10th NCERT Math Questions with Solutions

Unlocking Maths Genius: 10th NCERT Solutions to Important Questions

As a 10th grade math student, you'll likely encounter a range of challenging questions that demand more than just textbook solutions. NCERT (National Council of Educational Research and Training) textbooks are renowned for their problem-solving depth and real-life applications, and understanding how to tackle these questions can propel your mathematical prowess. To help you excel in your math journey, I've compiled a set of important questions, along with their NCERT solutions, and a few insights to equip you with a problem-solving mindset.

Linear Equations in One Variable

Question: Solve the following equation for x: (3x-4=11).

Solution: To solve for x, follow these steps:

1. Add 4 to both sides of the equation to isolate the variable on one side: (3x-4+4 = 11+4).
2. Simplify: (3x = 15).
3. Divide by 3: (\frac{3x}{3} = \frac{15}{3}).
4. Solve for x: (x = 5).

Linear Inequalities

Question: Solve the following inequality for x: (6-2x > 8).

Solution: To solve this linear inequality, follow these steps:

1. Subtract 6 from both sides: (-2x>2).
2. Divide by -2: (\frac{-2x}{-2}<\frac{2}{-2}).
3. Flip the inequality sign when dividing by a negative number: (x<-1).

Quadratic Equations

Question: Solve the quadratic equation (x^2-3x-4 = 0) by the quadratic formula.

Solution: To solve this quadratic equation using the quadratic formula, plug the coefficients into the formula:

[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

Substitute the coefficients: (a=1), (b=-3), and (c=-4).

[ x = \frac{3 \pm \sqrt{(-3)^2 - 4(1)(-4)}}{2(1)} ]

[ x = \frac{3 \pm \sqrt{9 + 16}}{2} ]

[ x = \frac{3 \pm \sqrt{25}}{2} ]

[ x = \frac{3 \pm 5}{2} ]

Solve for x: (x = \frac{3+5}{2}) or (x = \frac{3-5}{2})

[ x = \frac{8}{2} = 4 \text{ or } \frac{-2}{2} = -1 ]

Coordinate Geometry

Question: Find the equation of the line passing through the points ((-1,3)) and ((2,5)).

Solution: To find the equation of a line passing through two points, follow these steps:

1. Plug the coordinates of one point, such as ((-1, 3)), into the slope-intercept form of a linear equation: (y = mx + b).
2. Find the slope (m) using the coordinates of the two points: (m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - 3}{2 - (-1)} = \frac{2}{3}).
3. Substitute the coordinates of one point and the slope into the equation: (y = \frac{2}{3}x + b).
4. Substitute the coordinates of the second point into the equation and solve for b: ((5) = (\frac{2}{3}(2)) + b), (b = \frac{5}{3}).

The equation of the line is (y = \frac{2}{3}x + \frac{5}{3}).

Practice and Mindset

As you explore these questions and their solutions, don't just memorize methods. Instead, focus on understanding the underlying concepts, and practice applying them to a variety of problems. Remember that the NCERT textbooks are designed to help you develop a strong foundation in math, and with practice and perseverance, you'll find that solving challenging problems becomes easier and more enjoyable.'s information about the "No Search" feature in Bing Chat is not directly applicable to NCERT solutions. However, it does provide insight into AI's ability to tackle complex math problems without web search capabilities, which can be an interesting topic of discussion.