Calculate Electric Field Due to a Charge
5 Questions
1 Views

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

What is the value of the charge (q) provided in the solution?

  • 8.0 x 10^-8 C
  • -8.0 x 10^-8 C (correct)
  • -8.0 x 10^8 C
  • 8.0 x 10^8 C

    • What is the radius (r) mentioned in the solution?

  • 5 m
  • 5 cm (correct)
  • 5 mm
  • 5 km

    • According to the formula given in the text, what is the expression for calculating electric field (E)?

  • $E = k \frac{q}{r^2}$ (correct)
  • $E = k \frac{q}{r}$
  • $E = \frac{1}{4\pi \epsilon_0} \frac{q}{r^2}$
  • $E = \frac{q}{r}$

    • What is the calculated value of the electric field (E) due to the charge in the solution?

    <p>-2.88 x 10^5 N/C</p> Signup and view all the answers

    If the radius (r) was doubled, what would be the effect on the electric field (E) according to the formula provided?

    <p>E would be halved</p> Signup and view all the answers

    More Like This

    Use Quizgecko on...
    Browser
    Open
    Browser
    Browser