Arithmetic Progressions Quiz

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Questions and Answers

Which of the following is the correct equation to find the nth term of an arithmetic progression?

  • $a_n = a_1 + (n + 1)d$
  • $a_n = a_1 \cdot (n - 1)d$
  • $a_n = a_1 \cdot (n + 1)d$
  • $a_n = a_1 + (n - 1)d$ (correct)

Which term of the arithmetic progression 2, 5, 8, 11, ... is 23?

  • $a_7$
  • $a_9$
  • $a_8$ (correct)
  • $a_6$

What is the common difference of the arithmetic progression 10, 7, 4, 1, ...?

  • $-3$ (correct)
  • $-1$
  • $-2$
  • $3$

What is the sum of the arithmetic series 3, 6, 9, 12, ..., 99?

<p>$1485$ (D)</p> Signup and view all the answers

According to the anecdote, who reinvented the method to compute arithmetic progressions?

<p>Carl Friedrich Gauss (C)</p> Signup and view all the answers

Flashcards

Arithmetic Progression

A sequence where the difference between any two consecutive terms is constant.

Common Difference (d)

The constant difference between consecutive terms in an arithmetic progression.

nth Term Formula

The formula used to find the nth term of an arithmetic progression, where a1 is the first term, d is the common difference, and n is the term number.

Arithmetic Series Sum

The sum of all terms in a finite arithmetic progression.

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Carl Friedrich Gauss

A mathematical prodigy who is credited with reinventing the method for calculating the sum of an arithmetic series.

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Study Notes

Arithmetic Progression (AP) Basics

  • The nth term of an Arithmetic Progression can be calculated using the formula:
    • nth term = a + (n - 1)d
    • where 'a' is the first term, 'd' is the common difference, and 'n' is the term number.

Finding Specific Terms

  • In the AP 2, 5, 8, 11, ..., to find which term equals 23:
    • Use the nth term formula: 23 = 2 + (n - 1)3.
    • Solving gives n = 8, meaning 23 is the 8th term.

Common Difference

  • For the AP 10, 7, 4, 1, ..., the common difference 'd' can be identified:
    • d = second term - first term = 7 - 10 = -3.
    • This indicates a decreasing sequence.

Sum of the Series

  • The sum of the arithmetic series 3, 6, 9, 12, ..., 99 can be calculated:
    • First find the number of terms (n):
      • Last term (99) = first term (3) + (n - 1) * common difference (3).
      • Solve for n, yielding n = 33.
    • Then use the formula for the sum:
      • Sum = n/2 * (first term + last term), resulting in a total sum of 1683.

Historical Note

  • The anecdote attributes the reinvention of methods to compute arithmetic progressions to prominent mathematicians, although the specific names may vary based on context.

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