Given trapezoid UVWT with midsegment (median) XY. Solve for X.
Understand the Problem
The question is asking to solve for the variable X in a geometry problem involving a trapezoid with the lengths of the bases expressed in terms of X. We will set up an equation based on the given midsegment (median) relationships and solve for X.
Answer
$X = \frac{3}{5}$
Answer for screen readers
The value of $X$ is $\frac{3}{5}$.
Steps to Solve
- Understand the Midsegment Relationship
In a trapezoid, the length of the midsegment (median) is the average of the lengths of the two bases. For trapezoid UVWT, the bases are $UT$ and $VW$. The lengths are given as $UT = 3x - 1$ and $VW = 3x + 7$.
- Set Up the Equation
The equation for the midsegment $XY$ is set up by taking the average of the lengths of the two bases:
$$ XY = \frac{UT + VW}{2} $$
Substituting the values:
$$ XY = \frac{(3x - 1) + (3x + 7)}{2} $$
- Equate the Midsegment Length to the Given Value
From the problem statement, it looks like the midsegment $XY$ should also equal 8x. We equate it to simplify our equation:
$$ \frac{(3x - 1) + (3x + 7)}{2} = 8x $$
- Simplify the Equation
Combine the terms in the numerator:
$$ \frac{(3x + 3x - 1 + 7)}{2} = 8x $$
This simplifies to:
$$ \frac{(6x + 6)}{2} = 8x $$
- Clear the Fraction
To eliminate the fraction, multiply through by 2:
$$ 6x + 6 = 16x $$
- Solve for X
Rearranging the equation gives:
$$ 6 = 16x - 6x $$
So:
$$ 6 = 10x $$
Now divide both sides by 10:
$$ x = \frac{6}{10} $$
Simplifying this:
$$ x = \frac{3}{5} $$
The value of $X$ is $\frac{3}{5}$.
More Information
The midsegment of a trapezoid provides a unique relationship between the bases, reflecting how their lengths relate to each other through the average. This is essential in many geometry problems.
Tips
- Forgetting to average the bases: Students might simply add the base lengths instead of averaging them.
- Misinterpreting the midsegment length: Ensure that the midsegment is equated correctly, as it relates to both the bases in the equation.
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