Business Expansion Decision-Making Quiz
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Questions and Answers

Which of the following transformations can be used to assign a very high risk value to the potential risk variable?

  • Linear feature scaling: $N(t) = rac{t - min}{max - min}$
  • No transformation needed
  • Negation: $N(t) = 1 - t$ (correct)
  • Negation followed by scaling: $N(t) = 25000 - t$

    • Which of the following transformations can be used to assign an easily able value to the capability variable?

  • Linear feature scaling: $N(t) = rac{t - min}{max - min}$
  • No transformation needed
  • Negation: $N(t) = 1 - t$ (correct)
  • Negation followed by scaling: $N(t) = 25000 - t$

    • Which of the following transformations can be used to assign a range of 0 to 1 to the potential profit variable?

  • Linear feature scaling: $N(t) = rac{t - min}{max - min}$
  • Negation: $N(t) = 1 - t$
  • Negation followed by scaling: $N(t) = 25000 - t$
  • No transformation needed (correct)

    • Which of the following transformations is NOT needed for any of the three variables?

    <p>No transformation needed</p> Signup and view all the answers

    Which of the following transformations could be appropriate for transforming the data so that it ranges over the unit interval and can be used with averaging aggregation functions?

    <p>Scale to the unit interval. Use the formula $x' = \frac{x - \text{min}(x)},{\text{max}(x) - \text{min}(x)}$</p> Signup and view all the answers

    Which of the following transformations could be used to assign a range of 0 to 1 to the potential profit variable?

    <p>Scale to the unit interval. Use the formula $x' = \frac{x - \text{min}(x)},{\text{max}(x) - \text{min}(x)}$</p> Signup and view all the answers

    Which of the following transformations could be used to assign a very high risk value to the potential risk variable?

    <p>Use a negation and linear feature scaling, $x' = -\frac{x - \text{min}(x)},{\text{max}(x) - \text{min}(x)}$</p> Signup and view all the answers

    Which of the following transformations is NOT needed for any of the three variables?

    <p>Use a log transformation, $x' = \ln(x)$</p> Signup and view all the answers

    Which of the following transformations could be used to scale the potential profit variable from 0 to 1?

    <p>Scale to the unit interval. Use the formula $x' = \frac{x - \text{min}(x)},{\text{max}(x) - \text{min}(x)}$</p> Signup and view all the answers

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