in equilibrium concentrations. (C)</p> Signup and view all the answers

A chemical reaction is said to be at equilibrium when:

<p>The rate of the forward reaction equals the rate of the reverse reaction. (D)</p> Signup and view all the answers

How does a reaction at equilibrium differ from a reaction that has reached completion?

<p>At equilibrium, the rates of forward and reverse reactions are balanced, whereas completion means all reactants have turned into products. (B)</p> Signup and view all the answers

Which statement accurately describes a system at dynamic equilibrium?

<p>The rates of the forward and reverse reactions are constant and non-zero. (D)</p> Signup and view all the answers

What does the equilibrium constant (K) indicate about a reversible reaction?

<p>The extent to which a reaction proceeds towards product formation at equilibrium. (B)</p> Signup and view all the answers

If a reaction has a very small equilibrium constant (K << 1), what does this imply about the reaction at equilibrium?

<p>The reaction mixture consists mostly of reactants. (D)</p> Signup and view all the answers

Consider the following reaction at equilibrium: $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$. If, at equilibrium, the partial pressures are $P_{N_2} = 1 \text{ atm}$, $P_{H_2} = 2 \text{ atm}$, and $P_{NH_3} = 4 \text{ atm}$, what is the value of $K_p$?

<p>$K_p = 2$ (B)</p> Signup and view all the answers

For a certain reaction, the equilibrium constant $K_c$ is expressed using concentrations in molarity, while $K_p$ is expressed using partial pressures in atmospheres. Under what conditions are $K_c$ and $K_p$ equal for a given reaction?

<p>When the change in the number of moles of gas is zero ($\Delta n = 0$). (C)</p> Signup and view all the answers

Which of the following statements correctly describes the relationship between K, $K_c$, and $K_p$?

<p>K is a general term for the equilibrium constant; $K_c$ uses concentrations, and $K_p$ uses partial pressures. (D)</p> Signup and view all the answers

In what scenario is it possible to completely fill out an ICE table with numerical values directly from the information provided in the problem, without needing to solve for 'x'?

<p>When the initial concentrations and the equilibrium concentrations of at least one reactant or product are given. (C)</p> Signup and view all the answers

When using an ICE table to solve for equilibrium concentrations, under what circumstances would you include '0' as an initial concentration in the 'I' row?

<p>When a reactant or product is not initially present in the reaction mixture. (D)</p> Signup and view all the answers

How are stoichiometric coefficients used when completing the 'C' (Change) row of an ICE table?

<p>They appear as multipliers of the 'x' variable, indicating how much each concentration changes relative to others. (A)</p> Signup and view all the answers

What does it mean if the reaction quotient, Q, is much larger than the equilibrium constant, K ($Q >> K$)?

<p>The reaction will proceed in the reverse direction to reach equilibrium. (D)</p> Signup and view all the answers

Which statement accurately describes the relationship between the reaction quotient (Q), the equilibrium constant (K), and the direction a reversible reaction will shift to reach equilibrium?

<p>If Q &gt; K, the reaction shifts to produce more reactants; if Q &lt; K, the reaction shifts to produce more products. (C)</p> Signup and view all the answers

In the context of equilibrium calculations, what is the primary difference between using the equilibrium constant, K, and the reaction quotient, Q?

<p>K is used to determine if a system is at equilibrium, while Q is used to predict the direction a reaction will shift to reach equilibrium. (A)</p> Signup and view all the answers

Consider the reaction $A + B \rightleftharpoons C + D$. At a certain point, $[A] = 2M$, $[B] = 1M$, $[C] = 3M$, and $[D] = 2M$. If the $K_c$ for this reaction is 4, which direction will the reaction shift to reach equilibrium?

<p>The reaction will shift to the left (towards reactants). (C)</p> Signup and view all the answers

Which of the following is a correct setup of an ICE table for the reaction $2A(g) \rightleftharpoons B(g)$, given an initial concentration of A as 2.0 M and no initial B, if 'x' represents the change in concentration of B?

<p>I: [A] = 2.0, [B] = 0; C: [A] = -2x, [B] = +x; E: [A] = 2.0 - 2x, [B] = x (D)</p> Signup and view all the answers

For the reaction $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$, what expression correctly relates the changes in concentration of reactants and products in the 'C' row of an ICE table?

<p>$[N_2] = -x, [H_2] = -3x, [NH_3] = +2x$ (A)</p> Signup and view all the answers

Given the initial concentrations $[A] = 2.0 M$ and $[B] = 0 M$ for the reaction $A(g) \rightleftharpoons 2B(g)$, and given the equilibrium constant $K = 4$, set up the correct equation to solve for 'x', where 'x' is the change in concentration of A.

<p>$4 = (2x)^2 / (2 - 2x)$ (A)</p> Signup and view all the answers

Which of the following mathematical representations correctly describes how to calculate the equilibrium constant, K, for a given reversible reaction?

<p>K = [Products] / [Reactants] (D)</p> Signup and view all the answers

Consider the reversible reaction: $aA(g) + bB(g) \rightleftharpoons cC(g) + dD(g)$. Which expression correctly represents the equilibrium constant, $K_c$?

<p>$K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}$ (B)</p> Signup and view all the answers

Which states of matter are excluded from the equilibrium constant expression ($K_c$) and why?

<p>Solids and pure liquids because their concentrations remain constant during the reaction. (C)</p> Signup and view all the answers

For the reversible reaction $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$, if at equilibrium there are significantly more reactants than products, what does this indicate about the value of $K_c$?

<p>$K_c$ is much less than 1. (D)</p> Signup and view all the answers

Given the reaction: $X(g) + 2Y(g) \rightleftharpoons Z(g)$ with an equilibrium constant $K_1$. If the reaction is reversed and multiplied by 2, resulting in $2Z(g) \rightleftharpoons 2X(g) + 4Y(g)$, how is the new equilibrium constant, $K_2$, related to $K_1$?

<p>$K_2 = \frac{1}{K_1^2}$ (B)</p> Signup and view all the answers

Consider two reactions: Reaction 1: $A(g) \rightleftharpoons B(g)$ with equilibrium constant $K_1$ Reaction 2: $B(g) \rightleftharpoons C(g)$ with equilibrium constant $K_2$. If the two reactions are added together, what is the equilibrium constant for the overall reaction $A(g) \rightleftharpoons C(g)$?

<p>$K = K_1 \times K_2$ (A)</p> Signup and view all the answers

For the reaction $2NO(g) + O_2(g) \rightleftharpoons 2NO_2(g)$, $K_c$ is $4.0 \times 10^5$ at 25°C. If the reaction is written as $NO(g) + \frac{1}{2}O_2(g) \rightleftharpoons NO_2(g)$, what is the new value of $K_c$?

<p>$6.3 \times 10^2$ (B)</p> Signup and view all the answers

The equilibrium constant for the reaction $A(g) + B(g) \rightleftharpoons C(g)$ is $K$. If the concentrations of A, B, and C are all doubled, how is the reaction quotient, Q, related to K?

<p>Q = K/4 (C)</p> Signup and view all the answers

Consider the following sequential reactions: $A \rightleftharpoons B$ ($K_1 = 2$) and $B \rightleftharpoons C$ ($K_2 = 3$). What is the equilibrium constant for the overall reaction $A \rightleftharpoons C$?

<p>6 (D)</p> Signup and view all the answers

When using ICE tables to solve equilibrium problems, what is the crucial difference between problems where you are given initial concentrations and K and asked to find equilibrium concentrations, versus problems where you are given some equilibrium concentrations and asked to find K?

<p>In the first case, you solve for x to find equilibrium concentrations; in the second, you use equilibrium concentrations to directly calculate K. (D)</p> Signup and view all the answers

Flashcards

Chemical Equilibrium

Forward and reverse reactions occur at the same rate, resulting in constant reactant and product amounts.

Equilibrium vs. Completion

Equilibrium is dynamic with ongoing reactions, while completion means all reactants have turned into products and the reaction stops.

At equilibrium, the rates are...

The forward and reverse reaction rates

Dynamic Equilibrium

Forward and reverse reactions continue to happen.

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At equilibrium, the amounts are...

Reactant and product amounts are constant.

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Equilibrium Constant (K)

K is the ratio of products to reactants at equilibrium, indicating reaction favorability.

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K Value Significance

Large K means more products, small K means more reactants.

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K, Kc, and Kp

K is general, Kc uses concentration, and Kp uses pressure.

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ICE Table Method

A systematic approach using an ICE table to solve equilibrium problems; Write balanced equation, Create ICE table, Write K expression, Solve for x, Calculate concentrations.

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Le Châtelier's Principle

If a stress is applied to a system at equilibrium, the system will shift to relieve the stress and re-establish a new equilibrium.

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Adding Reactant (Equilibrium)

Adding a reactant shifts the equilibrium to the right, favoring product formation.

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Catalyst and Equilibrium

Adding a catalyst speeds up forward and reverse reactions equally, reaching equilibrium without changing its position.

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Equilibrium is Dynamic

At equilibrium, reactants convert to products and products revert to reactants at the same rate, maintaining constant concentrations.

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K Expression

Products' concentrations, raised to their coefficients, divided by reactants' concentrations, raised to their coefficients.

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States Excluded from K

Solids and pure liquids are excluded because their concentrations remain constant during the reaction.

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K and Product/Reactant Amounts

K > 1 means more products; K < 1 means more reactants; K ≈ 1 means roughly equal amounts.

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Multiplying a Reaction by a Coefficient

Raise K to that power.

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Reversing a Reaction

Take the reciprocal of K (1/K).

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Adding Chemical Equations

Multiply their equilibrium constants together.

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What are ICE Tables?

ICE tables help solve equilibrium problems by organizing initial concentrations, changes, and equilibrium concentrations.

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Two Types of ICE Table Problems

One problem type calculates equilibrium concentrations given an initial concentration and K. The other calculates K given equilibrium concentrations.

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Reaction Quotient (Q)

It is the ratio of products to reactants at ANY given time, not necessarily at equilibrium. It predicts which direction a reaction will shift to reach equilibrium.

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Manipulating K

If you multiply a reaction by a constant, raise the equilibrium constant to that power. If you reverse a reaction, take the reciprocal of the equilibrium constant. If you add reactions, multiply their K values.

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Equilibrium Problem Type 1

Solving for equilibrium concentrations using initial concentrations and the equilibrium constant K. ICE table will contain variables, and you solve for 'x'.

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Equilibrium Problem Type 2

Determining the equilibrium constant (calculation of K) using initial and equilibrium concentrations, enabling complete ICE table filling.

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Difference Between Type 1 and 2 Equilibrium Problems

Both problem types use ICE tables. Type 1 requires solving for ‘x’, while type 2 allows direct calculation from given values.

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Q < K

The system shifts to produce more products to reach equilibrium. Rate of forward reaction is increased.

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Q > K

The system shifts to produce more reactants to reach equilibrium. Rate of reverse reaction is increased.

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ICE Table

Organize initial concentrations, changes, and equilibrium concentrations to solve equilibrium problems.

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ICE Table - Initial (I)

List the initial concentrations of all reactants and products in molarity. If concentration is not given, assume zero.

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ICE Table - Change (C)

Determine the change in concentration (x) for each species, considering stoichiometric coefficients. Use +/- 'x' to indicate direction reaction may shift.

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ICE Table - Equilibrium (E)

Sum the 'Initial' and 'Change' rows to find the equilibrium concentrations of each species.

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