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Questions and Answers
In which programming language does the programmer have explicit control over memory management, including creating and destroying objects?
In which programming language does the programmer have explicit control over memory management, including creating and destroying objects?
- JavaScript
- Java
- C++ (correct)
- Python
In Java, primitive variables are stored in the heap.
In Java, primitive variables are stored in the heap.
False (B)
What is a stack frame in Java?
What is a stack frame in Java?
A memory area allocated when a method is called.
In Java, objects are primarily stored in the _______, while references to these objects are stored in the stack.
In Java, objects are primarily stored in the _______, while references to these objects are stored in the stack.
What is the output of the following Java code snippet?
int age = 5; int other = 15; System.out.println(other);
What is the output of the following Java code snippet?
int age = 5; int other = 15; System.out.println(other);
When a method is called in Java, a new copy of all variables is created in the stack frame.
When a method is called in Java, a new copy of all variables is created in the stack frame.
In Java, if a primitive variable is passed to a function and modified inside that function, does the original variable's value change after the function call?
In Java, if a primitive variable is passed to a function and modified inside that function, does the original variable's value change after the function call?
When a primitive variable is passed into a method in Java, the method receives a _______ of the variable's value.
When a primitive variable is passed into a method in Java, the method receives a _______ of the variable's value.
Consider the following Java code:
`public static void change(int age) {
age = 9;
}
public static void main(String[] args) {
int age = 5;
change(age);
System.out.println(age);
}`
What is the output?
Consider the following Java code: `public static void change(int age) { age = 9; }
public static void main(String[] args) { int age = 5; change(age); System.out.println(age); }` What is the output?
When an object is created in Java, it is stored directly in the stack.
When an object is created in Java, it is stored directly in the stack.
What is stored in the stack when an object is created in Java?
What is stored in the stack when an object is created in Java?
In Java, the _______ contains the actual data of objects, while the stack holds the _______ to these objects.
In Java, the _______ contains the actual data of objects, while the stack holds the _______ to these objects.
Given a Java class Person
with an age
field, what is the output of the following code?
Person p = new Person(); p.age = 15; System.out.println(p.age);
Given a Java class Person
with an age
field, what is the output of the following code?
Person p = new Person(); p.age = 15; System.out.println(p.age);
When an object is passed to a method in Java, any changes made to the object's state inside the method will be reflected outside the method.
When an object is passed to a method in Java, any changes made to the object's state inside the method will be reflected outside the method.
Why do changes inside a method affect the original object when an object is passed as a parameter in Java?
Why do changes inside a method affect the original object when an object is passed as a parameter in Java?
When an object is passed to a method in Java, the method receives a _______ of the object's reference.
When an object is passed to a method in Java, the method receives a _______ of the object's reference.
Consider the following Java code:
`class Person {
int age = 0;
}
public static void change(Person i) {
i.age = 9;
}
public static void main(String[] args) {
Person p = new Person();
p.age = 15;
change(p);
System.out.println(p.age);
}`
What will be the output?
Consider the following Java code: `class Person { int age = 0; }
public static void change(Person i) { i.age = 9; }
public static void main(String[] args) { Person p = new Person(); p.age = 15; change(p); System.out.println(p.age); }` What will be the output?
Strings in Java are mutable.
Strings in Java are mutable.
What does it mean for a String to be immutable in Java?
What does it mean for a String to be immutable in Java?
In Java, once a String object is created, its value cannot be modified, making it an _______ object.
In Java, once a String object is created, its value cannot be modified, making it an _______ object.
Given the following Java code snippet:
String p = "Pravesh"; public static void change(String i) { i = "Steve"; } change(p); System.out.println(p);
What is the output?
Given the following Java code snippet:
String p = "Pravesh"; public static void change(String i) { i = "Steve"; } change(p); System.out.println(p);
What is the output?
In Java, the ==
operator compares the content of String objects.
In Java, the ==
operator compares the content of String objects.
What does the ==
operator compare when used with objects in Java?
What does the ==
operator compare when used with objects in Java?
To compare the content of two String objects in Java, you should use the ______ method, not the ==
operator.
To compare the content of two String objects in Java, you should use the ______ method, not the ==
operator.
What is the output of the following Java code?
String p = "pravesh"; String q = "pravesh".toLowerCase(); System.out.println(p == q);
What is the output of the following Java code?
String p = "pravesh"; String q = "pravesh".toLowerCase(); System.out.println(p == q);
What is the output of the following Java code?
String p = "pravesh"; String q = "pravesh".toLowerCase(); System.out.println(p.equals(q));
What is the output of the following Java code?
String p = "pravesh"; String q = "pravesh".toLowerCase(); System.out.println(p.equals(q));
Match the memory area with its primary purpose in Java:
Match the memory area with its primary purpose in Java:
Which of the following code snippets correctly demonstrates how Java allocates memory for a primitive variable?
Which of the following code snippets correctly demonstrates how Java allocates memory for a primitive variable?
What is the primary reason for understanding how Java handles memory management?
What is the primary reason for understanding how Java handles memory management?
Because strings are immutable, Java reuses string literals to point to the same memory location, resulting in memory optimization.
Because strings are immutable, Java reuses string literals to point to the same memory location, resulting in memory optimization.
When is a stack frame allocated in Java?
When is a stack frame allocated in Java?
In Java, what happens to the original object when it is passed to a method and modified inside that method?
In Java, what happens to the original object when it is passed to a method and modified inside that method?
Why are strings treated specially compared to other objects in Java?
Why are strings treated specially compared to other objects in Java?
If two strings have the same content, the '==' operator in Java will always return true
.
If two strings have the same content, the '==' operator in Java will always return true
.
Java automatically handles memory management, relieving developers from manual memory allocation and deallocation.
Java automatically handles memory management, relieving developers from manual memory allocation and deallocation.
In Java, the garbage collector reclaims memory from objects that:
In Java, the garbage collector reclaims memory from objects that:
Match the concept with appropriate descriptions.
Match the concept with appropriate descriptions.
What is a key benefit of Java handling memory management automatically, as opposed to manual memory management in C++?
What is a key benefit of Java handling memory management automatically, as opposed to manual memory management in C++?
Given that String objects are immutable, what happens when a new value is assigned to an existing String variable?
Given that String objects are immutable, what happens when a new value is assigned to an existing String variable?
Flashcards
C++ Memory Control
C++ Memory Control
In C++, you had control over memory; you explicitly created and destroyed objects and could manipulate pointers.
Java Memory Handling
Java Memory Handling
Java handles memory management automatically.
Stack frame allocation
Stack frame allocation
Allocates a stack frame when a method is called
Java Memory Allocation
Java Memory Allocation
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Local Primitive Variables
Local Primitive Variables
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Method/Function Calls
Method/Function Calls
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Object Storage
Object Storage
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Creating a Person object
Creating a Person object
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Object reference
Object reference
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Passing Objects to Methods
Passing Objects to Methods
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String Immutability
String Immutability
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Strings and Immutability
Strings and Immutability
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String Modification Consequence
String Modification Consequence
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== Operator on Objects
== Operator on Objects
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.equals() method
.equals() method
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Study Notes
Lecture 4: How Java Handles Memory
- In C++, memory control requires explicit creation, destruction of objects, and pointer manipulation.
- Java handles memory management automatically.
- Knowing how memory is handled helps to avoid confusion with unexpected outputs.
Back to Work!
- Java allocates a stack frame when the main method is run.
- Stack frames are also allocated anytime a method is called.
- Java stores primitives directly in the stack.
- Objects are stored in the heap.
- References to objects are stored in the stack.
Local Primitive Variables
- Primitive variables like
int age = 5
are stored directly in the stack frame of the method where they are declared.
Method/Function Calls
- When a method is called, a new stack frame is created for that method with its own local variables.
- Variables are passed by value, so changes made to parameters within a method do not affect the original variables in the calling method. For example, if
age
is 5 inmain
- A call to
change(age)
where age is assigned the value9
. System.out.println(age)
will still result in the printing the value5
.
Objects
- Objects are stored in the heap, and the stack holds a reference to the object's location in memory.
- Changes to an object's properties affect all references to that object.
- For example, setting
p.age = 15
after creating a "Person" object "p" changes the value ofp.age
in the heap.
Objects Containing Objects
- Objects can have other objects as fields.
- These nested objects are also stored in the heap.
Passing Objects to Methods
- When passing an object to a method, you are passing the reference to the object.
- Modifying the referenced object within the method will change the original object.
- For example, if
p.age
is initially 15, a method callchange(p)
where i.age is assigned 9 results inp.age
now reflecting the value is print as9
.
Strings are a Bit Different
- Strings are objects, but they are immutable.
- When a string is "changed", it creates a new string object in memory.
A Consequence of Immutability
- Because strings are immutable, assigning a new value to a string variable creates a new string object instead of modifying the existing one.
The == Operator on Objects
- Using == compares the references (memory addresses) of objects, not their values.
- To compare the values of objects use the
.equals()
method. - For example, comparing the string "pravesh" to "Pravesh".toLowerCase() using == will return
false
, but.equals()
will returntrue
.
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