Analytical Chemistry Solutions Quiz

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Questions and Answers

In the context of concentration, what are the majority and minority components referred to as?

  • Solution and solvent
  • Solvent and solutes (correct)
  • Solute and solution
  • Solute and solvent

What is the definition of a solution in analytical chemistry?

  • A mixture of two or more components with different physical states
  • A mixture with uneven distribution of components
  • A mixture of two or more components with visible boundaries
  • A homogenous mixture of two or more components (correct)

What is the definition of molarity in analytical chemistry?

  • $M = \frac{\text{grams of solute}}{\text{liters of solution}}$
  • $M = \frac{\text{moles of solute}}{\text{grams of solvent}}$
  • $M = \frac{\text{moles of solvent}}{\text{liters of solution}}$
  • $M = \frac{\text{moles of solute}}{\text{liters of solution}}$ (correct)

What is the unit for expressing concentration?

<p>Relative amount of solute per unit volume or unit mass of solution (C)</p> Signup and view all the answers

What is the molarity of the AgNO3 solution prepared by dissolving 1.26 g AgNO3 in a 250 ml volumetric flask?

<p>$0.0297 M$ (D)</p> Signup and view all the answers

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Study Notes

Concentration in Analytical Chemistry

  • In the context of concentration, the majority component is referred to as the solvent, while the minority component is referred to as the solute.

Definition of a Solution

  • A solution is a homogeneous mixture composed of two or more substances, where one substance (the solute) is dissolved in another substance (the solvent).

Definition of Molarity

  • Molarity is the number of moles of solute per liter of solution, expressed in units of moles per liter (mol/L) or molarity (M).

Unit for Expressing Concentration

  • Concentration is typically expressed in units of molarity (M), which represents the number of moles of solute per liter of solution.

Example Calculation: Molarity of AgNO3 Solution

  • The molarity of the AgNO3 solution prepared by dissolving 1.26 g AgNO3 in a 250 ml volumetric flask can be calculated as follows:
    • First, calculate the number of moles of AgNO3: moles = mass / molar mass = 1.26 g / 169.87 g/mol = 0.0074 mol
    • Then, calculate the molarity: molarity = moles / liter = 0.0074 mol / 0.25 L = 0.0296 M or approximately 0.03 M

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