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Transcript
## Boundary conditions ### Condition 1: - When x = 0, Ψ =0 - From equation ② 0=B - Therefore B=0 ### Condition 2: - When Ψ=0, x=a - From equation ③ 0= Asinka - Therefore 0 = Sin ka - Therefore sina = sinak
## Boundary conditions ### Condition 1: - When x = 0, Ψ =0 - From equation ② 0=B - Therefore B=0 ### Condition 2: - When Ψ=0, x=a - From equation ③ 0= Asinka - Therefore 0 = Sin ka - Therefore sina = sinak
Tags
boundary conditions
mathematics
equations
