Calculating Work and Kinetic Energy

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Questions and Answers

What condition must be met for a force to do work on an object?

  • The force must be greater than the object's weight.
  • The force must be applied constantly.
  • The force must cause a displacement of the object. (correct)
  • The force must be applied at an angle to the horizontal.

What is the SI unit of work?

  • Newton
  • Kilogram
  • Joule (correct)
  • Watt

A person applies a horizontal force of 50 N to push a box across a floor. If the work done by the person is 200 J, what distance did the box move?

  • 25 m
  • 2 m
  • 4 m (correct)
  • 10 m

A crane lifts a $1000 \text{ kg}$ car vertically upward at a constant speed of $2 \text{ m/s}$. What is the net work done on the car after it has been lifted $5 \text{ m}$?

<p>$0 \text{ J}$ (D)</p> Signup and view all the answers

What is the work-energy theorem?

<p>Net work is equal to the change in kinetic energy of the object. (A)</p> Signup and view all the answers

An object of mass $2 \text{ kg}$ initially moving at $3 \text{ m/s}$ has $16 \text{ J}$ of work done on it. What is its final speed?

<p>$5 \text{ m/s}$ (A)</p> Signup and view all the answers

Under what condition is work considered positive?

<p>When it is adding energy to the object. (D)</p> Signup and view all the answers

A box is pushed with a force of $10 \text{ N}$ across a frictionless surface for a distance of $5 \text{ m}$. What is the work done?

<p>$50 \text{ J}$ (B)</p> Signup and view all the answers

Which scenario describes negative work being done?

<p>A car braking to a stop. (B)</p> Signup and view all the answers

What does power measure?

<p>The rate at which work is done. (A)</p> Signup and view all the answers

If a machine does $500 \text{ J}$ of work in $10 \text{ seconds}$, what is its power output?

<p>$50 \text{ W}$ (C)</p> Signup and view all the answers

How does reducing the time to complete the same amount of work affect the power required?

<p>Increases the power. (B)</p> Signup and view all the answers

A $60 \text{ kg}$ student runs up a $5.0 \text{ m}$ high staircase in $3.9 \text{ seconds}$. What is the student's power output?

<p>$750 \text{ W}$ (A)</p> Signup and view all the answers

What best describes the relationship between work and power?

<p>Power is the rate of doing work. (C)</p> Signup and view all the answers

How does using a pulley system change the amount of work required to lift an object?

<p>It keeps the amount of work the same. (A)</p> Signup and view all the answers

A machine is used to lift a heavy object. Which of the following statements is always true?

<p>The machine makes the work easier by changing the amount of force or distance. (D)</p> Signup and view all the answers

When is it beneficial to use switchbacks to ascend a mountain?

<p>To ascend with a smaller force over a longer distance. (B)</p> Signup and view all the answers

A horizontal force of $30 \text{ N}$ is used to slide a $10 \text{ kg}$ box across a floor at a constant speed for a distance of $3 \text{ m}$. What is the work done by the frictional force?

<p>$-90 \text{ J}$ (B)</p> Signup and view all the answers

A $2 \text{ kg}$ ball is dropped from a height of $20.4 \text{ m}$. Calculate the final speed when it hits the ground. (Assume no air resistance, $g = 9.8 \text{ m/s}^2$).

<p>$20 \text{ m/s}$ (A)</p> Signup and view all the answers

Which of the following is an example of a situation where no work is done on an object?

<p>Pushing a stationary car. (D)</p> Signup and view all the answers

A machine has a power output of $100 \text{ W}$. How long would it take for this machine to perform $500 \text{ J}$ of work?

<p>$5 \text{ s}$ (C)</p> Signup and view all the answers

A hiker climbs a hill. Which statement is most accurate?

<p>The work will be same but the power will be different on different paths. (D)</p> Signup and view all the answers

A $1000 \text{ kg}$ car accelerates from rest to a speed of $20 \text{ m/s}$ over a distance of $200 \text{ m}$ on a level surface. What is the minimum average power that the engine must supply?

<p>$10000 \text{ W}$ (C)</p> Signup and view all the answers

A block is pulled across a rough surface at a constant speed by a force of $40 \text{ N}$. If the power of the force is $200 \text{ W}$, what is the speed of the block?

<p>$5 \text{ m/s}$ (C)</p> Signup and view all the answers

Which of the following actions requires more power?

<p>Lifting a $20 \text{ kg}$ box to a height of $2 \text{ m}$ in $5 \text{ seconds}$ (A)</p> Signup and view all the answers

A $2000 \text{ kg}$ elevator ascends $25 \text{ m}$ at a constant speed. How much work is done on the elevator by the lifting force?

<p>$490000 \text{ J}$ (D)</p> Signup and view all the answers

Why does it require more power for a helicopter to both hover and gain altitude, versus only hovering?

<p>The same amount of force and a greater rate of doing work. (C)</p> Signup and view all the answers

Flashcards

What is 'Work'?

Transfer of energy when a force causes an object to move.

Work Equation

Force multiplied by the distance over which it acts (W = Fd).

What are Joules?

The standard unit of work, equivalent to one Newton-meter.

Work Kinetic Energy Theorem

Net work equals the change in kinetic energy of an object.

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What is Power?

The rate at which work is done.

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What are Watts?

The unit of power, equivalent to one joule per second.

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Ramps and work

Using switchbacks does not reduce work, but it reduces the force required.

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Kinetic Energy equation

KE = 1/2mv^2

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Potential Energy equation

PE=mgh

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Study Notes

Work

  • Work is a transfer of energy
  • Work occurs when a force causes an object to move
  • Work requires the application of force and movement of something

Calculating Work

  • Work is calculated using the formula: W = Fd
  • W represents work
  • F represents force
  • d represents distance
  • Work is measured in Joules (J), equivalent to Newton-meters (N m)

Example

  • To calculate the work done when Mrs. Kreamer applies a force of 20 N to push Wesley in his stroller for 0.4 km, convert 0.4 km to 400 m
  • The work done is calculated as: W = (20 N) * (400 m) = 8000 J
  • Another example of calculating work is: lawnmower pushed with constance force of 100N. if the mower moves a distance of 10 m work done is: W = (100N) * (10m) = 1000J

Work Kinetic Energy Theorem

  • Net work equals the change in kinetic energy (KE) of the object and is expressed as: Wnet = ΔKE
  • Initial Energy + Work = Final Energy
  • Work is positive when adding energy
  • Work is negative when losing energy

Work Kinetic Energy Formula Expanded

  • Wnet = ΔE
  • Wnet = (1/2)mvf^2 - (1/2)mvi^2
  • vf represents final velocity
  • vi represents initial velocity
  • m represents mass

Applying the Work-Energy Theorem

  • To find the height a 1 kg football needs to fall from rest to reach a speed of 20 m/s, apply the work-energy theorem
  • W = ΔKE
  • Fd = (1/2)mv^2 - (1/2)mv^2
  • mad = (1/2)mv^2 - (1/2)mv^2
  • (1)(9.8)d = (1/2)(1)20^2 - (1/2)(1)0
  • Solve for d: 9.8d = 200, so d = 20.4 meters

Identifying Forces Doing Work

  • A 10-N frictional force slows a moving block to a stop after a displacement of 5.0 m to the right
  • Consider a 2-kg object sliding at constant speed across a friction-free surface for 5 m to the right
  • Consider a 2-kg object pulled upward at a constant speed by a 20-N force for a vertical displacement of 5 m
  • A 10-N force is applied to push a block across a frictional surface at a constant speed for 5.0 m to the right

Power

  • Power refers to the work done over time and is measured in Watts
  • One Watt (W) is equivalent to one Joule per second (1 J/1s)
  • The formula for power is P = W/t
  • P represents power
  • W represents work
  • t represents time

Calculating Power

  • To determine the power of a tired squirrel (1 kg) doing push-ups by elevating its center-of-mass by 5 cm (0.05 m) in 2 seconds:
  • Work done = force x distance = (1 kg * 9.8 m/s^2) * 0.05 m = 0.49 J
  • Power = work / time = 0.49 J / 2 s = 0.245 Watts
  • When a Marine lifts a 65.0-kg body a distance of 0.25 meters in 2 seconds, the power delivered is:
  • P = W/t
  • P = Fd/t
  • P = [(65)(9.8)(.25)] / 2
  • P = 79.6 watts

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