Calculus AB - Section II, Part B
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Questions and Answers

What is the first step in finding dy/dx for the curve defined by $6x^2 + 3xy + 2y^2 + 17y = 96$?

  • Isolate y on one side of the equation
  • Differentiate both sides with respect to x (correct)
  • Complete the square for the equation
  • Evaluate the equation at specific points
  • At the point (4,0), what is the slope of the tangent line to the curve $6x^2 + 3xy + 2y^2 + 17y = 96$?

  • 0
  • -1
  • 2 (correct)
  • 3
  • What is the purpose of using the tangent line to approximate the value of k at the point (3.8, k)?

  • To create an estimate of k based on nearby values (correct)
  • To determine the slope of the curve at that point
  • To simplify the computation of k
  • To find the exact value of k
  • Which of the following statements about the function g(x) = x·f(x) is true regarding the closed interval [-1, 5]?

    <p>g(2) represents a local minimum</p> Signup and view all the answers

    According to the Intermediate Value Theorem, what can be concluded about g(x) in the interval (1, 3)?

    <p>g(x) must be continuous and equal to -2 at some point</p> Signup and view all the answers

    What is the expression for dy/dx at the point (4,0) for the curve defined by $6x^2 + 3xy + 2y^2 + 17y = 96$?

    <p>The expression for dy/dx at the point (4,0) is $dy/dx = -\frac{9}{16}$.</p> Signup and view all the answers

    What is the equation of the tangent line to the curve at the point (4,0)?

    <p>The equation of the tangent line is $y = -\frac{9}{16}(x - 4)$.</p> Signup and view all the answers

    Using the tangent line approximation, what is the estimated value of k for the point (3.8,k)?

    <p>The estimated value of k is $-\frac{9}{16}(3.8 - 4) \approx -1.2$.</p> Signup and view all the answers

    What equation can be solved to find the actual value of k such that the point (3.8,k) is on the curve?

    <p>The equation to solve is $6(3.8)^2 + 3(3.8)(k) + 2(k)^2 + 17(k) = 96$.</p> Signup and view all the answers

    What can be deduced about g(x) concerning the value -2 based on the Intermediate Value Theorem within the interval (1, 3)?

    <p>The Intermediate Value Theorem indicates that there exists at least one x in (1, 3) such that $g(x) = -2$.</p> Signup and view all the answers

    Study Notes

    Calculus AB - Section II, Part B

    • Calculator not allowed for this part
    • Show all work and justify answers

    Problem 1

    • Curve equation: 6x² + 3xy + 2y² + 17y = 96
    • Part (a): Find the derivative dy/dx
    • Part (b): Find the equation of the tangent line at (4,0)
    • Part (c): Use the tangent line to approximate k for point (3.8,k) on the curve.
    • Part (d): Find the actual value of k so that (3.8,k) is on the curve (equation)

    Problem 2

    • Graph of f(x) given for the closed interval -1 ≤ x ≤ 5
    • Horizontal tangents: at x = 1, x = 3
    • f’(2) = -2
    • Part (a): g(x) = x * f(x). Find the equation of the tangent line at x = 2 for g(x)
    • Part (b): Find the average rate of change of g(x) for -1 ≤ x ≤ 5
    • Part (c): Show that g(x) = -2 on the interval 1 < x ≤ 3 using the Intermediate Value Theorem
    • Part (d): h(x) is the inverse of g(x). Find h’(-2)

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    Description

    This quiz focuses on derivatives, tangent lines, and approximation techniques using the calculus concepts taught in Calculus AB. It includes tasks of finding derivatives, tangent lines, and applying the Intermediate Value Theorem. Solve specific problems on a given curve and investigate properties of functions over a closed interval.

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