Zaira - Maths Equations Test 01

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Flashcards

What is BODMAS?

BODMAS is an acronym that defines the order of operations in mathematical expressions.

Brackets (B)

Calculations inside brackets are always performed first.

Orders (O)

Orders refer to powers or roots.

Division and Multiplication (DM)

Carry out both division and multiplication from left to right.

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Addition and Subtraction (AS)

Perform both addition and subtraction from left to right.

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Solving with brackets example

To solve: 7 × (8 – 3), compute 8-3 first.

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Multiplication before Addition

In 7 + 9 × 2, perform multiplication before addition.

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Division before Subtraction

In 10 – 9 ÷ 3, perform division before subtraction.

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Why solve parenthesis first?

Parenthesis must be evaluated before any other operations.

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BODMAS within Parenthesis

Terms within the parenthesis must follow BODMAS.

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No Parenthesis

When no parenthesis are present, multiplication and division take precedence over addition and subtraction.

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Same Priority Operations

When operations are of equal priority, solve from left to right.

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Solve: (12+8) ÷ 4

Evaluate brackets: (12 + 8) ÷ 4 = 20 ÷ 4 = 5.

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Solve: 4 × 6 – 14

Multiply before subtracting: 4 × 6 – 14 = 24 – 14 = 10

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Solve 8 × 3 + 6

Divide before adding: 8 × 3 + 6 = 24 + 6 = 30

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Solve: 3 × (15 – 9)

Solve the values within the parethensis: 3 × (15 – 9) = 3 x 6 = 18

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Solve: 6³ – (35 + 12)

If there are exponents you must evaluate the exponent first.

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Solve: 4 × – 25 = 23

Solve the equation within parenthesis before carrying out the multiplying: 4 × 12 – 25 = 23. 4 x 12 = 48. 48 - 25 = 23. The missing number is: 12

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Solve: (26 – 10) ÷ =4

Isolate the dividened: (26 – 10) ÷ 4 =4. The missing number is 4.

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Solve: 7 + 8 × 9 – 4

If performing multiple operations, remember to use BODMAS to identify the order you complete the equation.

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Solve: (19 – 7) + 82 + 9

Solve (19 – 7) + 82 + 9. = 12 + 82 + 9 = 94 + 9 = 103

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60 = 5 × (3 + )

If there is a missing number, and numbers on both sidse of the equation, preform algebraic manipulation to isolate for the unknown.

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Solve: (3 + 6) × (8 – 5)

Evaluate expression inside the parenthesis first (3 + 6) = 9 and (8 – 5) = 3, then multiply: 9 x 3 = 27

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Solve 7 + 8 × 9 – 4

Multiply 8 and 9 first: 7 + (8 × 9) – 4 = 7 + 72 - 4 = 75

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Solve: 8 × (6 + 3) + 5

Evaluate inside of parenthesis first, then multiply: 8 × (6 + 3) + 5 = 8 x 9 + 5 = 77

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Solve: 23 – 3 × (5 + 8)

Multiply 8 and 9 first: 23 – 3 × (5 + 8) = 23 – 3 x 13 = -16

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Solve: 8 + 7 × (12 – 5)

Evaluate 7 x (12 – 5) first: 8 + 7 × (12 – 5) = 8 + 7 x 7 = 57

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6 × 7 – 4 × 8 = 10

6 × 7 – 4 × 8 = 10. (6 x 7) - (4 x 8) = 42 - 32 = 10. No brackets are needed here!

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9 × 7 – 6 × 3 = 27

9 × 7 – 6 × 3 = 27. 9 × (7 – 6) × 3 = 27. 9 x 1 x 3 = 27.

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5 + 11 ÷ 7 – 3 = 4

5 + 11 ÷ 7 – 3 = 4 results in (5 + 11) ÷ (7 – 3) = 4

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Multiple card calculations.

Remember that all combinations of number cards may result in multiple answers.

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Define Orders within BODMAS.

Order is the second operation to complete within BODMAS, orders refers to raising to the power, or finding the root of an integer.

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Division and Multiplication rule.

Division and Multiplication are of equal importance so solve from left to right. Example: 10 / 2 * 5 = 25 as 5 * 5 = 25

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How to preform addition and subtraction.

The next operation to perform within the BODMAS ruleset is addition and subtraction.

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Addition and Subtraction rule.

Addition and subtraction are of equal importance so solve from left to right. Example: 8 + 7 - 4 = 11 as 15 - 4 = 11

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When to expand exponents.

If a number has an exponential perform this once you have solved the values in the parenthesis.

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How to solve equations when there is a number multiplying a bracket.

Evaluate inside of parenthesis first, then multiply the result by the number within the equation. E.g. Solve the equation (8 + 5) × 2

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What does 23 – 3 × (5 + 8) equal?

First multiply by 3, then take away 7 for the result: 3 × (5 + 8). (5+8) = 13. So then do: 3 x 13 = 39. Then subtract 39 from 23= 16.

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How to solve multiple brackets.

Before removing numbers evaluate everything within the parenthesis using BODMAS. Example: 12 ÷ 6 × (4 – 3) = 2.

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Calculations without Brackets.

Remember that some calculations may not require any brackets to solve.

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What is the use of brakets

Brackets isolates the operations within it.

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Study Notes

  • These notes cover multi-step calculations using the BODMAS order of operations
  • BODMAS is an acronym that helps remember the order of operations: Brackets, Order, Division/Multiplication, Addition/Subtraction

Order of Operations (BODMAS)

  • Brackets: Calculate expressions inside brackets first
  • Order: Evaluate powers, square roots, etc.
  • Division and Multiplication: Perform these operations from left to right
  • Addition and Subtraction: Perform these operations from left to right

Calculations

  • 7 × (8 - 3) = 7 × 5 = 35
  • 7 + 9 × 2 = 7 + 18 = 25
  • 10 ÷ (6 - 4) = 10 ÷ 2 = 5
  • 12 ÷ (7 - 4) = 12 ÷ 3 = 4
  • (8 + 9) + 6² = 17 + 36 = 53
  • 21 ÷ (4 + 3) = 21 ÷ 7 = 3
  • 10 – 9 ÷ 3 = 10 - 3 = 7
  • 7 + 6 × 4 = 7 + 24 = 31
  • (12 + 20) ÷ 4 = 32 ÷ 4 = 8
  • (13 – 6) × 5 = 7 × 5 = 35
  • 9 × (3 + 3) = 9 × 6 = 54
  • 2³ – (3 + 1) = 8 - 4 = 4
  • (10 + 5) ÷ 5 = 15 ÷ 5 = 3
  • 12 ÷ (7 - 4) = 12 ÷ 3 = 4
  • (11 – 3) × 7 = 8 × 7 = 56
  • (12 - 7) × 8 = 5 × 8 = 40
  • 9 + 2 × 7 = 9 + 14 = 23
  • 18 ÷ (8 - 2) = 18 ÷ 6 = 3
  • (12 + 8) ÷ 4 = 20 ÷ 4 = 5
  • (5² + 10) ÷ 5 = (25 + 10) ÷ 5 = 35 ÷ 5 = 7
  • (8 + 9) ÷ 6² = 17 ÷ 36 = 53
  • 4 × 6 - 14 = 24 - 14 = 10
  • 18 ÷ (4 + 5) = 18 ÷ 9 = 2
  • (21 – 9) × 2 = 12 × 2 = 24
  • 8 × 3 + 6 = 24 + 6 = 30
  • 3 × (15 – 9) = 3 × 6 = 18
  • 6³ – (35 + 12) = 216 - 47 = 169
  • (14 + 21) ÷ 5 = 35 ÷ 5 = 7
  • (8 + 13) ÷ 7 = 21 ÷ 7 = 3
  • 25 – 11 × 2 = 25 - 22 = 3
  • (7² + 11) ÷ 5 = (49 + 11) ÷ 5 = 60 ÷ 5 = 12
  • 9 ÷ (10 – 7) = 9 ÷ 3 = 3
  • 26 - 3 × 7 = 26 - 21 = 5
  • Determine missing values
  • 4 × 12 – 25 = 23
  • (26 – 10) ÷ 4 = 4; Therefore 16 / 4 = 4
  • 60 ÷ 5 = (3 + 9); Therefore 60 / 5 = 12, so 3 + 9 = 12
  • (5 + 9) ÷ 7= 2; Therefore 14 / 7= 2
  • 9 × (12 – 5)number = 63; Therefore 63 / 9 = 7 , so 12 - 5 = 7
  • 45 ÷ 5 = (5 + 4); Therefore 45 / 5 = 9, so 5 + 4 = 9
  • 15 ÷ (7-2) = 3; Therefore 15 / 5 = 3, so 7-2 = 5
  • 8² + (66 – 44)number = 86; Therefore 86 - 64 (8sq) = 22, so 66 - 44 = 22
  • 6 = 42 ÷ (11-4); Therefore 6 x 7 =42, so 11 - 4 = 7
  • (3 + 6) × (8 – 5) = 9 × 3 = 27
  • 7 + 8 × 9 – 4 = 7 + 72 - 4 = 75
  • 8 × (6 + 3) ÷ 5 = 8 × 9 ÷ 5 = 77
  • (19 – 7) ÷ 8² + 9= 12 + 64 + 9=85
  • 9 × (5 + 6) ÷ 4 = 9 x11 + 4= 103
  • 8 ÷ (7–5) × 6 = 8 ÷ 2 × 6 = 24
  • 9 × 3 + 18 ÷ 9 = 27 + 2 = 29
  • (124 ÷ 2) × 2² = 62 × 4 = 248
  • 23 – 3 × (5+8)= 23 – 3 × 13 = -16
  • 8 + 7 × (12 – 5) = 8 + 7 × 7 = 57
  • 24 – 17 × 8 – 16 = 40
  • 8 × (9 – 5) – 6 = 8 × 4 – 6 = 26
  • 9 × (7 - 6) × 3 = 9 × 1 × 3 = 27
  • 8 × (7 - 4) ÷ 6 = 4
  • 9 + 23 – 5×5= 7
  • (5 + 11) ÷ (7 - 3) = 4
  • 7 + 6 × (12 - 7)= 37
  • (15 + 9) ÷ 6 − 4= 0
  • 6 + 4 + 3 − 12 = 1
  • 12 ÷ 6 × (4-3) = 2
  • Use all the numbers to create a calculation and then solve it using order of operations: 3, 4, 6, 12
  • 12- 3 x 4 + 6 = 6
  • (4 × 3) - (12 ÷ 6) = 10
  • (12 x 3) - (6 × 4) = 12
  • (4 + 6) × 3 – 12 = 18
  • (4 + 6) × 12 ÷ 3 = 40

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