Nile College Statistics Test No. 4 PDF
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Uploaded by MerryDrama
Niles College
2015
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Summary
This is a statistics exam, with questions on probability and probability distributions, specifically designed for students at Nile College, in the 2015/2016 academic year.
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## Nile College ### MLS Programme #### First year 2015/2016 - Semester II #### Statistics Test No. 4 #### Student's Name: ABD ELHAG ADAM #### Index No: 1 ###### Answer all the questions 1. The probability that an event happens is 0.46. What is the probability that the event will not happen? 0.54...
## Nile College ### MLS Programme #### First year 2015/2016 - Semester II #### Statistics Test No. 4 #### Student's Name: ABD ELHAG ADAM #### Index No: 1 ###### Answer all the questions 1. The probability that an event happens is 0.46. What is the probability that the event will not happen? 0.54 2. When two dice are rolled, find the probability of getting a sum of 5? 3/36 = 1/12 3. Find the probability of flipping a tail with a coin and then throwing an old number with a standard die? P(T) = 1/2 P(odd with a die) = 3/6 = 1/2 P(T and odd) = P(T) * P(odd with a die) = 1/2 * 1/2 = 1/4 4. If three people are randomly selected, find the probability that they will both have birthdays on a Monday. 1/7 * 1/7 * 1/7 = 1/343 5. The sample space S = {0, 1, 2, 3, 4} with probabilities P(0=0.1, P(1) = 0.3, P(2) = 0.25, P(3) = 0.15, P(4) = 0.2. Let A denote the event A = {0, 2, 3}, and let B denote the event B = {0, 1, 4}. Determine the following: I. P(A) P(A) = P(0) + P(2) + P(3) = 0.1 + 0.25 + 0.15 = 0.5 II. P(AUB) P(AUB) = P(A) + P(B) - P(A∩B) = 0.1 + 0.3 + 0.25 + 0.2 - (0.1 + 0.25) = 1 III. P(A∩B) P(A∩B) = P(A) * P(B) = {0} = 0.1 * 0.3 = 0.03 IV. P(AUB) P(AUB) = 1 - P(A∩B) = 1 - 0.03 = 0.97 V. P(A/B) P(A/B) = P(A∩B) / P(B) = 0.03 / 0.6 = 0.05 6. The probability that a specific medical test will show positive is 0.28. If four people are tested, find the probability that all four will show positive. P(SN SNS SN SN) = (0.28)^4 = 0.0065 ==End of OCR for page 90==