Algebra 1 Quiz 15
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Questions and Answers

A consistent system of equations has at least one solution.

True

A system of independent equations has indefinite solutions.

False

An inconsistent system of independent equations has zero solutions.

True

Is 5x + 2y = 4, 4x + y = 11 a solution?

<p>Not a solution</p> Signup and view all the answers

Is 3x + 2y = 13, 4x - 3y = -11 a solution?

<p>Solution</p> Signup and view all the answers

Is 2x - 5y = -22, 3x - 2y = -22 a solution?

<p>Not a solution</p> Signup and view all the answers

What are the coordinates for number 7 on the graph paper?

<p>(2, -4)</p> Signup and view all the answers

What are the coordinates for number 8?

<p>(-6, 1)</p> Signup and view all the answers

What is the solution for the system x - y = 3 and 2x + y = -6?

<p>(-1, -4)</p> Signup and view all the answers

Study Notes

Systemata aequationum

  • Systema consistentium aequationum habet saltem unam solutionem.
  • Systema independens aequationum non habet solutiones indefinitas; potius dicitur esse dependentium.

Systemata inconsistente

  • Systema inconsistente aequationum independens non habet solutiones (Zero solutions).

Solutiones et non solutiones

  • Pro example, pro aequationibus 5x + 2y = 4 et 4x + y = 11:

    • Cum x = 2 et y = -3, aequatio 5(2) - 2(-3) = 4 verum est, sed 4(2) - 3 non = 11; igitur, non est solutio.
  • Pro aequationibus 3x + 2y = 13 et 4x - 3y = -11:

    • Cum x = 1 et y = 5, 3(1) + 10 = 13 et 4(1) - 15 = -11; igitur, haec est solutio.

Exempla non solucionum

  • Pro aequationibus 2x - 5y = -22 et 3x - 2y = -22:
    • Cum x = -6 et y = -2, -12 + 10 non = 22; igitur, non est solutio.

Puncta in graphico

  • Puncta quae referuntur:
    • Punctum 7: (2, -4)
    • Punctum 8: (-6, 1)

Solutio specifica

  • Pro aequationibus x - y = 3 et 2x + y = -6, solutio est (-1, -4).

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Hic quiz in Algebram 1 tractat systems aequationum. Investigabitur veritatem et falsitatem propositionum, et definientur solutiones quaestionum specificarum. Paratus est ad provocationem tuam in re algebraica!

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