Adiabatic Process: Thermodynamics

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Questions and Answers

In an adiabatic process, which of the following statements is always true?

  • The change in internal energy is zero.
  • The work done by the system is zero.
  • The temperature of the system remains constant.
  • The heat transfer between the system and its surroundings is zero. (correct)

A gas performs 500 J of work in an adiabatic container. What is the change in the internal energy of the gas?

  • +1000 J
  • 0 J
  • +500 J
  • -500 J (correct)

If the internal energy of a system decreases during an adiabatic process, what can be inferred about the temperature of the system?

  • The temperature increases.
  • The temperature decreases. (correct)
  • The change in temperature cannot be determined.
  • The temperature remains constant.

Four moles of neon gas undergo an adiabatic process with a temperature change from 500K to 300K. Given that $C_v = 12.47 \frac{J}{mol*K}$, what is the change in internal energy ($\Delta U$)?

<p>-9976 J (B)</p> Signup and view all the answers

In the previous question, where the internal energy change of neon gas was calculated as -9976 J, how much work was performed?

<p>+9976 J (Work done by the gas) (C)</p> Signup and view all the answers

Nitrogen gas (a diatomic gas with $C_v = 20.79 \frac{J}{mol*K}$) undergoes adiabatic expansion. If the initial pressure and volume are $20 \times 10^5 Pa$ and $0.02 m^3$, and the final pressure and volume are $2 \times 10^5 Pa$ and $0.08 m^3$, what is the approximate amount of work done by the gas?

<p>60,000 J (D)</p> Signup and view all the answers

Given the adiabatic expansion of Nitrogen gas in the previous question, where the work done by the gas was calculated as 60,000 J, what is the change in its internal energy?

<p>-60,000 J (B)</p> Signup and view all the answers

Air is compressed adiabatically from $0.10 m^3$ at $1 \times 10^5 Pa$ to $0.01 m^3$ at $40 \times 10^5 Pa$. Given $\gamma = 1.4$, calculate the approximate work done on the gas.

<p>-75,000 J (C)</p> Signup and view all the answers

Following the adiabatic compression of air in the previous question, where the work done on the gas was calculated as -75,000 J, determine the change in the internal energy of the air.

<p>+75,000 J (D)</p> Signup and view all the answers

Which scenario exemplifies an adiabatic process most accurately?

<p>The rapid expansion of hot gas in an engine cylinder. (A)</p> Signup and view all the answers

Flashcards

Adiabatic Process

A process where no heat is transferred into or out of the system; Q = 0.

Change in Internal Energy Formula

The change in a system's internal energy equals the heat added to the system minus the work done by the system: ΔU = Q - W.

Adiabatic Expansion and Temperature

In an adiabatic process, if work is done by the gas (expansion), the internal energy decreases, leading to a temperature decrease.

Cv for Monoatomic Gas

For a monoatomic gas like Neon, Cv is (3/2)*R, where R is the ideal gas constant.

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Adiabatic ΔU and Work

In adiabatic conditions, the change in internal energy is the negative of the work done: ΔU = -W.

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Cv for Diatomic Gas

For diatomic gases, Cv = (5/2) * R, where R is the ideal gas constant.

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Work Formula for Adiabatic Process

W = -1/(γ - 1) * (P_final * V_final - P_initial * V_initial); where γ is the ratio of specific heats.

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Sign Convention for Work (Thermodynamics)

If work is done on the gas (compression) the value is negative. If work is done by the gas (expansion) the value is positive.

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Gamma for Air

For diatomic gases, γ is 1.4

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Study Notes

The provided text contains the same information already present in the existing notes. Therefore, no updates are necessary.

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