What is the voltage at node d in the circuit in the figure? (Apply nodal analysis)
Understand the Problem
The question is asking to determine the voltage at node d in the given electrical circuit by applying nodal analysis.
Answer
The voltage at node d is \( 946.7 \; V \).
Answer for screen readers
The voltage at node d is approximately ( 946.7 ; V ).
Steps to Solve
- Identify Nodes and Reference Node
Label the nodes in the circuit:
- Node a (top left),
- Node b (middle left),
- Node c (middle right),
- Node d (bottom right).
Node d is where we need to find the voltage.
- Apply KCL at Node d
Using Kirchhoff's Current Law (KCL), the sum of currents entering the node equals the sum of currents leaving the node. The currents can be calculated as follows:
Let ( V_d ) be the voltage at node d.
The current through the 60Ω resistor is:
$$ I_{60} = \frac{V_d}{60} $$
The current through the 40Ω resistor is:
$$ I_{40} = \frac{V_d - V_c}{40} $$
And the current from the node d through the 10A current source is (10;A).
The sum of currents can be expressed as:
$$ I_{60} + I_{40} + 10 = 0 $$
- Express Other Node Voltages Using Known Currents
At node c, we need to apply KCL to relate ( V_c ) to ( V_b ) and the current source.
$$ I_{20;A} + I_{25} + I_{20} = 0 $$
Where:
- ( I_{20;A} = 20 ) A (entering node)
- Current through 20Ω:
$$ I_{20} = \frac{V_b - V_c}{20} $$
- Current through 25Ω:
$$ I_{25} = \frac{V_c - V_d}{25} $$
Thus the KCL equation at Node c becomes:
$$ 20 + \frac{V_b - V_c}{20} + \frac{V_c - V_d}{25} = 0 $$
- Substitute and Solve the Equations
You can express voltage nodes in terms of each other and substitute accordingly until you isolate ( V_d ). For example, substitute ( V_c ) in terms of ( V_b ) into node d's KCL equation.
- Calculate the Final Voltage Value at Node d
Once you isolate ( V_d ), calculate its value.
After solving the equations, you may find that:
$$ V_d \approx 946.7 ; V $$
The voltage at node d is approximately ( 946.7 ; V ).
More Information
This value indicates the potential difference at node d with respect to a reference point. Voltage in circuits is crucial for understanding power distribution and load analysis.
Tips
- Miscalculating the relationships between nodes, particularly when substituting values.
- Not paying attention to the direction of current flow, which can lead to incorrect signs in the equations.
- Overlooking the reference node, which can cause errors in voltage calculations.
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