integrate sec x
Understand the Problem
The question is asking for the indefinite integral of the secant function, sec(x). This involves applying integration techniques to find the antiderivative of the secant function.
Answer
\ln|\text{sec}(x) + \text{tan}(x)| + C
Answer for screen readers
The indefinite integral of $\text{sec}(x) , dx$ is $\ln|\text{sec}(x) + \text{tan}(x)| + C$
Steps to Solve
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Rewrite the integral using a known technique
We start with the integral of $ ext{sec}(x)$, and use a clever substitution technique to simplify it. Specifically, we multiply and divide by $ ext{sec}(x) + ext{tan}(x)$.
$$ \int \text{sec}(x) , dx $$
Multiply and divide by $\text{sec}(x) + \text{tan}(x)$:
$$ \int \frac{\text{sec}(x)(\text{sec}(x) + \text{tan}(x))}{\text{sec}(x) + \text{tan}(x)} , dx $$
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Simplify the integrand
Simplify the expression inside the integral:
$$ \int \frac{\text{sec}^2(x) + \text{sec}(x)\text{tan}(x)}{\text{sec}(x) + \text{tan}(x)} , dx $$
Let $u = \text{sec}(x) + \text{tan}(x)$. Then, the differential $du$ is:
$$ du = \text{sec}(x)\text{tan}(x) , dx + \text{sec}^2(x) , dx $$
Thus,
$$ du = (\text{sec}(x)\text{tan}(x) + \text{sec}^2(x)) , dx $$
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Perform the substitution
Notice that the numerator of our integral $\text{sec}^2(x) + \text{sec}(x)\text{tan}(x)$ is exactly $du$:
$$ \int \frac{du}{u} $$
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Integrate using the natural logarithm rule
The integral of $\frac{1}{u}$ with respect to $u$ is $\ln|u| + C$:
$$ \ln|u| + C $$
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Substitute back the original expression
Substitute $u = \text{sec}(x) + \text{tan}(x)$ back into the expression:
$$ \ln|\text{sec}(x) + \text{tan}(x)| + C $$
The indefinite integral of $\text{sec}(x) , dx$ is $\ln|\text{sec}(x) + \text{tan}(x)| + C$
More Information
The integration of $\text{sec}(x)$ introduces the natural logarithm because of a unique substitution technique often used in calculus.
Tips
A common mistake is forgetting to introduce the absolute value in the natural logarithm, which is essential because the argument of the logarithm can be negative.
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