5 Questions
What is the value of the charge (q) provided in the solution?
-8.0 x 10^-8 C
What is the radius (r) mentioned in the solution?
5 cm
According to the formula given in the text, what is the expression for calculating electric field (E)?
$E = k \frac{q}{r^2}$
What is the calculated value of the electric field (E) due to the charge in the solution?
-2.88 x 10^5 N/C
If the radius (r) was doubled, what would be the effect on the electric field (E) according to the formula provided?
E would be halved
Learn how to calculate the electric field created by a specific charge at a given distance. In this example, the electric field due to a charge of -8.0x10^-8 C at a distance of 5 cm is calculated using the formula E = 9x10^9 x q / r^2.
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