Calculating Electric Field for Continuously Distributed Charges
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Questions and Answers

What does the small amount of charge in the text give rise to?

  • Magnetic field
  • Gravitational field
  • Electric field (correct)
  • Heat field
  • Which component of the electric field is non-cancelling in the -axis due to symmetry?

  • x component
  • y component
  • No component is non-cancelling
  • z component (correct)
  • What is the dependency of arc length on and according to the text?

  • No dependence (correct)
  • Inverse dependence
  • Exponential dependence
  • Linear dependence
  • What distribution of charges is considered along a wire in the text?

    <p>Continuous distribution</p> Signup and view all the answers

    What mathematical technique is used to solve the integral mentioned in the text?

    <p>Trigonometric substitution</p> Signup and view all the answers

    Which axis could have been taken instead of the y axis for calculating the distance from the wire?

    <p>-x axis</p> Signup and view all the answers

    How do we calculate the electric field when charges are continuously distributed over a region?

    <p>By breaking up the region into small pieces and treating each piece as a point charge</p> Signup and view all the answers

    How can the total electric field be expressed when charges are continuously distributed?

    <p>As an integral over the region where charges are distributed</p> Signup and view all the answers

    What is charge density used for when dealing with continuously distributed charges?

    <p>To specify the amount of charge per unit volume, area, or length in the region</p> Signup and view all the answers

    How is linear charge distribution defined?

    <p>Using charge density lambda (λ)</p> Signup and view all the answers

    For which type of charge distribution is surface charge density sigma (σ) defined?

    <p>Surface charge distribution</p> Signup and view all the answers

    How do we work out the electric field coming from a continuous charge distribution?

    <p>By integrating over the charge distribution region</p> Signup and view all the answers

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