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Questions and Answers
What is the first step in finding the molar concentration of a solute in a solution using dilution rule?
What is the first step in finding the molar concentration of a solute in a solution using dilution rule?
- Measure the mass of the solute (correct)
- Calculate the molar mass of the solute
- Measure the volume of the solution
- Calculate the final molar concentration
In problem 3, what is the molar mass of NaBr?
In problem 3, what is the molar mass of NaBr?
- 22.99 g/mol
- 58.44 g/mol (correct)
- 102.89 g/mol
- 50 g/mol
What is the correct method for preparing 0.18 M CaSO4 in 100 mL?
What is the correct method for preparing 0.18 M CaSO4 in 100 mL?
- Calculate the molar concentration of the stock solution and dilute it to obtain 0.18 M in 100 mL (correct)
- Add 0.18 moles of CaSO4 to 100 mL of water
- Add 18 grams of CaSO4 to 100 mL of water
- Dissolve 0.18 grams of CaSO4 in 100 mL of water
How much volume (in mL) of the solution is requested to dissolve 3 grams of LiOH to prepare 0.25 M?
How much volume (in mL) of the solution is requested to dissolve 3 grams of LiOH to prepare 0.25 M?
What is the definition of 'specific grav.Write' on the bottle mentioned in problem 1?
What is the definition of 'specific grav.Write' on the bottle mentioned in problem 1?
Problem 1 is about calculating the molar concentration of ethanol in an aqueous solution
Problem 1 is about calculating the molar concentration of ethanol in an aqueous solution
Problem 2 is about preparing 2.00 L of 0.108 M BaCl2 from BaCl2 2H2O
Problem 2 is about preparing 2.00 L of 0.108 M BaCl2 from BaCl2 2H2O
Problem 3 involves preparing 0.5 M NaBr in 500 mL distilled water
Problem 3 involves preparing 0.5 M NaBr in 500 mL distilled water
Problem 4 is about preparing 0.18 M CaSO4 in 100 mL
Problem 4 is about preparing 0.18 M CaSO4 in 100 mL
Problem 5 involves finding the volume of the solution requested to dissolve 3 grams of LiOH to prepare 0.25 M
Problem 5 involves finding the volume of the solution requested to dissolve 3 grams of LiOH to prepare 0.25 M