Analyzing Group I Cations (Silver Group)
5 Questions
0 Views

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

Which of the following cations does NOT belong to Group I cations?

  • Bismuth (Bi^{3+}) (correct)
  • Mercurous (Hg_2^{2+})
  • Silver (Ag^{+})
  • Lead (Pb^{2+})
  • What is the role of HCl in the precipitation of Group I cations?

  • To form soluble salts of the cations
  • To prevent the formation of insoluble salt of bismuth (correct)
  • To oxidize the cations
  • To increase the solubility of the precipitates
  • Why should a slight excess of HCl be added during the analysis?

  • To fully dissolve all the cations
  • To obtain complete precipitation and prevent peptization of the insoluble chlorides (correct)
  • To increase the temperature of the solution
  • To ensure the chlorides remain soluble
  • What is the formula of the precipitate formed by the addition of cold dilute HCl in Group I cations?

    <p>$PbCl_2$</p> Signup and view all the answers

    Which of the following chemical equations represents the formation of lead chloride precipitate?

    <p>$Pb^{2+} + 2Cl^- + H_2O \rightarrow PbCl_2 \downarrow$</p> Signup and view all the answers

    Study Notes

    Group I Cations (Silver Group)

    • The group includes lead, silver, and mercurous, with their respective ions: $Pb^{2+}$, $Ag^{+}$, and $Hg_2^{2+}$

    Steps of Analysis

    • Precipitation is the first step of analysis, using cold dilute $HCl$ as the group reagent
    • The group reagent $HCl$ precipitates the ions as chlorides, with the following formulas: $AgCl$, $PbCl_2$, and $Hg_2Cl_2$, resulting in a white precipitate
    • $HCl$ is preferred over $NH_4Cl$ because it prevents the formation of insoluble bismuth oxychloride precipitate
    • A slight excess of $HCl$ should be added to ensure complete precipitation and prevent peptization of the insoluble chlorides
    • The chemical equation for the precipitation of $PbCl_2$ is: $Pb^{2+} + 2Cl^- + H_2O \rightarrow PbCl_2 \downarrow$

    Studying That Suits You

    Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

    Quiz Team

    Description

    This quiz covers the analysis of Group I cations, including lead, silver, and mercurous, through precipitation reactions with cold dilute HCl. Understand the formula of precipitates and the reasons behind using HCl as the group reagent.

    More Like This

    Use Quizgecko on...
    Browser
    Browser