Chapter 6 Test Algebra 1 Flashcards
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Chapter 6 Test Algebra 1 Flashcards

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Questions and Answers

What is an absolute value equation?

An equation that contains an absolute value expression, such as |X| = 4.

What are the solutions to the equation |X|=7?

7 and -7

How do you solve the equation |X-3| = 8?

Rewrite it as X-3=8 or X-3=-8, leading to solutions x=11 or x=-5.

An OR case occurs when the inequality is set to be greater than.

<p>False</p> Signup and view all the answers

A Compound AND case occurs when the inequality is set to be greater than.

<p>True</p> Signup and view all the answers

What needs to be checked to determine if an absolute value equation can be solved?

<p>The absolute value expression cannot equal a negative number.</p> Signup and view all the answers

How do you solve the equation 3|2x-7|-5=4?

<p>Rewrite it as |2x-7|=3 and then solve 2x-7=3 or 2x-7=-3.</p> Signup and view all the answers

What is the first step in solving and graphing an inequality in one variable like -2x+3?

<p>Identify the inequality and rewrite it in a solvable format.</p> Signup and view all the answers

Study Notes

Absolute Value Equations

  • Absolute value equation includes an expression like |X| = a, representing the distance of X from zero.
  • An equation |X| = 4 has solutions X = 4 and X = -4.

Solving |X| = 7

  • Solutions represent distances where X is 7 units away from zero, yielding X = 7 and X = -7.

Solving |X - 3| = 8

  • Rewrite into two cases: X - 3 = 8 and X - 3 = -8.
  • Solutions are X = 11 and X = -5, noted as an OR case due to two possible solutions.

OR Case Definition

  • An OR case arises when an inequality is set to be less than, allowing multiple solutions.

Compound AND Case

  • A Compound AND case occurs when the inequality is set to be greater than, leading to a single solution scenario.

Determining Solvability of Absolute Value Equations

  • Absolute value expressions cannot equal negative numbers; if |X| = -a, there are no solutions.
  • Isolate the absolute value expression first to assess solvability.

Solving 3|2x - 7| - 5 = 4

  • Begin with the equation 3|2x - 7| - 5 = 4, then adjust to isolate the absolute value.
  • Step-by-step isolation: add 5, divide by 3, yielding |2x - 7| = 3.
  • Break into two cases: 2x - 7 = 3 and 2x - 7 = -3, leading to solutions X = 5 and X = 2.

Solving and Graphing Inequalities

  • To solve and graph an inequality like -2x + 3, express the solution on a number line to visualize the inequality’s range.

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Test your knowledge on absolute value equations with these flashcards from Chapter 6 of Algebra 1. Review definitions and solve equations involving absolute values to reinforce your understanding. Perfect for quick study sessions or exam preparation.

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