Analyzing Group I Cations (Silver Group)
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Questions and Answers

Which of the following cations does NOT belong to Group I cations?

  • Bismuth (Bi^{3+}) (correct)
  • Mercurous (Hg_2^{2+})
  • Silver (Ag^{+})
  • Lead (Pb^{2+})
  • What is the role of HCl in the precipitation of Group I cations?

  • To form soluble salts of the cations
  • To prevent the formation of insoluble salt of bismuth (correct)
  • To oxidize the cations
  • To increase the solubility of the precipitates
  • Why should a slight excess of HCl be added during the analysis?

  • To fully dissolve all the cations
  • To obtain complete precipitation and prevent peptization of the insoluble chlorides (correct)
  • To increase the temperature of the solution
  • To ensure the chlorides remain soluble
  • What is the formula of the precipitate formed by the addition of cold dilute HCl in Group I cations?

    <p>$PbCl_2$</p> Signup and view all the answers

    Which of the following chemical equations represents the formation of lead chloride precipitate?

    <p>$Pb^{2+} + 2Cl^- + H_2O \rightarrow PbCl_2 \downarrow$</p> Signup and view all the answers

    Study Notes

    Group I Cations (Silver Group)

    • The group includes lead, silver, and mercurous, with their respective ions: $Pb^{2+}$, $Ag^{+}$, and $Hg_2^{2+}$

    Steps of Analysis

    • Precipitation is the first step of analysis, using cold dilute $HCl$ as the group reagent
    • The group reagent $HCl$ precipitates the ions as chlorides, with the following formulas: $AgCl$, $PbCl_2$, and $Hg_2Cl_2$, resulting in a white precipitate
    • $HCl$ is preferred over $NH_4Cl$ because it prevents the formation of insoluble bismuth oxychloride precipitate
    • A slight excess of $HCl$ should be added to ensure complete precipitation and prevent peptization of the insoluble chlorides
    • The chemical equation for the precipitation of $PbCl_2$ is: $Pb^{2+} + 2Cl^- + H_2O \rightarrow PbCl_2 \downarrow$

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    Description

    This quiz covers the analysis of Group I cations, including lead, silver, and mercurous, through precipitation reactions with cold dilute HCl. Understand the formula of precipitates and the reasons behind using HCl as the group reagent.

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