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What is BODMAS?
What is BODMAS?
BODMAS is an acronym that defines the order of operations in mathematical expressions.
Brackets (B)
Brackets (B)
Calculations inside brackets are always performed first.
Orders (O)
Orders (O)
Orders refer to powers or roots.
Division and Multiplication (DM)
Division and Multiplication (DM)
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Addition and Subtraction (AS)
Addition and Subtraction (AS)
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Solving with brackets example
Solving with brackets example
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Multiplication before Addition
Multiplication before Addition
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Division before Subtraction
Division before Subtraction
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Why solve parenthesis first?
Why solve parenthesis first?
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BODMAS within Parenthesis
BODMAS within Parenthesis
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No Parenthesis
No Parenthesis
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Same Priority Operations
Same Priority Operations
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Solve: (12+8) ÷ 4
Solve: (12+8) ÷ 4
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Solve: 4 × 6 – 14
Solve: 4 × 6 – 14
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Solve 8 × 3 + 6
Solve 8 × 3 + 6
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Solve: 3 × (15 – 9)
Solve: 3 × (15 – 9)
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Solve: 6³ – (35 + 12)
Solve: 6³ – (35 + 12)
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Solve: 4 × – 25 = 23
Solve: 4 × – 25 = 23
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Solve: (26 – 10) ÷ =4
Solve: (26 – 10) ÷ =4
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Solve: 7 + 8 × 9 – 4
Solve: 7 + 8 × 9 – 4
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Solve: (19 – 7) + 82 + 9
Solve: (19 – 7) + 82 + 9
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60 = 5 × (3 + )
60 = 5 × (3 + )
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Solve: (3 + 6) × (8 – 5)
Solve: (3 + 6) × (8 – 5)
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Solve 7 + 8 × 9 – 4
Solve 7 + 8 × 9 – 4
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Solve: 8 × (6 + 3) + 5
Solve: 8 × (6 + 3) + 5
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Solve: 23 – 3 × (5 + 8)
Solve: 23 – 3 × (5 + 8)
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Solve: 8 + 7 × (12 – 5)
Solve: 8 + 7 × (12 – 5)
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6 × 7 – 4 × 8 = 10
6 × 7 – 4 × 8 = 10
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9 × 7 – 6 × 3 = 27
9 × 7 – 6 × 3 = 27
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5 + 11 ÷ 7 – 3 = 4
5 + 11 ÷ 7 – 3 = 4
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Multiple card calculations.
Multiple card calculations.
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Define Orders within BODMAS.
Define Orders within BODMAS.
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Division and Multiplication rule.
Division and Multiplication rule.
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How to preform addition and subtraction.
How to preform addition and subtraction.
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Addition and Subtraction rule.
Addition and Subtraction rule.
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When to expand exponents.
When to expand exponents.
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How to solve equations when there is a number multiplying a bracket.
How to solve equations when there is a number multiplying a bracket.
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What does 23 – 3 × (5 + 8) equal?
What does 23 – 3 × (5 + 8) equal?
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How to solve multiple brackets.
How to solve multiple brackets.
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Calculations without Brackets.
Calculations without Brackets.
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What is the use of brakets
What is the use of brakets
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Study Notes
- These notes cover multi-step calculations using the BODMAS order of operations
- BODMAS is an acronym that helps remember the order of operations: Brackets, Order, Division/Multiplication, Addition/Subtraction
Order of Operations (BODMAS)
- Brackets: Calculate expressions inside brackets first
- Order: Evaluate powers, square roots, etc.
- Division and Multiplication: Perform these operations from left to right
- Addition and Subtraction: Perform these operations from left to right
Calculations
- 7 × (8 - 3) = 7 × 5 = 35
- 7 + 9 × 2 = 7 + 18 = 25
- 10 ÷ (6 - 4) = 10 ÷ 2 = 5
- 12 ÷ (7 - 4) = 12 ÷ 3 = 4
- (8 + 9) + 6² = 17 + 36 = 53
- 21 ÷ (4 + 3) = 21 ÷ 7 = 3
- 10 – 9 ÷ 3 = 10 - 3 = 7
- 7 + 6 × 4 = 7 + 24 = 31
- (12 + 20) ÷ 4 = 32 ÷ 4 = 8
- (13 – 6) × 5 = 7 × 5 = 35
- 9 × (3 + 3) = 9 × 6 = 54
- 2³ – (3 + 1) = 8 - 4 = 4
- (10 + 5) ÷ 5 = 15 ÷ 5 = 3
- 12 ÷ (7 - 4) = 12 ÷ 3 = 4
- (11 – 3) × 7 = 8 × 7 = 56
- (12 - 7) × 8 = 5 × 8 = 40
- 9 + 2 × 7 = 9 + 14 = 23
- 18 ÷ (8 - 2) = 18 ÷ 6 = 3
- (12 + 8) ÷ 4 = 20 ÷ 4 = 5
- (5² + 10) ÷ 5 = (25 + 10) ÷ 5 = 35 ÷ 5 = 7
- (8 + 9) ÷ 6² = 17 ÷ 36 = 53
- 4 × 6 - 14 = 24 - 14 = 10
- 18 ÷ (4 + 5) = 18 ÷ 9 = 2
- (21 – 9) × 2 = 12 × 2 = 24
- 8 × 3 + 6 = 24 + 6 = 30
- 3 × (15 – 9) = 3 × 6 = 18
- 6³ – (35 + 12) = 216 - 47 = 169
- (14 + 21) ÷ 5 = 35 ÷ 5 = 7
- (8 + 13) ÷ 7 = 21 ÷ 7 = 3
- 25 – 11 × 2 = 25 - 22 = 3
- (7² + 11) ÷ 5 = (49 + 11) ÷ 5 = 60 ÷ 5 = 12
- 9 ÷ (10 – 7) = 9 ÷ 3 = 3
- 26 - 3 × 7 = 26 - 21 = 5
- Determine missing values
- 4 × 12 – 25 = 23
- (26 – 10) ÷ 4 = 4; Therefore 16 / 4 = 4
- 60 ÷ 5 = (3 + 9); Therefore 60 / 5 = 12, so 3 + 9 = 12
- (5 + 9) ÷ 7= 2; Therefore 14 / 7= 2
- 9 × (12 – 5)number = 63; Therefore 63 / 9 = 7 , so 12 - 5 = 7
- 45 ÷ 5 = (5 + 4); Therefore 45 / 5 = 9, so 5 + 4 = 9
- 15 ÷ (7-2) = 3; Therefore 15 / 5 = 3, so 7-2 = 5
- 8² + (66 – 44)number = 86; Therefore 86 - 64 (8sq) = 22, so 66 - 44 = 22
- 6 = 42 ÷ (11-4); Therefore 6 x 7 =42, so 11 - 4 = 7
- (3 + 6) × (8 – 5) = 9 × 3 = 27
- 7 + 8 × 9 – 4 = 7 + 72 - 4 = 75
- 8 × (6 + 3) ÷ 5 = 8 × 9 ÷ 5 = 77
- (19 – 7) ÷ 8² + 9= 12 + 64 + 9=85
- 9 × (5 + 6) ÷ 4 = 9 x11 + 4= 103
- 8 ÷ (7–5) × 6 = 8 ÷ 2 × 6 = 24
- 9 × 3 + 18 ÷ 9 = 27 + 2 = 29
- (124 ÷ 2) × 2² = 62 × 4 = 248
- 23 – 3 × (5+8)= 23 – 3 × 13 = -16
- 8 + 7 × (12 – 5) = 8 + 7 × 7 = 57
- 24 – 17 × 8 – 16 = 40
- 8 × (9 – 5) – 6 = 8 × 4 – 6 = 26
- 9 × (7 - 6) × 3 = 9 × 1 × 3 = 27
- 8 × (7 - 4) ÷ 6 = 4
- 9 + 23 – 5×5= 7
- (5 + 11) ÷ (7 - 3) = 4
- 7 + 6 × (12 - 7)= 37
- (15 + 9) ÷ 6 − 4= 0
- 6 + 4 + 3 − 12 = 1
- 12 ÷ 6 × (4-3) = 2
- Use all the numbers to create a calculation and then solve it using order of operations: 3, 4, 6, 12
- 12- 3 x 4 + 6 = 6
- (4 × 3) - (12 ÷ 6) = 10
- (12 x 3) - (6 × 4) = 12
- (4 + 6) × 3 – 12 = 18
- (4 + 6) × 12 ÷ 3 = 40
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