Lab 2 Physical Pharmacy PDF
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جامعة كلكامش
Hiba Sabah, Sura Zuhair, Zeina Dawoad
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Summary
This document covers the phase rule and different components in physical pharmacy. It explains the concept of phases and components in equilibrium systems, and explores two-component systems, particularly miscibility (or immiscibility) of substances such as water and phenol. The document also includes procedures for experiments on mixtures at various temperatures with calculations and graphical representations of results.
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Lab(2) physical pharmacy the Phase Rule and Different Components Done By: Assistant Lecturer Hiba Sabah Assistant Lecturer Sura Zuhair Assistant Lecturer Zeina Dawoad phase rule : is a relationship for determining the least number of variables required to define the sta...
Lab(2) physical pharmacy the Phase Rule and Different Components Done By: Assistant Lecturer Hiba Sabah Assistant Lecturer Sura Zuhair Assistant Lecturer Zeina Dawoad phase rule : is a relationship for determining the least number of variables required to define the state of the system. -phase :-is homogeneous physically distinct portion of the system which is separated from other parts of the system by bounding surfaces (e.g. water & its vapor is one component two phase system) Number of component :is the smallest number of constituents by which the phase of equilibrium system can be expressed as a chemical formula or equation. Two component systems containing liquid phase -as we know ethyl alcohol & water are miscible in all proportions , while water & mercury are completely immiscible regardless the amount of each. Between these two extremes lie a whole range of system which exhibit a partial miscibility ( or immiscibility) such as water & phenol , as their miscibility affected by two factors conc. & temp. To see the effect of temp. & conc. ,we draw graph paper of temp. versus conc. binodal curve :- is the curve that separates two phase area from one phase area. -tie line :- is the line drawn across the region of two phases (conjugate phases ) as each temp. has its own tie line. -upper consolute temp. or critical solu. Temp. :- is the maximum temp. at which two phase region exists. Water & phenol system it is 66.8 as all combinations above this temp. is completely miscible & give one phase system. -mass ratio:-is the relative amount by wt. of conjugate phase ,it depends on the position in tie line & temp. properties of the tie –line in two component systems:- 1-it is parallel to the base line 2-all systems prepared along the tie line at equilibrium separated into two conjugate phases of constant composition. For instance, consider a system containing 24% by weight of phenol and 76% by weight of water (point d in the diagram). At equilibrium two liquid phases have been presented in the tube. The upper one, A, has a composition of 11% phenol in water (point b on the diagram), whereas the lower layer, B, contains 63% phenol (point c on the diagram). The relative weights of the two phases can be calculated by the equation advantages of binodal curve :- Binodal curve or phase diagram is used to formulate systems containing more than component in single liq. phase product Q: At 25 C a tie line 7%---------70%, find the mass ratio and the composition of each phase of 40% w/w phenol by water at this temperature note that the total weight is 10 gm? 7%-------40%------------70% b-----------d---------------c Wt of A = dc 70-40 = 30 = 10 Wt of B bd 40-7 33 11 10+11=21 (total parts) 10 21 x 10 x= 4.76 gm wt of A 10-4.76 = 5.24 gm wt of B If we want I know the amount of phenol and water in each phase For phase A For phase B 7 100 70 100 X 4.76 x= 0.33gm of phenol in A X 5.24 X= 3.6gm of phenol in B 4.76-0.33= 4.42 gm of water in A 5.24- 3.6= 1.57gm of water in B Procedure: Prepare the following percent W/W phenol/water(10 gm total) 2%,7%,9%,11% ,24%,40%,55 %,63%,70%,75%. Put test tube in a fixed temperature in water bath (25 C0) or (left test tube at room temp.) and keep it for 10 minutes at that temp. Take the test tubes out and before their temp has changed record which one has 2 phases and which has one phase. Repeat the work at higher temp using the following temp.40C0, 50C0, 70C0. Draw a curve temp verses concentrations showing your 2 phases area and one phase area in the curve. Draw tie line for each temp. Take 40% W/W for example to find the mass ratio and the composition of each phase at different temp. Mention the upper consulate temp