Calculus Derivatives and Decreasing Intervals Quiz

$f'(x) = -6x + 7 - \frac{1}{x^2}$ (correct)

$f'(x) = -6x + 7 + \frac{1}{x}$

$f'(x) = -6x + 7 + \frac{1}{x^2}$

$f'(x) = -6x + 7 - \frac{1}{x}$

$f'(x) = -4(\cos(x) + 2x)(x^3 - 5)^3\sin(x) + 4(\cos(x) + 2x)3(x^3 - 5)^4$

$f'(x) = -4(\cos(x) + 2x)(x^3 - 5)^3\sin(x) + (\cos(x) + 2x)3(x^3 - 5)^4$

$f'(x) = -4(\cos(x) + 2x)(x^3 - 5)^3\sin(x) + 4(\cos(x) + 2x)(x^3 - 5)^4$ (correct)

$f'(x) = -4(\cos(x) + 2x)(x^3 - 5)^3\sin(x) + (\cos(x) + 2x)3(x^3 - 5)^3$

$f'(x) = -2\sin(2x)x^4 + 4x^3$ (correct)

$f'(x) = -2\sin(2x)x^4 - 8x^3$

$f'(x) = -2\sin(2x)x^3 - 8x^3$

$f'(x) = -2\sin(2x)x^3 + 4x^3$