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Questions and Answers
What is the value of the charge (q) provided in the solution?
What is the value of the charge (q) provided in the solution?
- 8.0 x 10^-8 C
- -8.0 x 10^-8 C (correct)
- -8.0 x 10^8 C
- 8.0 x 10^8 C
What is the radius (r) mentioned in the solution?
What is the radius (r) mentioned in the solution?
- 5 m
- 5 cm (correct)
- 5 mm
- 5 km
According to the formula given in the text, what is the expression for calculating electric field (E)?
According to the formula given in the text, what is the expression for calculating electric field (E)?
- $E = k \frac{q}{r^2}$ (correct)
- $E = k \frac{q}{r}$
- $E = \frac{1}{4\pi \epsilon_0} \frac{q}{r^2}$
- $E = \frac{q}{r}$
What is the calculated value of the electric field (E) due to the charge in the solution?
What is the calculated value of the electric field (E) due to the charge in the solution?
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If the radius (r) was doubled, what would be the effect on the electric field (E) according to the formula provided?
If the radius (r) was doubled, what would be the effect on the electric field (E) according to the formula provided?
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