An explosive with a density of 1.2 g/cm³ has a heat of explosion equal to 900 cal/g. If the heat of explosion of ANFO with density of 0.8 g/cm³ is 950 cal/g, the bulk strength of t... An explosive with a density of 1.2 g/cm³ has a heat of explosion equal to 900 cal/g. If the heat of explosion of ANFO with density of 0.8 g/cm³ is 950 cal/g, the bulk strength of the explosive relative to ANFO is ______. (round off up to 2 decimals) Read more

Steps to Solve

1. Identify values for the given materials

From the problem statement, extract the necessary values:

• For the explosive:

  • Density ($\rho_1$) = 1.2 g/cm³
  • Heat of explosion ($H_1$) = 900 cal/g

• For ANFO:

  • Density ($\rho_2$) = 0.8 g/cm³
  • Heat of explosion ($H_2$) = 950 cal/g

2. Calculate the bulk strength of the explosive

The bulk strength relative to ANFO can be calculated using the formula:

$$ \text{Bulk Strength} = \frac{H_1 \cdot \rho_1}{H_2 \cdot \rho_2} $$

Substituting the values we have:

$$ \text{Bulk Strength} = \frac{900 , \text{cal/g} \cdot 1.2 , \text{g/cm}³}{950 , \text{cal/g} \cdot 0.8 , \text{g/cm}³} $$

3. Perform the calculations

Calculating the numerator:

$$ 900 \cdot 1.2 = 1080 $$

Calculating the denominator:

$$ 950 \cdot 0.8 = 760 $$

Now, divide the results:

$$ \text{Bulk Strength} = \frac{1080}{760} \approx 1.4211 $$

4. Round the result to 2 decimal places

Rounding 1.4211 to two decimal places gives:

$$ \text{Bulk Strength} = 1.42 $$