If a berkelium-249 target is bombarded with neon-22 ions, what other particle(s) must be released to synthesize seaborgium-266?
Understand the Problem
The question is asking us to determine the nuclear reaction products when berkelium-249 is bombarded with neon-22 to produce seaborgium-266. This involves balancing the nuclear equation and determining the number and type of particles emitted.
Answer
5 neutrons must be released.
To synthesize seaborgium-266 by bombarding berkelium-249 with neon-22, 5 neutrons must be released. The nuclear reaction is: $^{249}{97}Bk + ^{22}{10}Ne \rightarrow ^{266}_{106}Sg + 5\ ^1_0n$
Answer for screen readers
To synthesize seaborgium-266 by bombarding berkelium-249 with neon-22, 5 neutrons must be released. The nuclear reaction is: $^{249}{97}Bk + ^{22}{10}Ne \rightarrow ^{266}_{106}Sg + 5\ ^1_0n$
More Information
Seaborgium is a synthetic element, meaning it is not found in nature and must be created in a lab.
Tips
Make sure the mass numbers and atomic numbers are balanced on both sides of the equation.
Sources
- Seaborgium - Wikipedia - en.wikipedia.org
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