Centripetal Motion Concepts
24 Questions
0 Views

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

An object traveling with uniform circular motion has a centripetal acceleration due to the change in

  • mass
  • direction (correct)
  • kinetic energy
  • speed
  • The diagram here represents a mass of 1.0 kilogram traveling at 8.0 meters per second in a circular path of radius 4.0 meters. v = 8.0 m/sec r = 4.0m m = 1.0 kg What is the centripetal acceleration of the object?

    16 m/sec^2

    The diagram shown represents a mass of 10.0 kilograms traveling at a constant speed of 4 meters per second in a horizontal circular path about point D. Speed = 4m/sec Mass = 10.kg Radius = 4m The centripetal acceleration of the satellite is directed toward point

  • D
  • B
  • C (correct)
  • A
  • What is the magnitude of the centripetal acceleration?

    <p>4 m/sec^2</p> Signup and view all the answers

    Which quantity would increase if the radius increased?

    <p>period</p> Signup and view all the answers

    If the 10-kilogram mass is replaced with a greater mass, the centripetal acceleration will

    <p>remain the same</p> Signup and view all the answers

    If the velocity of a car traveling around a circular track doubles, its centripetal acceleration would be

    <p>4 times greater</p> Signup and view all the answers

    An object on the end of a string rotates clockwise in a circle as shown in the diagram. If the string breaks when the object is at point X, which arrow below best represents the path of the object after the string has broken?

    <p>Arrow pointing to the right</p> Signup and view all the answers

    The diagram shows an object traveling clockwise in a horizontal, circular path at constant speed. Which arrow best shows the direction of the centripetal acceleration of the object at the instant shown?

    <p>Arrow pointing to the left</p> Signup and view all the answers

    The diagram shows an object with a mass of 1.0 kilogram attached to a string 0.50 meter long. The object is moving at a constant speed of 5.0 meters per second in a horizontal circular path with center at point O. string 0.50m 1.0-kg mass What is the magnitude of the centripetal force acting on the object?

    <p>25 N</p> Signup and view all the answers

    While the object is undergoing uniform circular motion, its acceleration

    <p>is directed toward the center of the circle</p> Signup and view all the answers

    If the string is cut when the object is at the position shown, the path the object will travel from this position will be

    <p>a straight line tangent to the circle</p> Signup and view all the answers

    If the string is lengthened while the speed of the object remains constant, the centripetal acceleration of the object will

    <p>decrease</p> Signup and view all the answers

    A 60-kilogram adult and a 30-kilogram child are passengers on a rotor ride at an amusement park. When the rotating hollow cylinder reaches a certain constant speed, v, the floor moves downward. Both passengers stay "pinned" against the wall of the rotor, as shown in the diagram. Compared to the magnitude of the acceleration of the adult, the magnitude of the acceleration of the child is

    <p>the same</p> Signup and view all the answers

    The diagram shows a 5.0-kilogram cart traveling clockwise in a horizontal circle of radius 2.0 meters at a constant speed of 4.0 meters per second. At the position shown, the velocity of the cart is directed toward point

    <p>Q</p> Signup and view all the answers

    At the position shown, the centripetal acceleration of the cart is directed toward point

    <p>P</p> Signup and view all the answers

    If the mass of the cart was doubled, the magnitude of the centripetal acceleration of the cart would be

    <p>unchanged</p> Signup and view all the answers

    What is the magnitude of the centripetal force acting on the cart?

    <p>40 N</p> Signup and view all the answers

    Base your answer(s) to the following question(s) on the information and diagram below. A 1.00 × 10^3-kilogram car is driven clockwise around a flat circular track of radius 25.0 meters. The speed of the car is a constant 5.00 meters per second. What minimum friction force must exist between the tires and the road to prevent the car from skidding as it rounds the curve?

    <p>5.00 × 10^3 N</p> Signup and view all the answers

    If the circular track were to suddenly become frictionless at the instant shown in the diagram, the car's direction of travel would be

    <p>toward W</p> Signup and view all the answers

    Base your answer(s) to the following question(s) on the information and diagram below. A 1200-kilogram car traveling at a constant speed of 9.0 meters per second turns at an intersection. The car follows a horizontal circular path with a radius of 25 meters to point P. At point P, the car hits an area of ice and loses all frictional force on its tires. Which path does the car follow on the ice?

    <p>C</p> Signup and view all the answers

    Calculate the magnitude of the centripetal force acting on Moon as it orbits the Earth, assuming a circular orbit and an orbital speed of 1.02 × 10^3 meters per second. [Show all work, including the equation and substitution with units.]

    <p>The centripetal force acting on the Moon is calculated using the formula: F = mv^2/r. Where: F is the force (in Newtons), m is the mass of the Moon (7.35 x 10^22 kg), v is the orbital velocity (1.02 x 10^3 m/s), and r is the radius of the Moon's orbit around the Earth (3.84 x 10^8 m). Plugging in the values into the equation, we get: F = (7.35 x 10^22 kg)*(1.02 x 10^3 m/s)^2 / (3.84 x 10^8 m) F = 2.06 x 10^20 N</p> Signup and view all the answers

    Base your answer(s) to the following question(s) on the information given below. Friction provides the centripetal force that allows a car to round a circular curve. Find the minimum coefficient of friction needed between the tires and the road to allow a 1600-kilogram car to round a curve of radius 80. meters at a speed of 20. meters per second. [Show all work, including formulas and substitutions with units.]

    <p>The centripetal force needed to keep the car on the curve is: F = (1600 kg)*(20 m/s)^2 / 80 m = 8000N. The minimum coefficient of friction, μ, is calculated using the formula: μ = (F / mg ), where m is the mass of the car (1600 kg), g is the acceleration due to gravity (9.8 m/s^2). So, μ = 8000N / (1600 kg * 9.8 m/s^2) = 0.51. This means that a coefficient of friction of at least 0.51 is required for the car to round the curve safely.</p> Signup and view all the answers

    If the mass of the car were increased, how would that affect the maximum speed at which it could round the curve?

    <p>remain the same</p> Signup and view all the answers

    Study Notes

    Centripetal Motion

    • Centripetal acceleration is the change in direction of an object moving in a circular path, not the change in speed.
    • An object in uniform circular motion experiences a centripetal acceleration directed towards the center of the circle, changing its velocity.
    • The magnitude of centripetal acceleration (ac) is calculated using the formula: ac = v2/r, where v is the speed and r is the radius of the circular path.
    • The greater the speed, the greater the centripetal acceleration.
    • The greater the radius, the smaller the centripetal acceleration.
    • The centripetal force (Fc) is the force that causes the change in direction of the object.
    • Fc = mac, where m is the mass of the object.
    • The centripetal force is a net force, and it is always directed towards the center of the circular path.
    • If the string holding a rotating object breaks, the object will move in a straight line tangential to the circle.
    • The tangential velocity is constant in uniform circular motion.
    • Centripetal acceleration remains constant in uniform circular motion.
    • Period does not affect any force in centripetal motion, but is correlated to speed.
    • The direction of the constant centripetal acceleration is always directed toward the center of the circular path.
    • An object moving in a uniform circular motion has a constant speed, a changing velocity, consistent centripetal acceleration, and a continuous force directed towards the center of the circle.

    Examples of Calculations

    • Example 1: A 1.0 kg mass travels at 8.0 m/s in a 4.0 m radius circle. What is the centripetal acceleration?
      • ac = v2/r = (8.0 m/s)2 / (4.0 m) = 16 m/s2
    • Example 2: A 10.0 kg mass travels at a constant speed of 4.0 m/s around a 4.0 m radius circle. What is the centripetal acceleration?
      • ac = (4.0 m/s)2 / (4.0 m) = 4m/s2
    • Example 3: What is the minimum friction needed so a 1200 kg car can move around a curve of 25 m radius with a speed of 9.0 m/s ?
      • Centripetal force = 1200kg ✕ (9.0m/s)2 / 25m = 4.6 ×103N
      • Friction force = Centripetal force to stop the car from slipping or sliding on the horizontal path., which is approximately 4600N

    Studying That Suits You

    Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

    Quiz Team

    Related Documents

    Description

    Test your understanding of centripetal motion and acceleration in circular paths. This quiz covers the definitions, formulas, and concepts related to centripetal acceleration and force. See how well you grasp the relationships between speed, radius, and the forces at play in circular motion.

    More Like This

    Physics: Circular Motion and Centripetal Force
    12 questions
    Centripetal Motion Practice Problems
    25 questions
    Centripetal Motion Concepts
    8 questions
    Use Quizgecko on...
    Browser
    Browser