Calculus AB - Section II, Part B

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Questions and Answers

What is the first step in finding dy/dx for the curve defined by $6x^2 + 3xy + 2y^2 + 17y = 96$?

  • Isolate y on one side of the equation
  • Differentiate both sides with respect to x (correct)
  • Complete the square for the equation
  • Evaluate the equation at specific points

At the point (4,0), what is the slope of the tangent line to the curve $6x^2 + 3xy + 2y^2 + 17y = 96$?

  • 0
  • -1
  • 2 (correct)
  • 3

What is the purpose of using the tangent line to approximate the value of k at the point (3.8, k)?

  • To create an estimate of k based on nearby values (correct)
  • To determine the slope of the curve at that point
  • To simplify the computation of k
  • To find the exact value of k

Which of the following statements about the function g(x) = x·f(x) is true regarding the closed interval [-1, 5]?

<p>g(2) represents a local minimum (D)</p> Signup and view all the answers

According to the Intermediate Value Theorem, what can be concluded about g(x) in the interval (1, 3)?

<p>g(x) must be continuous and equal to -2 at some point (C)</p> Signup and view all the answers

What is the expression for dy/dx at the point (4,0) for the curve defined by $6x^2 + 3xy + 2y^2 + 17y = 96$?

<p>The expression for dy/dx at the point (4,0) is $dy/dx = -\frac{9}{16}$.</p> Signup and view all the answers

What is the equation of the tangent line to the curve at the point (4,0)?

<p>The equation of the tangent line is $y = -\frac{9}{16}(x - 4)$.</p> Signup and view all the answers

Using the tangent line approximation, what is the estimated value of k for the point (3.8,k)?

<p>The estimated value of k is $-\frac{9}{16}(3.8 - 4) \approx -1.2$.</p> Signup and view all the answers

What equation can be solved to find the actual value of k such that the point (3.8,k) is on the curve?

<p>The equation to solve is $6(3.8)^2 + 3(3.8)(k) + 2(k)^2 + 17(k) = 96$.</p> Signup and view all the answers

What can be deduced about g(x) concerning the value -2 based on the Intermediate Value Theorem within the interval (1, 3)?

<p>The Intermediate Value Theorem indicates that there exists at least one x in (1, 3) such that $g(x) = -2$.</p> Signup and view all the answers

Flashcards

Tangent Line Equation

The equation of the line that touches a curve at a single point, representing the instantaneous rate of change at that point.

Implicit Differentiation

A technique for finding the derivative of a function when the function isn't explicitly defined as y = f(x).

Average Rate of Change

The overall change in a function over an interval divided by the length of the interval.

Intermediate Value Theorem

If a function is continuous on a closed interval and takes on two values, it must also take on every value in between.

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Inverse Function Derivative

The derivative of the inverse function at a point is the reciprocal of the derivative of the original function at the corresponding point on the inverse function's graph.

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Tangent Line Equation

The equation of a line that touches a curve at a single point.

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Implicit Differentiation

Finding a derivative when the function isn't written as y=f(x).

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Average Rate of Change of g(x)

Overall change in g(x) over an interval, divided by the interval length.

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Intermediate Value Theorem

If a continuous function takes on two values in an interval, it must also take on all values between.

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Inverse Function Derivative, h’(-2)

Derivative of the inverse function at a point, related to the derivative of the original function.

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Study Notes

Calculus AB - Section II, Part B

  • Calculator not allowed for this part
  • Show all work and justify answers

Problem 1

  • Curve equation: 6x² + 3xy + 2y² + 17y = 96
  • Part (a): Find the derivative dy/dx
  • Part (b): Find the equation of the tangent line at (4,0)
  • Part (c): Use the tangent line to approximate k for point (3.8,k) on the curve.
  • Part (d): Find the actual value of k so that (3.8,k) is on the curve (equation)

Problem 2

  • Graph of f(x) given for the closed interval -1 ≤ x ≤ 5
  • Horizontal tangents: at x = 1, x = 3
  • f’(2) = -2
  • Part (a): g(x) = x * f(x). Find the equation of the tangent line at x = 2 for g(x)
  • Part (b): Find the average rate of change of g(x) for -1 ≤ x ≤ 5
  • Part (c): Show that g(x) = -2 on the interval 1 < x ≤ 3 using the Intermediate Value Theorem
  • Part (d): h(x) is the inverse of g(x). Find h’(-2)

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