Catalase and Hydrogen Peroxide Experiment

Experiment Overview: Catalase and Hydrogen Peroxide

• Catalase speeds up the breakdown of hydrogen peroxide into water and oxygen.
• The purpose of the experiment is to determine if plant tissue contains catalase.
• Test tube 1 contains hydrogen peroxide and fresh (living) plant tissue.
• Test tube 2 contains hydrogen peroxide and boiled (dead) plant tissue.
• Hydrogen peroxide breaks down into water and oxygen gas.
• Oxygen gas is the product being measured.
• In test tube 1, the plant tissue contains catalase
• In test tube 2, the boiled tissue's catalase is denatured due to high temperature.
• Boiling the tissue is like not adding catalase.
• The expected result is bubbles in test tube 1, and no bubbles in test tube 2.

Analyzing Question 3

• Question 3 notes that a lot of gas bubbles were released in test tube 1, but not in test tube 2.
• To conclude plant tissue contains catalase, the gas must be identified as oxygen.
• According to the text, knowing there is a product being release confirms that the reaction is occurring.
• Setting up a tube with water and fresh plant tissues is also necessary.
• This will address concerns that the plant tissue releases oxygen regardless of the hydrogen peroxide.
• Removing the substrate determines if the fresh plant tissues release oxygen on their own.
• Setting up a tube containing hydrogen peroxide but no plant issue is not an additional step.
• This is because test tube 2 already uses boiled tissue, where the catalase is denatured.
• This is like adding nothing, making it a repeated step.

Analyzing Question 4

• Question 4 describes gas bubbles stopping in test tube 1, additional hydrogen peroxide is added, and gas bubbles start again
• It indicates the catalase is reusable
• The catalase remains unchanged after the reaction, and restarts when more substrate is added.

Analyzing Questions 5 and 6

• Two boiling tubes are put in a 25°C water bath for 10 minutes, one with hydrogen peroxide, and one with catalase solution.
• After 10 minutes, the contents are mixed and maintained at the same temperature.
• Measurement is taken of the amount of oxygen released over 5 minutes, and the data is graphed.
• Focus should be on the accumulative amount of oxygen.
• The red line of the graph represents the accumulative amount of oxygen reaches its maximum level, meaning the reaction is finished.
• The reaction stops at the point where the accumulative amount of oxygen reaches its maximum level.
• This happens at the third minute.
• Reaction rate is determined by the slope of the line.
• The substrate has been used up, so no more oxygen is produced.

Analyzing Question 6

• The same experiment is repeated, but kept at 35°C.
• Substrate concentration does not change.
• The amount of final product will not change.
• MSI concentration is same, so will not produce more product.
• The maximum level will be limited.
• The maximum level is reached earlier.
• Higher temperature gives higher kinetic energy for the enzymes to collide with the substrate to produce products faster

Analyzing Question 7

• Focus on the shape of the enzyme molecules
• Enzymes are reusable and specific
• State one property of MIT and explain it using figure 2
• MSI is reusable because it remains unchanged after the reaction.
• The active site is specific because only the substances R and S can fit into this shape to form an enzyme-substrate compress.
• Draw three lines on the graph: one horizontal at the maximum level, and two vertical.
• Maximum level indicates reaction completeness.
• With Chemical X, it takes a shorter time to reach the Max, and if added takes longer.

Analyzing Questions 7P1 and 7P2

• Chemical X slows down the synthesis of substance you or inhibits it.
• Quote evidence from the graph.
• The time taken for the conversion to complete was longer when chemical X was added.
• Chemical X is a drug that inhibits M sigh T.
• No substance you, no protein.
• Protein is very important for growth and repair and making some and bring for making em sigh.
• If enzyme is inhibited, chemical X can be used as a truck and slow the growth of the bacteria.

Analyzing Question 8

• This experiment is about running away a kind of protease.
• Protease is acting on protein.
• At a describe the pattern in the results, write a general tendency of the result shown in the table, or you get higher cutting edge shows idea.
• As temperature increases, the time for me to crowd decreases and then increases again.
• For Part B and C is a little bit easier for puppy.
• It asks for the optimum temperature, should be 40 degrees Celsius based on the result shown in the table, just based on the result, don't need to use your test poll.
• At 70 degree Celsius, there is no reaction because the M's I are the nature, or you can say that the active side of the enzyme molecules change shape.

Analyzing Question 10

• Is about another kind of protease catalyze the breakdown of protein.
• The experiment is talking about we prepare a protein by mixing a milk powder with the distributor to get a right cloudy suspension.
• Add the protease to the suspension and then probably if the enzyme it can really work it will change the protein from right and County to become colorless rate that means clear in the inner question is a clear.
• Protein is broken down into amino acid and the basic unit is amino acid.

Analyzing Questions 10 A and B.

• 10A: Protein can be broken down and from bright and country to become clear, because the insoluble proteins are broken down into products amino axis hey.
• 10B1: What you need to know is that or by increasing the pH, so what will be the effect on the activity of tribe seed.
• Increase the pH, the time taken for suspension to become clear becomes shorter.
• PH 8 the tribe scene is most active and between pH 5 and ph8 the activity of traffic increases.- Time taken indicates enzyme activity and heightened demand for a job.
• Increased demand may indicate a change in the M cycle.
• When analyzing enzyme activity, avoid relying solely on one parameter.

pH and Enzyme Activity

• Unsuitable pH can break bonds within enzyme molecules, specifically the bonds between amino acids that form proteins.
• Conformational changes occur at the active site of the enzyme due to unsuitable pH.
• The substrate and enzyme active site cannot combine to form the enzyme-substrate complex if bonds are disrupted.

The Importance of Water Bath

• Maintaining a constant temperature of 45 degrees Celsius in the experiment ensures temperature remains a controlled variable.
• The question in the assignment explanation specifically aimed to test why the water bath was important and not why the enzyme works best at 45 degrees Celsius.