Evaluating Soil Loss Using RUSLE PDF

Summary

This document details problems related to soil loss calculations using RUSLE (Revised Universal Soil Loss Equation). It includes various tables and equations for calculating factors like soil erodibility (K), topographic factor (LS), and plant cover management factor (C) to determine the amount of soil loss.

Full Transcript

Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Evaluating Soil Loss Using RUSLE Site Condition: A disturb...

Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Evaluating Soil Loss Using RUSLE Site Condition: A disturbed area of 15 acres has been created due to development construction near Norwich, Conn. (R=150). The soil is Charlton exposed in the B horizon. The average slope is 8% and the length of the slope is 400 feet. EnviroCert International, Inc.TM 17 Problem 1 Determine the estimated soil loss from this site if it remains unprotected for a period of one year. EnviroCert International, Inc.TM 18 9-9 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Use RUSLE Equation A = R K LS C P First find R-value using isoerodent maps EnviroCert International, Inc.TM 19 Reference Isoerodent maps from Figure 9-1 A = R K LS C P First find R-value using isoerodent maps EnviroCert International, Inc.TM 20 9-10 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Reference Isoerodent maps from Figure 9-1 R=150 EnviroCert International, Inc.TM 21 A = 150 K LS C P Now solve for soil erodibility factor, K. Reference Table 9-1 matching soil types EnviroCert International, Inc.TM 22 9-11 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 K-Value Table 9-1 K= 0.43 EnviroCert International, Inc.TM 23 A = 150.43 LS C P Find the corresponding slope length value, LS from slope grade and length Determine LS-value from Table 9-2 EnviroCert International, Inc.TM 24 9-12 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Table 9-2 Length = 400 ft. Slope = 8% LS value = 2.7 EnviroCert International, Inc.TM 25 A = 150.43 LS C P Determine plant cover management factor, C. Use Table 9-3 to determine C-value EnviroCert International, Inc.TM 26 9-13 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Table 9-3 C-value = 1 C-value = 1 (assume 1 if no cover practice provided) EnviroCert International, Inc.TM 27 A = 150.43 LS C P Finally, determine support practice factor, P Refer to P-factors Table 9-4 EnviroCert International, Inc.TM 28 9-14 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Table 9-4 P-value = 1 (assume 1 because of unprotected land) EnviroCert International, Inc.TM 29 Problem 1 - Solution A = R K (LS) C P A = (150)(0.43)(2.70)(1)(1) = 174.15 tons/acre/year x 15 acres = 2,612 tons per year EnviroCert International, Inc.TM 30 9-15 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Partial Year Soil Loss M Factor Table 9-6 Table 9-6 EnviroCert International, Inc.TM 31 Problem 2 Given the rainfall intensity distribution for Connecticut as shown on Table 9-6, determine the soil loss from this site for the period from October 1 to June 1 the following season. EnviroCert International, Inc.TM 32 9-16 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Soil Loss Percentages Percentages are 8 + 8 + 7 + 3 + 3 + 5 + 4 + 6 from Table 9-6 EnviroCert International, Inc.TM 33 Problem 2 - Solution Table 9-6 for October 1 through June 1: 8+8+7+3+3+5+4+6 = 44% of annual soil loss 0.44 x 2,612 = 1,149 tons EnviroCert International, Inc.TM 34 9-17 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Problem 3 Determine the annual soil loss from this site if a temporary seeding of annual rye grass is established. EnviroCert International, Inc.TM 35 What Value Changes? A = 150.43 2.7 C P C-value will decrease with ground cover. EnviroCert International, Inc.TM 36 9-18 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Table 9-3 C-value decreases by a factor of 10 EnviroCert International, Inc.TM 37 Problem 3 - Solution Table 9-3 for Temporary Seeding, annual rye: C = 0.1 0.1 x 2,612 = 261 tons EnviroCert International, Inc.TM 38 9-19 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Problem 4 How many cubic yards of soil will be lost from this site if the site is left unprotected for a year and the surface is compact and smooth, scraped with a bulldozer uphill and downhill? EnviroCert International, Inc.TM 39 Now What Will Change? A = 150.43 2.7 C P Support factor P will increase. (Table 9-4) EnviroCert International, Inc.TM 40 9-20 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Table 9-4 P-value = 1.3 EnviroCert International, Inc.TM 41 Problem 4 - Solution P = 1.3 So, predicted soil loss is recalculated: 2,612 x 1.3 = 3,396 tons 1st of 2 methods to convert tons to cubic yards: 3,396 Tons x 0.7 = 2,377 cubic yards (Table 4-5 for conversion factors) EnviroCert International, Inc.TM 42 9-21 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Unit Weight of Soil TABLE 9-5 - ESTIMATED WEIGHT OF SOILS 1 EnviroCert International, Inc.TM 43 Problem 4 - Solution Table 9-1 - Charlton texture is a fine sandy loam Table 9-5 - fine sandy loam has a unit weight of 1 0 5 l b s. / f t 3 2nd of 2 methods to convert tons to cubic yards: unit weight = 105 lbs./ft3 EnviroCert International, Inc.TM 44 9-22 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Problem 4 - Solution How many cubic yards? Convert 3396 tons to cubic yards using 105 lbs./ft3 (3396 tons)(2000 lbs./ton)(ft3/105 lbs.)(cy/27 ft3) = 2396 cy EnviroCert International, Inc.TM 45 Problem 5 A 22-acre site in Syracuse, NY (R=100) on Paxton soils is under construction. The site lies on a 6% slope with a slope length of 1,000 feet. (a) If left unprotected from April 1 until Nov. 1, what is the expected soil loss from the project based on the erosion index percentage graph (Figure 9-8)? (b) If mulched with straw at 2 tons per acre, what is the expected soil loss? EnviroCert International, Inc.TM 46 9-23 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Problem 5 - Solution A = R K (LS) C P A = (100)(0.43)(3.30)(1)(1) x 22 acres = 3,122 tons per year EnviroCert International, Inc.TM 47 Problem 5 – Solution (a) Next, adjust for the period of construction: Use the Erosion Index Graph Figure 9-8: 94% (Nov. 1) - 4% (Apr. 1) = 90% EnviroCert International, Inc.TM 48 9-24 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Problem 5 – Solution (b) Next, adjust for the period of construction: Table 9-3 for 2 tons per acre straw mulch: C-value = 0.02 (2,810) (0.02) = 56 tons EnviroCert International, Inc.TM 49 Modified Universal Soil Loss Equation (MUSLE) T = 95(V Qp)0.56 K LS C P Where: T = Sediment yield in tons for a storm event V = Volume of runoff for the storm event, ac-ft Qp = Peak flow for the storm event, cfs K, LS, C, P = same as in RUSLE For a specific storm event EnviroCert International, Inc.TM 50 9-25 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 Problem 6 Based on the 15 acre site in Problem 1, find the sediment yield for a storm with a Qp = 1.56 cfs and Runoff = 2.07” T = 95(V Qp)0.56 K LS C P K = 0.43; LS = 2.7; C = 1.0; P = 1.0 V = Runoff volume in ac-ft EnviroCert International, Inc.TM 51 Problem 6 Approach? Use the MUSLE Equation anytime you are calculating SOIL YIELD for a specific rain event at a specific location. Important note: Keep your notes organized. Label the question number and values. EnviroCert International, Inc.TM 52 9-26 | Page Certified Professional in Erosion and Sediment Control Review Presentation Manual V.7.0 T = 95(V Qp)0.56 K LS C P V = Runoff Acres (or [2.07in 1ft/12in] 15 Ac) = 2.59 ac-ft T = 95(V Qp)0.56 K LS C P T = 95(2.59 1.56)0.56 0.43 2.7 1 1 T or Sediment Yield for this storm event equals: 241 tons EnviroCert International, Inc.TM 53 Wind Erosion The process in which, by the actions of wind, a soil particle is detached and removed from its location. EnviroCert International, Inc.TM 54 9-27 | Page

Use Quizgecko on...
Browser
Browser