Questions and Answers
A fruit vendor sells fruits at 15% discount on all fruits. If the marked price of a fruit is ₹120, what is the cost price of the fruit?
A student got 420 marks out of 600 in an examination. What is the percentage of marks obtained by the student?
A shopkeeper marks his goods at 25% above the cost price. If he sells the goods at 10% discount, what is the profit percentage?
What percentage of 120 is 24?
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If 15% of x is 24, what is the value of x?
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Study Notes
Percentage Calculations
- To find what percentage of 120 is 24, use the formula: (Part/Whole) × 100. Therefore, (24/120) × 100 = 20%. So, 24 is 20% of 120.
Discount and Cost Price
- A fruit vendor offers a 15% discount on all fruits.
- For a fruit with a marked price of ₹120, the selling price after discount is calculated as: Selling Price = Marked Price - (Discount × Marked Price) = ₹120 - (0.15 × ₹120) = ₹102.
- To find the cost price (CP), if needed, we need additional information about profit margins or other costs.
Exam Performance Percentage
- A student scored 420 out of a total of 600 marks.
- The percentage of marks is calculated as: (Obtained Marks/Total Marks) × 100 = (420/600) × 100 = 70%.
- Thus, the student obtained 70% marks in the examination.
Profit Calculation
- A shopkeeper marks his goods 25% above the cost price (CP).
- If CP is denoted as CP, then the marked price (MP) becomes: MP = CP + (0.25 × CP) = 1.25 × CP.
- The shopkeeper sells the goods at a 10% discount: Selling Price (SP) = MP - (10% of MP) = MP - (0.10 × MP) = 0.90 × MP.
- Profit percentage can be derived from the selling price and cost price using: Profit Percentage = [(SP - CP)/CP] × 100.
Value of x from Percentage
- If 15% of x is equal to 24, the equation can be expressed as: 0.15 × x = 24.
- To find x, rearrange the equation: x = 24 / 0.15 = 160. Thus, the value of x is 160.
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Description
This quiz covers concepts of percentage, discount, and profit in Comparing Quantities chapter of CBSE Math. Test your understanding of percentage calculations and application problems.